How can you predict whether a salt will produce an acidic, basic, or neutral solution when you dissolve it in water? Free chemistry help @ www.chemistnate.com
No no no. Just memorize the small list of strong acids. Everything else is weak. ^^ This isn't 100% true but works for most students in high school / university :)
Anyone wondering why the conjugate acid SO4^-2 is H2SO4, remember that it is reacting with two NH4+ which both give it 1 H+. Consequently it's conjugate acid is H2SO4, which is one of the 6 simple, strong acids. You can find a chart of all six of these thru google (there a good thing to memorize).
this helped so much !! i've been struggling with this concept all semester, and our final exam is tomorrow. it makes so much more sense now, thank you !!
Oh my flippin god! You have a gift for instruction. This has been a mystery to me until you explained it. Thank you Thank you Thank you!!! Subd and liked !!
The first example is incorrect. The conjugate acid of sulfate is HSO4-. While H2SO4 is a strong acid, HSO4- is not. The second proton in sulfuric acid only partially dissociates. For this problem you need to consider the Ka of NH4+ and the Kb of sulfate. You would have to solve this problem like his part c).
Hi! uhhh I would like to know the reactions happen when salts dissolve in acids such as calcium oxalate dissolve in certain acids? Could you explain please? I was searching for it ages online
For the second example, is the solution basic because its salt of a weak acid and a strong base (spectator ion only)? A lot of other people seem to get fuzzy on that part...
Thank you, Mr. chemistNATE. Your explanation was 200% better than how my book tried to explain it. Again, thank you very much, and I've only skim your other videos, but I'd like to encourage you to keep up the good work :)
For example a: Couldn't you just take the Ka of NH4+ (which is in the order of 2*10^-5), compute the Kb of the sulphate ion (which, given the Ka of HSO4, puts the Kb in the order of 10^-12), and argue that, given the relative magnitudes, such a solution would be acidic?
dumb questions incoming. we saw in the first example that clearly NH4+ could donate a proton, allowing for the salt (NH4)2SO4 to be acidic. and given that the SO4^2- ion will not accept protons because it is the conjugate base of a strong acid. but how can a salt like CuSO4 be acidic if it has no protons to donate? and if you want to be technical, only the first proton in H2SO4 is strong. the second proton dissociates less easily, making the second one weak. wouldn't that allow SO4^2- to accept at least one proton (making it slightly basic)?
The Cu+2 ion of CuSO4 is acidic for a special reason. In water in becomes Cu(H2O)6(2+) which is a “complex” (H2O are ligands) and so it does actually have an H to donate
HSO4- donates more H than it accepts (you are correct that it can accept). Overall it will be acidic because a higher % of the H’s are donated vs accepted back
lol unfortunately in the IB Chemistry higher level exams they don't give you the Ka/Kb values so if you get a nasty one like the last one you did in the video we can't really tell which dissociate more and thus whether the solution would be basic or acidic. Oh well... Good concept though. It works
what the actual is being said here. like. i feel like chemistry at this point just says things happen and expect that everyone taking chem is jsut going to educated guess. " yup this is the point where we seperate into different things"
It explained the concepts very well and walked us through several typical questions relating to the topic and provided the answer. What is wrong with it?
No no no. Just memorize the small list of strong acids. Everything else is weak.
^^ This isn't 100% true but works for most students in high school / university :)
Anyone wondering why the conjugate acid SO4^-2 is H2SO4, remember that it is reacting with two NH4+ which both give it 1 H+. Consequently it's conjugate acid is H2SO4, which is one of the 6 simple, strong acids. You can find a chart of all six of these thru google (there a good thing to memorize).
this helped so much !! i've been struggling with this concept all semester, and our final exam is tomorrow. it makes so much more sense now, thank you !!
How
This video somehow explained the salt thing in a way I understand. Thank You
studying for an exam and this helped a ton! You rock!
Mate thank you so much that was really good love ya !
This was awesome! I got an exam tomorrow and this is going to be on it. Very helpful and informative. Thanks for posting :D
Thank you for your time. This video is great.
Oh my flippin god! You have a gift for instruction. This has been a mystery to me until you explained it. Thank you Thank you Thank you!!! Subd and liked !!
absolutely useful and clear!
The first example is incorrect. The conjugate acid of sulfate is HSO4-. While H2SO4 is a strong acid, HSO4- is not. The second proton in sulfuric acid only partially dissociates. For this problem you need to consider the Ka of NH4+ and the Kb of sulfate. You would have to solve this problem like his part c).
Thanks brother. Made it so much simpler and shorter than my prof did.
Very helpful, thank you!
I used two of your videos so far and i understood both concepts completely after watching! Thank you so much!
P.s. can you be my chemistry teacher?
Hi! uhhh I would like to know the reactions happen when salts dissolve in acids such as calcium oxalate dissolve in certain acids? Could you explain please? I was searching for it ages online
🎉🎉🎉 thank you for helping me study for my MCAT ❤
I am from India and I suddenly found this vdo..which clear my concept easily.thanks a lot
Finally i understood this, thank you so much.
THANK YOU!!!! I have MCAT coming up.....Your videos literally helps 24/7
how do you determine the conjugate pairs that you hv written in orange ? pls help ! :(
i love this chemistNATE guy...
literally only video that helped...thank god
Very well put, thank you!
So..... was B a basic solution???
Yup!
