Video není dostupné.
Omlouváme se.

02.3 Linear and nonlinear analysis in FEA/CAE (Analysis step)

Sdílet
Vložit
  • čas přidán 14. 08. 2024
  • In this video tutorial i tried to explain analysis step in Abaqus for geomtric linear analysis, geometric Nonlinear Analysis & combined geo and material non linear Analysis.
    I also talked a little on convergence issue in abaqus standard, which i decide to explain completely in next video tutorial (I don't want to make this video more lengthy).
    I suggest to have a look on video 02.1, 02.2 before 02.3 in playlist (Abaqus Simulia). Plz have a look I'm sure it will be much helpful for beginners in Abaqus & if you are already Abaqus user then also here you find something new (probably little confusion). On which I'll discuss more in next video tutorial.
    To know more plz check playlists.
    For related questions & discussion you can contact me on 7891401376. or mail me gkn0504@gmail.com
    Telegram Link - t.me/joinchat/...
    Whatsapp Link1 - chat.whatsapp....
    Whatsapp Link2 - chat.whatsapp....
    FaceBook Group - / simtechknowladge

Komentáře • 17

  • @simtech0598
    @simtech0598  Před 5 lety +6

    Here density should be 7800e-12 for steel material according to mm, ton, sec unit system. I made little mistake - instead of 7800e-12 I put 7800e-9.
    But static analysis are independent to density value, even you not need to define it. So analysis results remains same, Please don't bother about it.

    • @aukfaworld4792
      @aukfaworld4792 Před 3 lety

      Dear sir, I also confused about this point defining the mass density, I try to model the load for N, dimension for mm, Elastic modulus by MPa or N/mm2. in this case what mass density value I should use.

    • @simtech0598
      @simtech0598  Před 3 lety

      Dear,
      It is just unit conversion.
      If ur model unit is in meter..it easy to use MKS unit system.
      If ur model is in mm...it easy to use...mm,ton,sec unit.
      In case 2 (mm,ton,sec)
      Density become ton/mm3
      Or
      7800 Kg/m3 = 7800*e-12 ton/mm3
      Similarly stress
      1 N/m2 = 1*e6 N/mm2 or 1Mpa

    • @aukfaworld4792
      @aukfaworld4792 Před 3 lety +1

      @@simtech0598 I really appreciate your response. It very useful information. Thank you.

  • @HayatTeleHealth
    @HayatTeleHealth Před 4 lety +2

    Best video, I don't know how you manage you keep our intrest in the entire video. well done sir.

    • @simtech0598
      @simtech0598  Před 4 lety

      Just sharing knowledge dear.
      Thanks for appreciation.

  • @ib_parametres724
    @ib_parametres724 Před 4 lety +2

    I'm just getting familiar with the software, and I must say your videos are quite elucidating. Thumbs up!

  • @alialijamelll5016
    @alialijamelll5016 Před 2 lety +1

    dear sir, why should we define increments for linear, static analysis and small deformation? I know that for this case we solve the equation f=k*d one time that will give the deformation because stiffness matrix will not change, so why do we define increments and why does software solve the problem by dividing it into many increments (my qustion is only for static, linear and small deformation cases).

    • @simtech0598
      @simtech0598  Před 2 lety

      Dear,
      The general static step is based on increment method... whether stiffness changes or not (linear or nonlinear). This method converge solution in better way when convergence tolerance is higher than the specified tolerence.
      Let say for any increment ∆f = k ∆x convergence not occur due to larger difference un RHS and LHS (convergence tolerance). In next increment it consider lower step time and other subsequent values and try to converge.
      The method of direct solution (without iteration) is used in linear pertribution step in Abaqus.
      I also suggest you to learn FEA in this way... raise good question as you raised here.
      Read Abaqus documentation and practice finite element analysis book (Nitin gokhle sir).

  • @ravipukale6073
    @ravipukale6073 Před rokem +1

    What if I have to do it on solid elements, which element type must be selected?

    • @simtech0598
      @simtech0598  Před rokem

      Dear,
      Element selection depends on analysis type.
      I uploaded one video that may helpuf - czcams.com/video/PhZhNAwUaxI/video.html

  • @le_Bizarre
    @le_Bizarre Před 3 lety

    Thank you for a great content. I have a question, though: in the linear simulation, I wonder how Abaqus is 'stretching' the length of the plate: is it stretching it via an additional tension force, or is it simply considering the plate as being longer and longer as time goes by, so no added stresses, just an additional length is given for it?

    • @simtech0598
      @simtech0598  Před 3 lety +1

      Dear,
      The reason you mentioned is wrong.
      As i told i video...in linear analysis stiffness matrix not change...so for large deformation also it not update stiffness matrix (it should be updated as shape of elements change)...hence nodes are not follow load path..

  • @Bala92635
    @Bala92635 Před 2 lety

    sir i wanted to know what is solution for the convergence error occurred in material non linearity problem

    • @simtech0598
      @simtech0598  Před 2 lety

      Dear,
      Whats problem you are facing... share visuals on my WhatsApp.

  • @aukfaworld4792
    @aukfaworld4792 Před 3 lety

    Dear Sir, Actually, I use Marc for structure analysis. have you ever use Marc Mentat. I wonder that I set the material yield criteria as Von Mises criteria, it means it will stop when I reach the criteria or not?.

    • @simtech0598
      @simtech0598  Před 3 lety

      Dear,
      I'm unaware to word "Marc mentat"