Understanding UART

Sdílet
Vložit
  • čas přidán 22. 07. 2024
  • This video explains the technical overview of the UART (universal asynchronous receiver/transmitter) serial protocol, including a description of the frame structure and the significance of each frame bit.
    More information on Rohde & Schwarz oscilloscopes: www.rohde-schwarz.com/us/prod...
    Need help with Rohde & Schwarz products & services?
    Contact Us: www.rohde-schwarz.com/us/m4c/...
  • Věda a technologie

Komentáře • 113

  • @AJRobinson
    @AJRobinson Před 2 lety +80

    After watching 6 videos, this one was clear, concise, wasn't 13 minutes long, didn't have awful hand-writing, and included everything I needed to know. Thanks!

  • @jigyasupant453
    @jigyasupant453 Před rokem +19

    Highly appreciate the efforts put in to explain everything in a concise manner. Thanks!!

  • @norvalchenu6102
    @norvalchenu6102 Před 3 lety +18

    I found this video very useful. Thank you so much!!

  • @abhimanyu2842
    @abhimanyu2842 Před 3 lety +20

    Small Correction S has value hex value as 0x53 and decimal value as 83.

  • @siricortana9550
    @siricortana9550 Před 6 měsíci +3

    Short and comprehensive -- amazing video!

  • @BALO_BERSERK
    @BALO_BERSERK Před rokem +2

    Excellent video. You clarified many doubts and I understood new concepts.

  • @chetananam475
    @chetananam475 Před 3 lety +4

    Extremely clear cut explanation!

  • @shvideo1
    @shvideo1 Před 3 lety +15

    Excellent video so very clearly explained. This is the best I have seen on this topic. Thank you for covering all the bases.

  • @occamraiser
    @occamraiser Před 7 měsíci +1

    Ahh, happy days of measuring one and a half start bits to work out the width of the clock/pulses to manually read the data from a remote UART. Life was such fun writing process control software in the 1980s :)

  • @saumittrasarker7138
    @saumittrasarker7138 Před 3 lety +3

    Thank you sir for a clear concept video. best wishes for you.

  • @selvakumarr6672
    @selvakumarr6672 Před rokem +1

    The parity bit is more clear now. Thanks.

  • @akashbidap
    @akashbidap Před 2 lety +1

    admirably explained sir enjoyed the video
    😍

  • @Someone-fu7wz
    @Someone-fu7wz Před 4 měsíci +1

    When someone understands a thing he knows how to explain it clearly! Thank you :D

  • @pascalkreis1524
    @pascalkreis1524 Před 2 lety +3

    Very well done. Thank you for this great explanation.

  • @Ranmitita
    @Ranmitita Před 3 lety +3

    Great video, thanks for this!

  • @gyricyace9215
    @gyricyace9215 Před rokem +2

    yeah rohde & schwarz rulezzz ;) pretty good explanation, with few precise questions left to be solved by myself, but i will figure that out soon! keep up the good work! thanks a lot

  • @limenspicewithshaheenkhali5222

    Thnku so much for such an easy explanation

  • @dipsylogic1715
    @dipsylogic1715 Před 3 lety +4

    Incredible explanation

  • @Annie_EE
    @Annie_EE Před rokem +1

    This is a great introduction

  • @sung-hyunchoi25
    @sung-hyunchoi25 Před 3 lety +4

    THANKS FOR GREAT EXPLANATION!

  • @MusaYmc
    @MusaYmc Před rokem +2

    Neat and tidy explanation, tnx!

  • @SuperGoodka
    @SuperGoodka Před 3 lety +3

    thanks a lot! its very easy to understand

  • @curtpiazza1688
    @curtpiazza1688 Před 6 měsíci +1

    Clear concise explanation! 😊

  • @Autotrope
    @Autotrope Před 3 lety +2

    Great explanation

  • @vinoth3895
    @vinoth3895 Před 4 lety +6

    Thank you!

