Uniform Circular Motion and Centripetal Force
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- čas přidán 16. 03. 2017
- Enough of this moving in straight lines business, let's go in circles! Circular motion may not be productive but it's super fun. Ferris wheels are fun. Yes they are, don't be a spoilsport. Roller coasters are fun too. And merry-go-rounds. And learning about centripetal force. Look, I don't understand why you're resisting so much, we are talking about a freaking amusement park. Fine, be that way, I'll go by myself. You stay here and learn this math!
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Should be, the profs are not professional at teaching
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Extremely helpful thanks!
lucky, im in 6th grade and my dad could have explained it fastly but hes making me watch videos that i cannot unerstand (at all)
lol thats like every single comment here
same fact for to bro
this video is so simple but well-made... i'm studying for finals and when i started struggling with centripetal acceleration i had to come back to this specific video to remember it again. thank you professor dave!!
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sir this channel is just love the way you explain is awesome and makes the whole topic simpler and easier
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I have an exam tomorrow, you literally explained everything I need to know in 6 minutes. Amazing!
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Comprehensive, yet easy to understand !! TQ Professor Dave !! 😁👍🏻👍🏻
Hi Professor Dave, thanks for all the great videos. I think that I spotted a slight mistake at 2:55, where you say that centripetal acceleration is inversely proportional to r. However, tangential velocity is v*r, therefore tangential velocity squared/radius will equal omega squared times r, so they are linearly related.
i love his lessons now everything is so simple
now i can understand this completly. thanks sir. it is very helpfull for me🙏
best teacher , wow i follow u first on chemistry, wow u are also excelled in teaching physics. The best video on centripetal force in the universe
Thank you proff Dave !!!
Have you considered doing a short Electricity series ?
i have a few on electricity coming next week!
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Thanks dave.... wish i had a professor like you....
Professor I really respect you. By your knowledge.
Good graphics and Good way of explaining
Professor Dave, thank you very much.
Thanks Mr.Dave, it helped a lot!
haha reply go brrrrrrr
Any uniform circular motion example, like earth which doesn't stop, which is constant in speed any other example
your explanations are the best!
You always explain so well
wow this video has helped me so much thank you very much dave!!!
very, very good explanation.
You have answered many of my questions in this little video..What is more beautiful than this😁..
Sir plzz cover and explain some topics of alternating current
3:54
Owh, no.... that would hurt.... XD
I almost commented that 😳
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Awsome!
Very useful and quickly!
Good evening Sir,
Very helpful and eassy to understand,
Thanks and regards,
Ankur
00:01 Uniform circular motion requires different equations
00:47 Uniform circular motion involves constant tangential speed and a constant radius.
01:30 Shorter distance in same time means slower speed
02:07 Centripetal force causes constant change in direction.
02:47 Centripetal force is generated by centripetal acceleration.
03:31 Centripetal force keeps objects in circular motion
04:11 Centrifugal force is not a real force, it's due to inertia.
04:49 Uniform Circular Motion and Centripetal Force explained
Professor Dave is really great
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dave youre a legend mate
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Tenx professor u really helped me a lot
Dave, you are a good man
good explanation
Thank you !
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Short and sweet!
sir pls upload a video on dimension and units tricks for engineering students.
Thanks I've an exam tomorrow and you helped me out
First of all, thanks for all the help! I never thought I would be able to understand physics LOL!
This chapter was really hard for me and I don't feel like you get so much into it in this video. Is there anyother video about this out there that you've posted? I had big problems with equations and the formula K=1/2 * Mv^2 + 1/2 * Iw^2
Ty for the video really good 👍
The most precise illustration circular motion. I went through this in my Physics lessons years ago and yet, this lecture simplified it much more than the rest. Keep up the good work, Professor! You're making a huge difference in academic circles. :)
Hehe
Speaking of circles..
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This is soooo helpfullll :)
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why the force will pull the object inwards?
plz make live class,,
in this video the answer for your question is 6.25N professor Dave but you gave the answer as 6.3N..............but theexplanation is very good............at first i was blank on this concept but after seeing your video i became an expert in this topic and i even got full marks in my exam............thank you so much
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Thank you
After hearing for years that centrifugal force isn't a real force, I finally understood why. Prof, you are our savior, science Jesus.
wouldnt it be 25*0.5*/1 because the string is 2 meters long and we need teh radius which is half
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Hey vaishnavi where are you from????
Hey vaishnavi where are you from?????
You are not from India I guess...
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Oof, i just remembered that I'm Catholic and we believe in ressurection 🤸
why are you here mary
with how much of my grades he's saved, he pretty much is
shouldnt the answer of question be 6.25N instead of 6.3N?
is anyone else getting 3.125 N in the check your understanding question? I solved it like 6 different ways and thats the only answer I get. I do, however, get 6.25 if you *dont* divide by 2. Did Dave forget to divide by 2 or am I just doing something wrong?
Right I don't get it I did the same thing and it's 6.25
How to solve comprehension?
How can a decrease in radius increase the centrepetal acceleration when the tangential speed would decrease?plz help i am confused
You are confused about this, because you are losing track of what value you are holding constant during this time. The exact term you hold constant, will affect your answer, of what a change in radius does to the centripetal acceleration.
For instance, if you hold angular speed constant, then tangential speed would be proportional to radius. Accounting for this fact will allow us to conclude that centripetal acceleration will decrease with a decrease in radius. The equation v^2/r becomes omega^2*r instead. Hold omega constant, and centripetal acceleration is proportional to radius. You would see this if the object were something that we place on a rigid body with a constant rotating speed, and we are choosing where to put it on this rotating body. Like placing a coin on a turntable, and where you put the coin.
