The Nuts and Bolts of Sudoku
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- čas přidán 14. 05. 2024
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Normal sudoku rules apply. Box borders divide each line into segments with the same sum. Digits in a cage sum to the number in the top left corner of that cage. One digit is double the other in cells separated by a black dot.
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Hi! We're Simon Anthony and Mark Goodliffe, two of the UK's most enthusiastic puzzle solvers. We have both represented the UK at the World Sudoku Championships and the World Puzzle Championships. We're also "cryptic crossword" aficionados. Mark is the twelve-time winner of The Times crossword championship and twice Senior World Champion in Sudoku, and Simon is the former record holder for most consecutive correct solutions to The Listener crossword. We hope we can help your puzzle solving while also introducing you to some of the world's best puzzles.
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▶ Contents ◀
0:00 Theme Music & News around the channel
2:08 Rules of today’s puzzle
3:00 Start Of Solve - Let's Get Cracking! - Zábava
Thank you, Mark for the terrific solove and feature! You made handyman work of it.
I loved the look of the grid.
@@kathyjohnson2043 thank you :)
This is one of the most fascinating *SET* puzzles I have ever solved. _"Absolutely fabulous"_ (Mark @0:30).
I used SET (Set Equivalence Theory) twice. You are *stratospherically* clever and creative. 👏👏👏👏👏👏👏👏
I am glad Mark was _"mad"_ enough to tackle this magnificent beast.
@@Paolo_De_Leva thank you for the high praise; Mark used a simplified form of set, but there are other interesting ways to do it.
@@kennetsdad I described my ways to apply *SET* in a separate comment. I actually used *four* equivalent-set comparisons. Two for the left and two for the right side of the grid.
I would be very curious to know whether there are other ways... this puzzle absolutely deserves to be studied thoroughly.
Unfortunately, the math coprocessor and the mass storage unit installed into Mark's brain are too powerful 🦾🧠, so he just used *brutal arithmetics* for most deductions.
2 hour long videos in one day? Mr. Ambassador, you really are spoiling us.
how does Mark conclude that R2C8 cannot be a "1" @25:44? Didn't he make that determination for R8C2 because of the 8-cage in Box 7? But there's no such restriction on Box 3, right? And if that's the case, then he made a circular deduction that there's a "1" in the 9-cage because he already assumed that there's no "1" in R2C8? Or am I missing a deduction somewhere?
Correct conclusion based on incorrect logic. See also *@AchintanDey's* comment below. It was the second comment posted in this section (hence it appears second last in the list).
@@Paolo_De_Leva I can't find the comment you keep referencing.
@@SamuelSandeen It was posted 5 hours ago and it appears as the second last message in my list, but perhaps CZcams does not sort by time of publication and uses personalized sorting criteria.
"Live and in front of you" - yes, that is the biggest reason I love this channel (besides your charming personality, Mark, of course), that you (and Simon) solve these puzzles unprepared and without props, without having thought about it in advance, without anything except your minds. There is nothing more wonderful, I think, in the world of sudoku solving on the internet than a genuine live solve. Thank you so much for all that you do to bring all of the amazing content to this community.
Am I missing something? Why can't R2C8 at 25:43 be 1?
You are not missing anything. It was an incorrect gereralization by Mark, and unfortunately also a correct conclusion, based on incorrect logic.
I thought so too. It was cyclic logic - in box 7 it was a correct deduction because we know there is a 1 in the 8-cage. In box 3 it's a 9-cage so he "brought over" that "no 1" deduction AND used it to "conclude" that there WAS indeed a 1 in the 9-cage... :(
@25:45 mark rules out a 1 in the central cell of box 3, but is that justified? I assumed in box 7 it was because of the 8 cage, but the 9 cage in box 3 could still have been 234
I agree with you, I had to try to put the 1 in R2C8, and continue from that until it broke, but Mark certainly didn't justify we rule out the 1, confused me for some time.
