Method of Sections - Analysis of Trusses | Engineering Mechanics (🇵🇭 Tagalog 🇵🇭)
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- čas přidán 7. 08. 2024
- In this lesson we discussed another method of analyzing trusses called the method of sections. In the method of sections, we cut the truss into parts to expose the internal forces of members of interest.
#EngrLeir #EngineeringMechanics #Trusses
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Contents
0:00 Introduction
0:18 Steps in Method of Sections
2:30 Example 1
3:44 Solve for support reactions
7:02 Cutting the through members of the truss
7:25 Free-Body Diagrams of Truss Parts
8:27 Applying Equilibrium Equations in the Right Part FBD
12:37 Example 2
13:24 Cutting line
14:10 Applying a moment equation to solve for the member force
16:04 Tip for choosing a cutting line
16:37 Outro
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I will be uploading a new video each week and welcome suggestions for new topics. Please leave a comment or question below and I will do my best to address it. Thanks for watching!
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Para doon sa mga nagtatanong paano nakuha yung 3√ 3/4 horizontal distance sa member AB...
Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
(√3/2)cos60 = ✓6/4
ung √3(sin30) solution po ba sya for finding unknown side ng right triangle?
@@eliascomawas7963 3 lang po yung nasa square root then over 2
wag nyo eh shortcut sir para lalong maintindihan,, salamat.. step by step lang kc may mga low gets ksing viewers tulad ko na kailangan ng maraming discussion para maintindihan..
thumbs up sir! lahaat ng topic ng engineering from basic hanggang sa katapusan i discuss mo ! galing galiiing !
maganda kayo mag discuss sir,, wag nyo lqng eh shortcut,, hehhe sana gumawa kpa maraming tutorial about mechanics start nyo sa vector..
ang simple at linaw nyo po magturo. mas naiintindihan ko na ngayon 😭 thank you po!
Hindi ito naturo ng statics prof namin, dahil sa pandemic, good thing may ganitong vids sa YT. Thanks, sir!
Thank you po. Grabe, ngayon ko lang naintindihan 'to. God bless po, engr.
thank you, mas naging malinaw ang method of section
sobrang natuto ko dito boss💓
Thank you po sa videos, it really helps. More example pa po sana sir heheh.
Thank you, Engr.
Thank you sir! Big help po, supeerr!
better than my online class discussion
Pano nalang kaya kaming mga modular 😥
@@charddell9525musta engineering?
thank youuu! 💙
ang daling maintindihan sa paraaan mo ng pag eexplain
Thank you💚
mas naiintidhan ko pa to kesa sa teacher ko sa statics, dahil jan subscribe kita love you HAHA
more examples pa po Sir hehe ganda po manood eh
Thank you Sir. Hoping po for more examples and explanations about truss analysis. Nasa part ako ngayon ng buhay ko na nasa dilim ako. Kayo nagpaliwanag ng lahat salamat po Sir!
Anong year nyo naop
Buti pa po kayo sir, mabagal ang pacing. Prof ko po marathon! Hirap intindihin kasi po ang bilis! :D
Thank you so much po!
Milyong Salamat po!!!!
Sir centroid please!! Solid ng tutorial nyo! Salamat dito
Thank you sir
Napakahusay po
this reignited my love for math especially Engineering mechanics. Thought I hate math but since college for no reason, I was shocked how easy this subject can be.
Sanaol
Edi wow
Naol po
lol
Salamat po Sir.
hello po dun sasecond example how come na naging 3square of 3 over 4 po yung distance hihi. enlighten me please
THANKYOU SIR BIG HELP!
Welcome! Thanks for watching! 🙏
Thank you po! New subscriber here!
salamat po
Thank you so much Engr!
Welcome!
@@engrleir sir tanong ko
@@engrleir pwede ba?
NATUTO AKO NG MATINDI A KAHIT SAGLIT LANG
okay po yong discussion ninyo sir wag lang po sana i shortcut. hehhe thank you po.
Salamat master
Sa Methods of joints and sections talaga ako nahirapan sa statics sana nakita ko tong video mo sir last sem hahaha
thanks
Sir if there is a horizontal force at the joint B, going towards the right.
Do we have to include it in the moment equation or only the 40kn?