By contrast, if you hold tangential speed constant, and change the radial position (or change the center position so that the radius also changes), then decreasing radius will increase centripetal acceleration in an inverse proportionality. An example of where you see this, is if you take two turns in a car at the same speed, but different turning radii. The speed is given to be the same, and the radius changes because the center of the circle relative to the car changes position. You have to steer tighter to navigate the curve with less radius of curvature. You will also notice that if you turn too tightly, your wheels will skid and you won't be able to turn. This is why you have to slow down for tight turns.
STATIC friction from the road as the car navigates a road? I'm a bit confused about why it's not kinetic friction. The car is already is motion, I think? Interesting
Due to the fact that the wheels rotate, the point of contact between the tires and the road becomes an instantaneous center of zero velocity for each wheel. This is a point where the wheel that is in both translation and rotation, is locally at rest. The force of static friction prevents the tire from skidding, so that the car only moves according to the direction set up by the various axes of rotation of the wheels.
Static friction enables the force of traction, that allows the drive wheels to propel the car forward, and allows the steering wheels to change the direction of the car on a flat road. It also works with the braking of the car. The kinetic friction occurs between the brake drum and shoe, so that it doesn't have to occur between the tire and road. If your brakes lock up, your car will skid, and steering won't let you control it. This is why we have ABS brakes, so that the wheel-road remain in static friction, and the kinetic friction is kept inside the brakes. In pre-2000 vehicles that didn't have ABS brakes, you would have to manually pump your brake pedal to get the same result.
Waittt so a lower tangential speed means that an object travelled only for a short distance, then why is it that the centripetal acceleration increases as it gets closer to the center? I'm kinda confused
If you fix the tangential speed between examples, closer to the center means a greater centripetal acceleration. It is inversely proportional to the radius, a=v^2/r.
If you fix the period of rotation between examples, which is equivalent to fixing the angular speed, closer to the center means less centripetal acceleration. It is proportional to the radius, a=omega^2*r.
Is Change in momentum = centripetal force ?
What is change in momentum conceptual based?
momentum is centrifugal force?
Thanks sir give ans please not clearly understand sir
Rate of change in momentum = net force
When the rate of change in momentum is entirely perpendicular to the velocity, that rate of change in momentum is the force that causes centripetal acceleration.
Centrifugal force is a fictitious force, that is a consequence of looking at this problem from within a reference frame in circular motion, rather than from the inertial reference frame. What it really is, is a body's tendency to proceed in straight line, reacting to a force that attempts to accelerate it inward, and assuming (incorrectly) that it is due to a force that attempts to pull it outward. That apparent force attempting to pull it outward, is the centrifugal psuedoforce.
Crash Course left the group.
sir, can you make a video on non inertial frames
Vignesh Nithyanandam
non inertial frame of reference do not follow Newton's laws of motion
are u from SSC board
Ajinkya Deshpande i am from cbse mam
@@ajinkyadeshpande6271 It isn't that non-inertial frames of reference "do not follow Newton's laws of motion", they still do. It is just that you have the acceleration of the reference frame to account for, something that is not immediately obvious, which will feel like it is a fictitious force.
Wait for the equation how come you didnt divide the distance by 2 for radius?
how do you mean?
Wouldn't the radius equal 1m, if the string is 2m long?
but you don't hold the middle of the string, you hold the end of the string.
Thanks
encountered this concept many times since high school. im now on my second year in engineering and still needs to review this HAHA. (and i know this wont be my last)
thank you professor dave!
I do not understand why any will click the dislike button on videos like these
amazing u r
What a thrill at 5:00
does the mass of an object affect the period?
The period is a kinematics quantity. It is a mathematical description of the motion. Factors like forces, mass, energy, and momentum are not considered when we consider the definition of period for uniform circular motion.
If you want to know whether mass affects the period of a condition of uniform circular motion, you need to define what happens to the other kinetics quantities. If you make constant the magnitude of the tension in string that holds it in circular motion, mass will affect the period of the circular motion. If the kind of force that holds it in circular motion comes in proportion to the mass, then the period is independent of the mass (for instance, circular orbits around an astronomical body of significantly greater mass).
good video
if the string is 2.0 metres long doesn't that mean the radius should be 2.0/2π as 2πr = circumference?
The length of the string is the radius.
@@ProfessorDaveExplains Ah, silly mistake from me there! Thanks for the reply
Hello Professor can you tell me why the acceleration is always towards center ?
There is a component of acceleration that is parallel to the velocity. There is a component of the acceleration that is perpendicular to the velocity. The component that is parallel to the velocity causes a change in speed. The component perpendicular to velocity causes a change in direction.
If it is not directed toward the center, it will not move in a path around that particular circle of curvature.
Nice explanation, considering it actually helped me with a certain problem. Might I add the piece I noticed that helped me out with it.
The only change in tangential velocity for uniform circular motion is in the direction, while we know the magnitude is constant. As you say, the vertical component of the acceleration controls causes change in direction, while the horizontal component causes change in magnitude. No change in magnitude means there’s zero horizontal acceleration, which means the total centripetal acceleration must just be the vertical acceleration.
falling down from a height always is something that always stop me to sit in this. 😅
I have a very simple but intuitive question.
Why doesnt the object collapse into the point.
Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre.
For example:
The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy.
But objects in the real world dont have fixed energy level so what keeps them in circular path?
Another example is that if we change the mechanics occurring on the body interns of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still moves circular
Perhaps tangential acceleration is stronger than centripetal acceleration, and the object should follow the stronger force more
@@user-hv6ef9ie1g there is no tangential acceleration if there is velocity so the tangential acceleration is zero
My physics teacher showed this to the class
Love u ma man
super