Acid-base titrations | Chemical reactions | AP Chemistry | Khan Academy
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- čas přidán 5. 07. 2024
- In a titration, a solution of known concentration (the titrant) is added to a solution of the substance being studied (the analyte). In an acid-base titration, the titrant is a strong base or a strong acid, and the analyte is an acid or a base, respectively. The point in a titration when the titrant and analyte are present in stoichiometric amounts is called the equivalence point. This point coincides closely to the endpoint of the titration, which can be identified using an indicator. View more lessons or practice this subject at www.khanacademy.org/science/a...
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greetings for all those students that are teaching themselves, trying to understand and fighting, because they have useless professors or doctors!
your truly strong and can do it :))
I study in one of the best schools of my country but I develop my understandings only through online vids...
Swagat Malla why is this so relatable?
This is so accurate. I graduate with a B.S. in Biology from a great school 3 years ago and only now do I fully understand these videos. Maybe we really just aren't ready for these topics at the ripe age of 18-19.
Same here ,I read in one of the best coaching class of my state but I learn all things and concepts through online videos ...lol😂😂😂
@@mrlilnomad well what about us having to study these topics at 15? 😂
Twin Turboed just try to nail the big picture of every process. It’ll certainly help you along the way. I was watching some of these videos just days before my MCAT, and now I already have an interview with a medical school!
I love how I already graduated w/ a B.S. in biology and I understand these issues so much more AFTER I am done with school. Now that I'm studying for the MCAT and actually watching videos all of these topics make so much more sense. Hate that I didn't apply myself in school. Fantastic vid.
hearing someone other than your chem teacher say molarity hits different.
3 weeks until the end of chemistry! I am so freaking done with school this year. I am loosing my sanity!
omg you do titration in schools?
we do everything as a sophomore, its similar to AP chem but a little less in depth
same accelerated chem is killing me
i have one more week of school and i have my final test for chem tmrw :)
Yall are lucky I'm in triple acceleration I'm in 7th learning this shit
It woulda been nice to have known this before taking my ap chem test yesterday
With the help of khan academy I will survive exams.
Needless to say that my teachers are so unqualified😑
ngn mA so true
lol i feel u
hahaha i feel u bro my sucks ass in both chem and bio
The teachers are qualified but they don't do their job.
Yes u r right.I sometimes think that why all school teachers are like this ....unqualified lol😂😂😂
Not all heroes wear capes 😅
How do you know he doesn't wear one?
@@UserName-us1nm 🤣
He just wears pants
ASDFHFJGKGKGL I just need to accept im getting a C in Chem. But it’s fine. I’m fine. EVERYTHING IS FINE GODDAMMIT
Never, before have I related to a god damn comment more than this... holy crap
@@natalyadonohue726 same except I'm failing
getting B here
Please keep this up it is so helpful
I mean... Why did my chem teacher give the class a titration concentration table the day before a test for review without explaining it? Why does this look a little complicated, what am I doing here, why wont they let me sleep, why am I pulling an all nighter for this test, why did he give all the review the day before the test? Im going to be okay :D
I am in the exact situation you are in right now. Never been taught titration so I'm here on a Sunday night before the Exam.
no
So basically we just identify the missing variable (e.g. the concentration or volume) then set it up as M= mol/L. Then we balance the chemical equation to see what the ratio between the acid and base is. Taking the ratio into consideration, we determine the missing concentration or volume by setting up another M=mol/L except with the originally unknown variable.
Hopefully that was right?
Sounds about right to me, it helped clear a bit of confusion from the MV=MV relationship. The number of moles of the acid is equal to the number of moles of the base shown by the equation
Thank you for uploading this video. Really helped me out..
best ever video on titration!!!!!
THANK YOUR SIR ! FOR CLEARING ALL MY DOUBTS ABOUT TITRATION. I'M GREATFUL!
very well explained, thankyou
u helped me so much thank you for everything ! :D
Fantastic Video!!! I was stuggling with this concept but now I understand.