  • @suryakrishsaiyan
    @suryakrishsaiyan Před 3 měsíci +2

    I have a question here: How do you know if it is a stop bit or a sequence of 1's as data. For example, if i need to send 0xffff, when will UART know that the data has ended?

    • @elektron2kim666
      @elektron2kim666 Před 10 dny

      It's usually automatic in "drivers" so you load in something and use a command like 'write "oxffff"' from instructions on the internet. The driver is something like 'Uart.h' or whatever. It's probably 300 lines in C or MicroPython and you need to write 5 lines very carefully to make it happen or you use some more advanced software doing most of it.

  • @Windy254
    @Windy254 Před 3 měsíci +1

    Thank you.

  • @milo7605
    @milo7605 Před rokem +1

    very usefull and concise, thank you!!!

  • @motivationalcomred
    @motivationalcomred Před rokem +2

    uart(universal asynchronous reciever transmitter) - parity(error detection) - asynchronous so both sender and reciever should transmit at same speeD(baud rate) - tx,rx are registers used in transmitting and recieving data

  • @abheetl9743
    @abheetl9743 Před rokem +2

    Excellent. To the point.

  • @aumotion
    @aumotion Před 10 měsíci +1

    Nowadays UART often reaches 3 Mbps, i have even used 6 Mbps. Serious SOC have many UARTs peripherals. UART is trivial to handle on the software side. UART is ... GREAT.

    • @pauldenisowski
      @pauldenisowski Před 10 měsíci

      UART will always have a special place in my heart :)

  • @DarkNevrozz
    @DarkNevrozz Před 3 lety +1

    Very well explainded thanks !

  • @VvtheD3M0N
    @VvtheD3M0N Před 2 lety

    so to go from & bit ASCII to LSB, you just have to reverse the order of the bit?

  • @FabioSpelta
    @FabioSpelta Před 3 lety +4

    EPIC explanation thank you!

  • @saumilkapadia88
    @saumilkapadia88 Před 3 lety +1

    Very nice !

  • @jcbritobr
    @jcbritobr Před 2 měsíci +1

    Nice stuff.

  • @Ankit.max.
    @Ankit.max. Před rokem

    we are not mention in code ,that type of method so where we use that type of method

  • @egorgreb3828
    @egorgreb3828 Před 2 lety +1

    Awesome!

  • @ronan5228
    @ronan5228 Před 4 měsíci +1

    Good video, but a minor correction! 0x52 is listed as ASCII "S" but it is actually 0x53, caused me some confusion while watching :)

    • @pauldenisowski
      @pauldenisowski Před 3 měsíci +1

      (laughs) I wish I had a dollar for every person who noticed that :) You're absolutely correct - thanks!

  • @isuckatthisgame
    @isuckatthisgame Před 3 měsíci +2

    0% bull shit
    0% advertisements
    50% swag
    50% spot on content

  • @SmoothCode
    @SmoothCode Před 2 lety +1

    Teaching like a GOD.

  • @abandxz
    @abandxz Před 3 lety

    I'm facing problems with one of device , where the display required 7-n-1 setting but for the input need 8-n-1

    • @pauldenisowski
      @pauldenisowski Před 3 lety +1

      7N1 means seven bits, no parity bit and one stop bit, whereas 8N1 means eight bits, no parity bit and one stop bit, so these settings are most likely incompatible. If one of the endpoints is a configurable terminal program (like Hyperterm, PuTTY, etc.) you should be able to configure these parameters.

  • @ThanhThanh-zu3gu
    @ThanhThanh-zu3gu Před 3 lety +1

    thank you

  • @Thinkeaic
    @Thinkeaic Před měsícem

    Best video ever

  • @danielvelkov116
    @danielvelkov116 Před 3 lety +1

    Can it be used for media(sound,image) transfer from (for e.g) a bluetooth module? What is the cost of implementing this interface in comparison with I^2C, CAN or MLBB?