Good day, may I ask what software you're using for your videos? Maybe at some point of my journey I'd start making videos for engineering also. Thank you
Re: Problem 2, Summation of Moment with Respect to Point A. Need pa po bang iconsider yung vertical component ng Force BD?
Pano po kunin yung length na 3square root of 3 over 4
Lods parequest naman ng tutorial about frame analysis
Thank you po💚
This is better than my instructor hahahaha
sir gawa kayo tutorial first step para sa truss section.. kung pano sya ma identify ng mas madali,,. salamat.
Sir may video po ba kayo pano na solve yung measurements sa last part? Medyo mahina kasi ako sa ratio and proportion
Sir, more example nga po sa last problem
Panu pu kinuha yung 3(sqr of 3)/4 po?
Paano po pag ang pinapahanap ay magkakalayo? Halimbawa po member BD, CE and FG.
Sa joint D po, (vertical y), yung DE po ma didisregard ba yung 50kN?
Hello sir, ask kolang kung pwede ka rin magmoment sa E para nakuha Forces DG
Good evening sir pano nyu kinuha yung 105KN?pag sa calcu na -1664 yung lalabas
Hello sir! Sa section method po ba mag-assume tayo na yung ibang members ay walang forces?
sir kahit di na po ba talaga kunin yung reactions? or depende lang sa problem?
pa'no po nakuha yung special triangle na 3-4-cube root?
sir pwede rin po bang gawing assumption sa gantong side ng section is clockwise positive or mas matrabaho po?
na ol ganyan magturo
thank you po
Thanks for watching!😆
Ask kolang po sa electrical engineering din po ba may solving din po ba sa mga trusses
Tumatanggap po ba kayo tutoring services Engr. Leir? Pwede niyo poba kong turuan kahit isang araw lang?
eyyyy
Pwede pobang malaman yung process kung paano kinuha yung 3√3/4, yung sa last part po moment atm ng 20KN, sana po may maka sagot
Yung force kasi na 20kN, perpendicular sa member AB, so yung horizontal distance from A to B ang kukunin para magkaroon ng moment. Ang first step ay solve for the length of member BC by √ 3(sin30). Equal yan sa √ 3/2 Then draw a perpendicular line from point B to line AC. For example, let the point of intersection be O. Therefore, pag sinolve natin yung length ng OC at sinubtract natin sa AC, makukuha natin yung hinahanap na horizontal distance. So para makuha natin ang OC (from right triangle BOC), use (√ 3/2)cos60, which is equal to √ 3/4. Finally, (√ 3) - (√ 3/4) = 3√ 3/4
@9:48 wala po bang force ang FH?
bat 3 sq. root of 3 over 4 distance ng AB?
paano nas solve po yung 3(sqrt 3)/4 na distance?
Sir ask sana ako paano po nakuha ang value na 3square root of 3 / 4
what if walang tab(y) and tab(x). yung binigay lang is tab?
Paano po kung walang given na angle sa problem no. 2?
paano nyo po nakuha 3√3/4 ? sana masagot
Sir paano mag calculate ng bowstring truss vertical nya para mag curve may video kBa nito?
Yung last ex po, bakit po hindi kinuha yung BC?
Sir bakit d po pweding 4 ang eh cucut na member?
hindi ba pag clockwise is positive at counterclockwise is negative?
Good day sir. Paano po pag colinear yung dalawang joints but hindi kasama yung isang joint sa section na cinut, kasama pa po ba yung length nung section na yun?
Un ung length na icoconsider mo if magmomoment ka doon sa isang joint
sir pag method of section kahit saan lang ba pwede mag cut?? I means pwede sa side ng roller support o pwede rin sa kabila??
Yes. Kahit saan pwede.
wait, so going clockwise is negative and counter clockwise is positive? or the other way around?
Hello po, sa pagkakaalam ko ay pwede po siya kahit alin basta consistent lang po sa pag gamit sa buong solution 😊 ang clockwise po ay pwedeng positive or negative same answer pa rin po.
Shear and moment diagram naman sir.
Pwede po kayo gumawa ng video pano po ma determine kung tension or compression? Please po🥺 Thank youuuu
Kapag ung force po palayo sa joint tension. Pag papunta naman sa isang joint compression po.