Yes, Mark had a logical gap there. He thought that the 1 is ruled out from r2c8 just like it couldn't be r8c2, and then used it to argue that the 9-cage in box 3 can't be 234, so must contain a 1.
Correct conclusion based on incorrect logic. See also *@AchintanDey's* comment below.
You can rule out that 9 cage being a 135-triple, because the 7 in R5C6 makes R5C9 a 35-pair. That does put a 2 in the 9 cage.
@@kennethjfair Yup. That's how I did it. Mark unfortunately skipped this step.
The first deduction @5:21 was excellent, but it can be also be done without arithmetics, if you use *SET* (Set Equivalence Theory). Just compare
*columns 1* and *4*
with
*boxes 1* and *4.*
Then remove the common cells and the bolts... You obtain two small sets that must add up to the same value:
*8 + 9 = 17*
Of course, you can also compare *columns 6* and *9* with *boxes 6* and *9.*
You can also compare *column 2* with *column 4,* reaching interesting conclusions about the possible values of *r8c2:*
*r8c2 = 3* or *4*
In turn, this means the *8-cage* in *box 7* cannot contain
*1 + 3 + 4 = 8*
and must contain
*1 + 2 + 5 = 8.*
Similarly, you can compare *column 6* with *column 8...*
Loved the use of "subtrahend" ... great puzzle btw
34:59
A beautiful layout which appropriately turned into quite the mechanical grind towards the end, but the opening displayed some lovely logical steps to get us there.
There might have been one more secret in that kropki dot that would have added some oil.
_"Madness is upon me..."_ (Mark @0:17)
Thank you for being mad enough to tackle this magnificent beast. This is one of the most fascinating SET puzzles I have ever solved.
👏👏👏👏👏👏👏👏👏
_"Absolutely fabulous"_ (Mark @0:30)
I agree.
CTC is by far the best sudoku channel on CZcams. 🏆🥇
Every day they feature _"absolutely fabulous"_ puzzles.
Exceptions are unbelievably rare‼‼‼
I am actually surprised there exist so many magnificent artworks and so many stratospherically clever and wildly imaginative constructors.
At 39:06, somehow Mark said 124 added up to 9. What a knowledge bomb!
Somehow ruled out 234. Hmmm.....
That was a bummer. I still don't know what would have been a logical step from there onwards.
@@Mephistahpheles he put the 1 in by mistaking the 124 does not add up to 9. but in the end when he put the 135 in the box he noted that the 234 pair would break the 3 squares across from the 9 cage. had 2 cells reduced down to 246 and the 234 cage would leave the 6 the only option for 2 cells.
@@deepanshushukla116 I did it using the top left nut, deducing, why the two unknown numbers on each side should always sum to 11, but it seemed a bit brute-force to me.
See also *@AchintanDey's* comment below. It was the second comment posted in this section (hence it appears second last in the list).
@39:02 after ruling a 6 out of the 9 cage... "It's either 135 or 124" to place a 1 in the 9 cage...but it still could've been 234 (and also 124 = 7). Sorry Mark!
Delighted to get through this one, at one point it looked like the sort of puzzle I would horribly stuff up and/or give up through sheer boredom, but happily neither happened and I was able to find a way through this using tools of logic. Very clever and intricate construction.
100 minutes for me. That was a tough one. Crazy amount of logic in it. Really fun!
Stuck after the 89s. See that Mark had a little logic miss, so will keep after it and hopefully find my way. Fun puzzle so far!
Rules: 02:07
Let's Get Cracking: 03:02
What about this video's Top Tier Simarkisms?!
The Secret: 1x (04:57)
And how about this video's Simarkisms?!