    • @pauldenisowski
      @pauldenisowski Před 3 lety +1

      My understanding is that a UART is included in most Bluetooth chips for the host-controller interface, with USB being another popular choice. Generally speaking, UART is often cheaper and easier to implement than other protocols but has lower data throughput. That said, the suitability and cost of using one protocol vs. another is a function of many things, so I couldn't really comment on that part of the question without knowing a lot more about the application, other components in the system, etc.

  • @kirlasharat2714
    @kirlasharat2714 Před 9 měsíci +1

    actually i have one doubt , inside the UART we have transmitter and receiver . will both transmitter and receiver will work at same clock frequency

    • @pauldenisowski
      @pauldenisowski Před 3 měsíci

      In order to UART to work, but transmitter and receiver have to be configured to run at the same speed (asynchronous - no shared clock).

  • @sriramkrishnamurthy4473
    @sriramkrishnamurthy4473 Před 2 lety +2

    i love u bro amaze

  • @getinthespace7715
    @getinthespace7715 Před 2 měsíci +1

    Awesome.

    • @pauldenisowski
      @pauldenisowski Před 2 měsíci

      Appreciate the feedback - thanks for watching!

  • @JeremyCook
    @JeremyCook Před 10 měsíci +2

    As others have said, very good - not too long, but seems to hit the important details well!

  • @battelground1526
    @battelground1526 Před 3 lety +2

    i have not understand that parity bit.means if data bits are 4-1s then parity bit sould be low(0).

    • @pauldenisowski
      @pauldenisowski Před 3 lety +1

      Depends on the type of parity - even versus odd. In even parity, the number of ones in the user bits + parity bit must be even, so if you send 1 1 1 1 and are using even parity, the parity bit would be zero. If you were using odd parity, the total number of ones would need to be odd, and 1 1 1 1 would require a one as the parity bit.

  • @erenoz2910
    @erenoz2910 Před 2 lety +1

    okay but how is something like "11111111" transmitted? how does the receiver tell the data apart from the stop bit?

    • @igornedashkivskyi1472
      @igornedashkivskyi1472 Před 3 měsíci

      You are always have "start" bit for this purpose which are "0" (low level one), this is kind of something change or begin at the line.

  • @watermark9282
    @watermark9282 Před 3 měsíci

    i have a question imagine a data with all 1's then how does the receiver identify the stop bit

    • @pauldenisowski
      @pauldenisowski Před 2 měsíci

      UART requires that both sides be configurated with the same bit rate and the number of data bits (this is fixed for all UART frames exchanged and cannot be "signaled"). So the receiver will know how long the frame is and thus can identify the stop bit.

  • @ozonewagle
    @ozonewagle Před 2 měsíci

    I have some confusions.
    1. The LSB is indicated first in waveform but actually receiver is receiving the MSB first.
    2. What kind of line coding techniques are used; it is told that NRZ-I is used but the waveforms just represent Unipolar NRZ.
    3. How cannot the receiver misinterpret as the end of data if consecutive 1's is present in the data which is similar as stop bits?

    • @pauldenisowski
      @pauldenisowski Před 2 měsíci

      1. The order of the bits (LSB or MSB) has to be agreed upon by the transmitter and receiver (and clearly must match at both ends)
      2. NRZ is the most common type of line coding used
      3. The transmitter and receiver must be configured to use the same baud rate, number of data bits, parity type, etc. From these two pieces of information, it is possible to derive the length of the frame (number of bits) and distinguish between a payload "1" and the stop bit.

  • @maxint2680
    @maxint2680 Před 3 lety +3

    The stop bit just looks like a normal "1" bit. How to distinguish a stop bit from a useful "1" bit, or a useful "1" bit from a stop bit? It is not explained in the video - I did not see the use of any prepositioned "length field" or "escape sequence". Can anyone help me with this?

