Trusses | Method of Sections | Problem 12 | Engineering Mechanics | 11.12

[@zjyub]

GF in in tension, not compression. -24cos30 + 13.85cos60 + GF = 0
-20.785 + 6.925 + GF = 0
-13.85 + GF = 0
GF = 13.85 Tension

[@seikome8147]

Thank you it help me alot God bless you🥰

[@KSGEngineering]

Welcome dear. God bless you too

[@missnlahi]

How did you determine triangle 📐 BXG is a right triangle? When you split angle B down the center to create triangle 📐 BXG, angle B becomes 45deg, making the triangle a non right triangle

[@julietkelvin4344]

Thank you very much

[@KSGEngineering]

You are welcome dear

[@Ncclife880]

Thanks sir best sol

[@KSGEngineering]

God bless you dear

[@chrismarklowitz1001]

Ive been scratching my head why I'm wrong Fgf I got was in tension and in your notes it says Compression. I got the same value as well and I double checked and I'm pretty sure its right idk.
I used the right side of the diaram.

[@chrismarklowitz1001]

I checked your diagram and the forces in the x dont sum to 0.

[@KSGEngineering]

If you need any help. Kindly ask

[@llingdendavid3309]

Hajur GF would be tension hoi

[@ayatislam1357]

If the section cut 2 member of a truss,, is it ok??

[@KSGEngineering]

Yes

[@bhawanshbagherwal8592]

thanks alot for the answer , i wasted whole 4 hrs on it

[@KSGEngineering]

God bless you

[@user-dk6nv7ty8f]

Hi, would I be able to contact to privately

[@KSGEngineering]

Hello dear. My email id is [e-mail]
You can ask your doubts here.

[@mdnaurezalam4422]

Fgc= - 27.7
Fgf=+ 20.8. book me answer ye bta rha please check and response
Fbc = - 24 ye sahi h..
.