Pag nakuha mong value ng isang member is POSITIVE "TENSION yun ( bale Yung direction is papalayo sa point or yung napili mong joints... Pay NEGATIVE naman yung value nya COMPRESSION yun( kabliktaran lang ng tension yung direction ng compression)😁
if negative ung value nya, then yung direction is opposite sa inassume mong initial direction. Bale baliktarin mo lang ung direction. If negative nakuha mo sa compression, then tension dapat sya, and vice versa. Ibig sabihin lang ng negative is mali ung direction na inassume mo, baliktarin mo lang
paano po nakuha yung distance sa example 2?
pa request po how to identify zero force members po
sir, pa namandesign naman po ng truss na 30 m ang span, salamat po
hindi po ba yung distance nung AB sa example 2 ay 3/2 m ?
Yes po. AB is 3/2 m. I used the vertical projection which is ABcos30 so 3/2 x sqrt3 /4
pano nyopo nakuha yung Hy?
sa 11:12 nakuha ko naman sa calcu sa FEG is 208KN
Saan po nanggaling yung (3√3)/4? 13:42
sir spring and suspended rod
hello sir ask ko lang kung saan galing at paano nakuha yung 4,3,5 na adjacent opposite at hypotenuse
543 triangle tawag dyan para sa slope. Proportional yan if 2 sides ay given. If given kaagad na 543, then yun na ang gagamitin.
sir san niyo po nakuha yung horizontal distance ng force AB
Sir i know 1 yr ago na po tong comment nyo. Nalito rin po ako san nakuha ang horizontal distance ng AB. salamat
@@tinmadrid3159 pede po sine law then cosine function of right tri after para maget po ang distance AB
paano po nasolve yung distance ng point A at B
sa poblem 2 nyo po?
(2)
pano nakuha FDG sa calcu?
Pano po malaman ung triangle 3/4? Sana po wag nyo ishort cut huhu
Kuya Engr. May tatanong po sana ako kung paano na come up yung distance ni 20KN na 3squarokt of 3 over 4
Itama nyo nalang ako pag mali,minultiply po ata sa area=1/2(bh),
where,b=b/2(para makuha is centroid ng triangle which is perpendicular sa distance a=(3√3/4)).
b=√3/2
h=3
a(distance)=1/2[(√3/2)(3))
@@kenthjonespaderes9419 hi lodi, ask lng po if yung b=b/2 is standard formula po ba?
@@nikotorralba4936 pagkukuhain po ang centroid,pero kung medyo naguguluhan po kayo search nyo po yung properties of the centroid of triangle malalaman nyo po yan kung bakit yung base naging b=b/2.
sir pano po kuhanin yung 3(sqrt3)/4?
Hi! AB is 1/4 of 3m (vertical distance of A-H) and since kinukuha po is moment you have to multiply (1/4 of 3m) to sqrt 3 (horizontal distance from A to B)
@@allylouise thank you po
Sir pwede po bang kayo nalang prof namin hahaha
11:11 I think force EG should be positive, since the moment is counterclockwise 🔄
⬆️ ⬅️ Will be positive
🔁➡️⬇️ Will be negative
So force EG will be in compression
Am I right?
Napansin ko din po nagassume Ako as positive EG so 105(8)-60(4)+EG(3)=-200 or 200 compression
Sir bat po 3 4 5 yung slope hindi 2 ,1.5, at 2.5 since nahati na po yung force EG?
in terms of triangles po, ung 3 4 5 at 1.5 2 2.5 ay similar triangles naman so parehas lang po sila ng angles
Thank you po engr . Pareho pala ng sagot hehe
saan po nakuha yung 3 square root of 3/4?
A=½(bh) po kung saan yung b=b/2(centroidal distance po sa base at sa distance ng point A to point B) by substituting the value b=√3/2.
a(AtoB)=1/2(√3/2)(3)=3√3/4
Pano po yung tamang pag lagay sa calcu upang makuha yung sagot na 17.32KN. THANKS PO
Shift solve po.
San po nakuha ung 5?
Hello Sir. From prob#2, May I ask kung pano po nakuha yung distance ng A to B na 3√3/4?
Dalawang triangles yan ang adjacent ng isa is equal to hypotenuse of the other triangle. Sin60=x/√3cos30
A=1/2bh (kuhain po muna yung centroidal distance po sa base)
Actually ung 3√3/4 i don't know