    • @maxint2680
      @maxint2680 Před 3 lety +3

      After doing some searching, I believe the frame length is also pre-configured just like the baud rate. (Please let me know if I am wrong)

    • @pauldenisowski
      @pauldenisowski Před 3 lety +7

      @@maxint2680 Yes, that's correct: Normally in serial communications, you have to explicitly specify (i.e. configure) certain parameters, which need to match on both ends of the connection. These are the speed (baud rate - e.g. 9600), the number of data bits (7 or 8, usually), the number of stop bits (almost always 1), and the parity type (none, even, or odd). So if you know these values, you can derive the length of the frame. If you use PuTTY as a terminal program, these values can be found under "Connection -> Serial"

    • @maxint2680
      @maxint2680 Před 3 lety +2

      @@pauldenisowski Detailed explanation. Thanks!

  • @devided4299
    @devided4299 Před rokem +1

    Aren't there supposed to be 8 data bits, for 8 bits equal to 1 bite?

    • @pauldenisowski
      @pauldenisowski Před rokem

      Typically the user data is 8 bits long. That said, UART doesn't specify how long the payload should be. I still remember when 7-bit ASCII was the norm in serial text transmission.

  • @rizwanrazvi-tl1qg
    @rizwanrazvi-tl1qg Před rokem

    hi...I want take 8bits data and 2 bits parity in design .Is it possible?

    • @pauldenisowski
      @pauldenisowski Před rokem

      Sorry, not with "standard" UART. Is there a reason why you would want a second parity (well, error-checking) bit?

  • @rahmanmd8460
    @rahmanmd8460 Před 2 lety +2

    4:15 its ox53

  • @mythix8070
    @mythix8070 Před 2 lety +1

    I'm a bit late but can I have the presentation I need it for school

  • @spaceman1328
    @spaceman1328 Před 3 lety +1

    More thn basic 🙌

  • @sudhansumtripathy
    @sudhansumtripathy Před 2 měsíci +1

    can we have a FlexRay tutorial for the braking of M Benz

    • @pauldenisowski
      @pauldenisowski Před 2 měsíci +1

      I'm working on some automotive protocol presentations that should be ready later this year :)

  • @tutankamon31
    @tutankamon31 Před rokem +1

    Thanks for great explanation. 0x52 should be 1010010 in binary system.

    • @pauldenisowski
      @pauldenisowski Před rokem

      Lol - I've had about a half dozen people catch that already :) I guess I should be happy that people are watching the video that closely. Thanks!!!

  • @TheMrR9
    @TheMrR9 Před 7 měsíci +2

    based

  • @marcinpozniak1605
    @marcinpozniak1605 Před 26 dny

    4:10 'S' is 0x53 in ascii, otherwise the video was flawless just as the other one ;)

  • @sanjaysethi7033
    @sanjaysethi7033 Před 9 měsíci +1

    There’s a very silly error here:
    ASCII for “S” = 0x53 NOT 0x52!!

    • @pauldenisowski
      @pauldenisowski Před 5 měsíci

      Yep, must have fat-fingered that one (binary is correct). Thanks!

  • @Toto-cm5ux
    @Toto-cm5ux Před rokem +1

    For people who doesn't understand math, S is 0x53 not 0x52

    • @pauldenisowski
      @pauldenisowski Před rokem +1

      Actually, it's for people who can't type :) The binary is correct :)

  • @JohnJohn-gy2st
    @JohnJohn-gy2st Před rokem +1

    Hello

  • @Estuan
    @Estuan Před 3 lety +1

    Pónganle subtitulos al español :c

  • @feelpainacceptpain
    @feelpainacceptpain Před rokem

    Dbit

  • @jacktorrance2336
    @jacktorrance2336 Před 5 měsíci +1

    0x52 != 1010011

  • @y_x2
    @y_x2 Před 2 měsíci

    UART need 3 wires not 2!!! UART are rated in bit per second NOT baud rate!!! Two stop bits is never used for at least 60 years...

    • @pauldenisowski
      @pauldenisowski Před 2 měsíci

      Yes, more than one stop bit is extremely rare. But I'm not sure what you mean by UART needing 3 wires - could you clarify? Thanks!

    • @zxchtl
      @zxchtl Před 2 měsíci

      @@pauldenisowskicould be referencing a ground wire