Thanks -- Very very helpful
Thanks, Nate.
thanks, helped very much
super helpful! thanks :)
I like how you explained it more instead of just saying well this is acidic because that is blah blah blah
How do we know an acid is weak or strong??
thanks Nate!!!
Thank you. I finally understand something.
Thank you!
For the second example, is the solution basic because its salt of a weak acid and a strong base (spectator ion only)? A lot of other people seem to get fuzzy on that part...
Nice explanation
what was first one ? neutral?
I wonder how CN- can have its own Kb since it has no OH- to dissociate into.
Thank you, Mr. chemistNATE. Your explanation was 200% better than how my book tried to explain it. Again, thank you very much, and I've only skim your other videos, but I'd like to encourage you to keep up the good work :)
so i have to memorize weak bases/acids tooo?
So what did b. make?
Why NaHSO 4 is a salt however it is slightly acidic?
Doesn't a strong acid/base have a conjugate base/acid that is neutral?
Thanks dude.
Are you Canadian? And was the second one basic or acidic?
great job thanks
Is he Irish!? Great video keep up the awesome videos!
Very well explained, and loved how you weren't speaking too fast. Thank you!
you have the same accent as my physics lecturer
So was the solution for B) basic or neutral?
Nooo
thanks!
and btw nice watch!
thank you
Thanks.
Thank you that was incredible! Really helped me so much!!!!!! THANK YOU!!
For example a:
Couldn't you just take the Ka of NH4+ (which is in the order of 2*10^-5), compute the Kb of the sulphate ion (which, given the Ka of HSO4, puts the Kb in the order of 10^-12), and argue that, given the relative magnitudes, such a solution would be acidic?
you're my hero :)
you're good, no you're great actually
THANK YOU SO MUCH FOR THIS. NOW I SHALL PASS.
Im in med school and this video is still super helpful.. Thank you Nate.
Sulfuric acid is a strong acid; HSO3 is the weak conjugate acid for the base SO3.
you are a life saver! I understand this now
Thanks for a great video! I have had a hard time finding anything on the intrenet about this topic but luckily I found your video! :)
@ 3:28 you said H2SO4 is a weak acid, the example you did right before it had H2SO4 as a STRONG acid with SO4 as a weak base... Im confused.
H2SO3 was the second example :)) not H2SO4
Thanks
thanks bestie
dumb questions incoming.
we saw in the first example that clearly NH4+ could donate a proton, allowing for the salt (NH4)2SO4 to be acidic. and given that the SO4^2- ion will not accept protons because it is the conjugate base of a strong acid.
but how can a salt like CuSO4 be acidic if it has no protons to donate? and if you want to be technical, only the first proton in H2SO4 is strong. the second proton dissociates less easily, making the second one weak. wouldn't that allow SO4^2- to accept at least one proton (making it slightly basic)?
The Cu+2 ion of CuSO4 is acidic for a special reason. In water in becomes Cu(H2O)6(2+) which is a “complex” (H2O are ligands) and so it does actually have an H to donate
HSO4- donates more H than it accepts (you are correct that it can accept). Overall it will be acidic because a higher % of the H’s are donated vs accepted back
dammit missed this question on the test. The question was worth 20% of the test!!!!!
Welp. Further confused me.
Spanishiwa liked it, so i thought it's bout Starcraft. x)
But nice guide. ;)
LMFAOOO
It was all professional then you were like, "That's a legit equilibrium that happens"
I laughed so hard. Keep it up this helped me a lot!
legit is a word, but how people use it now makes it like "unprof"
this dude literally saves my GPA
awesome !!!!
lol unfortunately in the IB Chemistry higher level exams they don't give you the Ka/Kb values so if you get a nasty one like the last one you did in the video we can't really tell which dissociate more and thus whether the solution would be basic or acidic. Oh well... Good concept though. It works
Thank you so much!
King fr
👍🏽U really goo at explaining chemistry topic/ but this one I still don get it/ is there's a easy way
To explain it.
Its difficult to understand
protone sucking up ability :D
what the actual is being said here. like. i feel like chemistry at this point just says things happen and expect that everyone taking chem is jsut going to educated guess. " yup this is the point where we seperate into different things"
Let’s figure out where you’re lost.
* do you know what HF does in water ?
Thanks *w*
I don't understand
Thought i got it....till i came here.
And THIS didnt help at all.
There was a lot of "sucking".... haha
could I just borrow your brain for my midterm?
Ka for HSO4- is 1.2 x 10^-2. It does not dissociate completely.
"proton sucking up ability" love that man. I need layman terms not some stuffy professor's explanation!
Ummmm.......
New drinking game: take a shot after every time he says "this"
Did not get this at all!!!
Nvm great vid :)
Aur chotta page nhi mila tha
chemistNate: saving my ass since my freshman year of HS to my first year in college :P.
thank you for the information but I have to let you know your tone of voice sounds unbearably condescending in this
Oh :/ I thought he was just being excited
if u increase speed up to *2 then he sounds nice and enthusiastic
Not helpful. I got even more confused after watching this.
terrible video, doesn't even answer the questions
wrong
It explained the concepts very well and walked us through several typical questions relating to the topic and provided the answer. What is wrong with it?
lol wat r u on about
Bkwas video hai.....koi kabhi mat dekna .
terrible...
Thanks -- Very very helpful
How can H2SO4^-2 be a strong acid in the first formula and then be a weak acid in the second?
+Benjamin Thomas That's because in the second formula it was SO3^2- and not SO4^2-
What? Cool thanks