Ah: 13x (03:47, 04:57, 09:47, 11:56, 13:37, 21:12, 23:49, 23:49, 34:18, 34:24, 46:41, 50:07, 52:12)
Obviously: 11x (00:33, 06:10, 08:49, 08:55, 10:12, 20:24, 23:56, 28:55, 35:04, 37:25, 38:22)
Hang On: 10x (06:42, 13:57, 15:10, 23:39, 23:39, 23:39, 31:15, 54:34)
Pencil Mark/mark: 7x (29:58, 30:03, 46:12, 47:26, 47:38, 49:38, 56:51)
Sorry: 5x (05:31, 09:37, 19:56, 50:10, 52:39)
Weird: 4x (15:06, 38:35, 55:52, 57:21)
Lovely: 3x (06:39, 07:13, 07:13)
Deadly Pattern: 3x (55:52, 56:02, 57:25)
Surely: 3x (37:04, 37:04, 53:14)
In Fact: 3x (07:31, 10:01, 34:39)
*****ing: 3x (37:02, 54:24, 54:31)
The Answer is: 2x (08:40, 14:43)
Clever: 2x (59:07, 59:25)
Brilliant: 2x (00:52, 14:43)
Incredible: 2x (02:02, 05:09)
Fabulous: 2x (00:31, 58:08)
Nonsense: 1x (51:45)
Stuck: 1x (19:56)
First Digit: 1x (29:43)
Gorgeous: 1x (29:20)
By Sudoku: 1x (36:29)
Shouting: 1x (52:43)
Progress: 1x (45:09)
Wow: 1x (19:37)
Symmetry: 1x (44:55)
Most popular number(>9), digit and colour this video:
Thirty Six (17 mentions)
Two (105 mentions)
Yellow (37 mentions)
Antithesis Battles:
Low (5) - High (0)
Even (9) - Odd (6)
Black (8) - White (1)
Column (33) - Row (16)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
25:40 I missed something. I agree that R8C2 can't be 1, but R2C8?
39:10 Column 4's 9-cage is either 135 or 234. It contains a 3.
I can't usually solve puzzles needing geometry so I'm a bit proud of myself for once to be able to do this one.
Brilliant puzzle.
Mark please explain how at 25:45 you deduced that R2C8 couldn’t have a 1
Incidentally R5C9 already couldn’t contain a 1 because both 1 and 2 were required for the sum to 6 or 7
See *@AchintanDey's* comment below.
An incredible puzzle
Fry brains 😂😂😂
That's was a great solve. Your logic was very good. It is ok to take your time to solve the puzzle! 😊
66:07 for me. Nice puzzle!
31:38 for me. Wonderful puzzle!
00:52:15
We are on a roll !!!
That was tricky. I enjoyed it but I struggled quite a bit. About an hour and a half, maybe a few more 😅
Really nice to say lets place 67 here and see that it doesnt. But nice to know for those of us that didnt see it that u can get to same place using the octagons...
Noting that the "corners" of each octagon are equal sums.and then comparing sums of C2&C4 and C6&C8 ...still get the third 89 pair.
The blackdot then breaks the puzzle
Butbhisblogic is more eloquent.
176:14 for me
😀Ha ha, you worked so hard for 10 minutes to remove a 1 from R5C9 (at about minute 25), when just 15 minutes before you said that the diamonds in box 4 and box 6 have "two 1s, two 2s, one 3 and one 4" (therefore this eliminates all 1s and 2s in R5C1 and R5C9, which you didn't do! albeit you are usually much better than Simon at clearing pencil marks 😛). I could not stop laughing. Anyhow, brilliant solve.
great solving, best regards from Ukraine!
Mark once again stumbling into the right solution with a mistake that luckily turns out to be right!
While ignoring the error of ruling 1 out of r2c8 when it couldn't yet be, the work that can be done later on in columns 4 and 6 with respect to the 22 and 21 totals in columns 2 and 8 will ultimately determine that 3 is in r7c8 or r9c8 and thus in column 9 in box 6, therefore ruling the 9 cage in box 3 to be 126.
Thank you, this was the hint I needed! This is the only comment here that actually helped show the right way to resolve that upper right 9 cage.