I prefer the short cut method of MV=MV .The problem is that it only applies wen the mole ratio for both is 1:1.anyway thanks❤
There is a wider formul that applies at all instances. It us given as CaVa / CbVb = Na / Nb
That's way more comprehensive
Just put the coefficients in front of the M
i missed my classes when we studied titration and this was so helpful, thank you!!!!!
Why can't my teacher actually explain stuff to us like this is stead of giving us packets with reading
this was so helpful! i'm so grateful thank you very much !!
thank you for this video, I've just begun IB HL chemistry and it was already getting stressful, this video helped a lot!! thanks!!!
shouldnt you have finished titration long before you came into IB?
lmao at least not where I’m from, we’re finishing up topic 1
Hi, I'm trying to perform a titration to find the average amount of lactic acid concentration in yogurt and how much is in a certain amount of bacteria(such as streptococcus thermopilus). I am confused on what my standard solution would be, pls help?
the quick method that you taught us at the end was really helpful thankyou so much!!
Thank you :)
Such a wonderful video with awesome explanation, too good for beginners
all of your videos are very helping me to understand chemistry moreeee...tqqqqqqqqq
What would be really helpful would be a video only showing examples which are visual with all three acid-base titrations.
have a lab due in a couple hours hope i can learn this fast
woow thats great
Thanks, very clear and understable
Now I understand, thanks for explaining :)
this is realy so helpful...thanku sir....
it was good 2nd method is more easy😊
For those who don't know, Molarity is just the concentration but in the unit (Moles/Litre)
tyy
the different colors just make it so much interesting
thanks...
what a great explanation! thank you.
thanks a lot thats was amazing !
will the short cut way still work if the mole ratio were different
What is the program you used?
Wow. Super clear and helpful. Thank you.
Dalila Robledo De Basabe
thank you for this
thank you very much this helped me alot
Thank you.
i hate chemistry with a passion
You are not alone
With a Very VERY strong Passion !!!
Yeti Sage I LOVE chemistry!
Thanks to breaking bad lol
James Lee haha yeah
Yeti Sage I thought it would be cool, but know I understand the pain! 😠🔫
Gr8 video thanks helped a lot
Thank you so much, this really helped me! :) :) :)
The whole video can be summarized as M1V1=M2V2
or C2V2=C1V1
@S S Patil thanks hon
@@wantedtofeelwanted3717 bro what can you explain this
@@rioZtherealone expalin what
@@rioZtherealone He used the dilutions formula. But that only works when the mole ratio is 1 to 1
i think a more suitable indicator would be methyl orange
great video btw
Is the simplified method -MV base =MVacid only applicable when the reactant mole ratio is 1:1 ?
Nopes, for any mole ratio
That's what I tought at first as well, but the ratio is already embedded into the volume of both acid and base
Yeah that's right.
Actually the full formula when there is different stiotoimetric ratio is *(M1V1)/Stiotoimetric ratio of acid in reaction = (M2V2)/Stiotoimetric ratio of base in reaction*
No need to say thanks😎
Manteg Singh thanks!!! This was confusing me 😣
how can you use phenolphthalien when hcl is a strong acid and naoh is a strong base. isnt that indicator only used for weak acid and strong bace?
Thanks I got it Explaination is awesome 🙂🙂🙂
Thank you
Love this.
awesome video! 😁 gave it a thumbs up 👍
is the same process still used if the conc. of the base is unknown? :)
itsrainingchan yeah
Thank you.
For amazing explanation
can you not do this in two steps using ratios?
20ml : 48.6ml
0.1 moles : x moles
20/0.1= 200 so 48.6/200= 0.243 M
or will this not work every time?
very nice...👍
Thank you so much!!!!!
I really like the introduction. Thanks Khan Academy.
It's not just me who come to his Videos to watch the introduction for Report
Im so glad I only need one class of chemistry, ive always hated it
You assumed early on that I knew how to "Solve for X" now I can't move forth with the rest of the video #whygodwhy #nowIknowwhyoneshowtheirwork
I can not find words to appreciate.
thanks
thats great
Really thank u
Thank you very much! :)
Thank you..
Please dear : if we have water tank has avolume of water 25000 liter ,and pH=4 ,And i want to add sodium hydroxide to the tank until reach pH=7...determine concentration of sodium hydroxide that you added to keep pH=7??