59:34 for me and solver #493.
Can’t help but think, Mark, if you’d kept the colours just a bit longer, you’d have known about the 3 in C2 much earlier. Nevertheless, brilliant solve, totally out of my league but great to watch.
After Mark's assumption that 1 is not in R2C8 I think I found a way how to prove it has to be in the 9 cage in box 3.
After a bit of math you can determine that can't be in R5C6
After some more math you know which way 8 and 9 go
After even more math you find that the 9 cage in box 8 has to be 135
Based on that you will find that you need a 3 in in R79C8 which means that 3 can't go in the 9 cage in box 3
I hope I didn't give a big spoiler :)) Maybe there is a better way to do it but this was my way
Any plans for the next dungeons and diagrams stream? I loved watching zachtronics content on here
Mark began brilliantly, but then the solve became shoddy and he got lucky with both 9 cages, unjustifiably forcing 1s into both cages and turning out to be right both times! 39:00 “That 6 does not appear in the 9-cage, so it’s either 135 or 124, the point being that it has a 1 in it” 😅
Right 🤣
First correct conclusion based on incorrect logic was at 25:40, as reported by others. Second one at 39:00, as reported by you.
I guess Mark's powerful neural math co-processor 🦾🧠 was heavily used in this solve, and was temporarily switched off due to over-heating.
blue vs yellow in box 1 and 2. If yellow was 2/7 that's 9. The only combo for blue that works is 4/5, but that breaks box 1.
Also in blue a 4/6 pair would be impossible therefore R1C2 is not 4 or 6 or it would be. Combined that with blue being forced and it gives you green, but not purple or blue.
I'd be interested to know what percentage of puzzles featured on this channel have the number *5* in the center, because I've noticed it happening well over the statistical probability of 1/9.
Mark makes an error at 25:45. He assumes R2C8 cannot be 1. This is not the case. He then uses it to determine that there is a 1 in the 9 cage. This is (in effect) a lucky guess. His solution flows from this. I am stuck at this point! Let me see how it resolves.
Actually it solves easily without this guess ... so no damage done.
See also *@AchintanDey's* comment below.
38:59 that's a mistake. But actually ok. It is not hard to see that 1 has to go in the 9 cage.
small logic mistake at 25:40 the center case of the 3rd box should be 134, not 234, it's a 9 cage that it is next to, not a 8 cage, it's the 2 that is assured inside the 9 cage, not the 1 like the 8 cage
well, it ends with the correct solution regardless, but that's just luck there
Why is 2 assured to be in the 9 cage at this stage? Couldn't the 9 cage still be 135?
Place the 2 89s...and call it quits
I got as far as figuring out the holes are 89, and got stuck after that.
I don't understand why he ruled out the possible or R2C8 being 1 at 25:39 ?
See *@AchintanDey's* comment below.
19:56 for me.
Ok, you lost me at the first 5 minutes mark lol... I'm terrible at maths :/
It can be solved with little arithmetics if you use SET. See my separate comment for details.
I don't understand the rules. in the 2x2 box, why are the top two equal to the bottom two parts, but in the 2x2 diamond one corner is equal to the other 3 parts? And why did you say that the five parts in the octagon equal the other 3 parts? how is a "border" defined? how is a "segment" defined? these rules are unclear to me.
Border are defined as box border. The 4 black lines that separate sudoku box
Now Imagine the blue shape as a looping line.
So in the blue box line, The "line" Is splitted into two parts by the black box line between row 3 and 4, and between row 6 and 7. Separating each blue box into "top" And "bottom" Segment.
In the diamond, the line is cut by the black line between column 3-4, and column 6-7. separating each diamond into "left" And "right" Segment.
The same black box line split the octagon line through the same process
I don't like puzzles that interrupt global counting techniques with non-trivial "guess and disprove" chains to reduce 4 possibilities to 2, before requiring global counting again.
ok?
“Swallow hard and keep going”