God bless your soul
How can get the tutorial of double titrations
God bless
Gunbnelch Maui
You can also use: C1*V1=C2*V2? So it would be C1=0,1M, V1=48,6ml, V2=20ml, and C2=x
You will have:
(C1*V1)/V2=C2
(0,1M*48,6ml)/20ml=0,43
Hello I have a question. Beaker A contains a solution with a ppm of 3000. Beaker B contains 1 liter of pure water. If I take 10 mL of solution A and add it to beaker B for a final volume of 1010 mL in beaker B, what is the ppm of the new solution in beaker B? Thank you very much.
Genius.
Isn't it much more straightforward to use C1V1=C2V2 and solve for the missing HCl concentration?
When you went to find the concentration of HCL, why didn't you use the formula concentration = mass/volume? Wouldn't that have worked? Concentration's unit is in grams per cubic decimeter or in mols per dm^3
you're better at this than my teacher
Lol the moment he took out the calculator
I didn't understand what a standard solution, equivalence point, and that stuff was about - even though I got taught that in chemistry but I still don't understand it :(
Standard solution- a solution whose molarity you know. (eg. a 2M NaOH solution)
Equivalence point- when all the. "H+" of the acid combine with all the "OH-" of the base(eg. You would need 1 mol of HCl to neutralize 1 mol of NaOH)
Wait how did it go from 0.0486 to 0.00486? What did he do to change the places again? 4:32
When the question says 'concentration', does the concentration refers to the 'mole' or 'molarity'?
molarity probably
Chemistry's born to mess with minds.......:(...............titration calculations were easy though.....:P
Comments here from 6 years ago 4 years ago 4 months ago 2 weeks ago and 1 day ago so its not a new problem but chemistry been stressing us out for years 🥲💀
Is the molarity of NaOH 0.1000 M always constant?
Ordidor no
It is not because molarity depends on volume and the number of moles (n). The number of moles (n) depends on mass (grams).
You forgot to say that in order to find moles we multiply liter per M
How did he know what the molarity of the base was?
I love the subject chemistry! Just not the way its taught.
hate both
chemistry is a hard subject to teach and understand. Chemistry is not logical like physic and math.
👍👍👍
But the problem is that Phenolphtalein only changes color when the pH reaches 8,2, way beyond 7. So you are always measuring a higher acid concentration than it realy is.
I love you
I thought to find the concentration your need to c=n/V??? you seems to C=nxV??? i dont get this
concentration (Molarity)=Moles/volume moles=Molarity*volume=(moles/volume)*volume (volume cancels out).
why did you divide by 4.86 by 20?
i fucking love you khan academy
Thanks for doing this. My teacher's 💩
Hahahahaha me 2
Often happens that pupils don't pay attention in the class, don't concentrate or don't put enough effort in the class. Most of the time pupils don't dare to interrupt when they don't understand in order to ask more explanation ( I was also often afraid to ask, not knowing if the question is "good" or it is me that was not following or being not so clever at that moment or not being up to date with previous lessons it is difficult to show that you din't prepare or follow previously). I see difference in private class 1 on 1 or just few pupils, then discussion happens more easily and the result is better even the teacher is the same. Same, when someone watches youtube video most of the time is motivated to understand and does it on his own pace which is not often the case in the class.
I recommend to ask in class, teachers like that, because it means that someone is trying and listening.
Just few thoughts on "my teacher is crap" ( which might as well be the case :)
Pls higher the volume
I was so happy with this as a link to show my students until you got to 7:30 and told them it's acceptable to use M1V1 = M2V2. You don't START with the context that it works only for 1:1 reactions and that it is not an acceptable general case for titrations. Most of the time, students stop watching after they figure out the way to do the problem! I suffered through EIGHT YEARS of titrations being set up as dilution problems regardless of the mole ratio, and this just perpetuates that error. You have to present the context FIRST, or, better yet, don't present the method that way at all!
Much easier way is mass times volume of acid = mass times volume of the base. You will get the same answer
Ariella Hakimi Ya I know!!!!!!!!!! I saw him do this and was like why??
or understanding of topic