Uniform Circular Motion - IB Physics

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  • čas přidán 29. 08. 2024

Komentáře • 164

  • @clarizeesmeralda3765
    @clarizeesmeralda3765 Před 3 lety +178

    This guy is so underrated , the way he teach is so direct to the point hands down

  • @philomenangoh6365
    @philomenangoh6365 Před rokem +22

    This man speaks the language of my brain cells

  • @Learning_with_Musti
    @Learning_with_Musti Před 8 dny +2

    Best video I have seen on this topic.Well done Sir. You inspire me to be a better teacher

  • @aycb8805
    @aycb8805 Před 3 lety +41

    It is so great that i finally found a lesson video that is JUST PERFECT !

  • @runeknight2842
    @runeknight2842 Před 3 lety +109

    This guy teaches better than my teacher

  • @danieljatombliansky3515
    @danieljatombliansky3515 Před 3 lety +10

    SUPER HELPFULL, really, there aren´t a lot of videos explaining this stuff, thanks a lot

  • @johnnyboy3390
    @johnnyboy3390 Před 2 lety +4

    Absolutely phenomenal job teaching this content, and $2,000 cheaper than my uni physics classes...

  • @larsityosmarsilyet5933
    @larsityosmarsilyet5933 Před 2 lety +3

    dude really, . In just 14 minutes, you really taught better than anyone. I liked and subs to your channel. Keep going like that.

  • @Twlghtsvd
    @Twlghtsvd Před 3 měsíci +1

    I’m in 12th grade and this channel is helping me so much this channel is underrated amazing video

  • @user-fl7iq7lo8j
    @user-fl7iq7lo8j Před 8 měsíci +1

    Absolutely nailed it. Have my exams tomorrow and your videos are the best one I can find on youtube, in terms of quality and going straight to the point ✨

  • @yeetmeat1356
    @yeetmeat1356 Před 3 lety +30

    Are you going to cover the HL topics as well? That would be a big help, and thanks for giving us this type of quality content!

    • @AndyMasley
      @AndyMasley  Před 3 lety +15

      I'd like to! I'm still working through the SL topics. Unfortunately each video takes a while so I'm not sure when I'll be done with the HL material.

  • @11392ash
    @11392ash Před 3 lety +4

    HOLY SMOKES, you broke that down SO WELL!!! Thank you so much

  • @sinan1322
    @sinan1322 Před 2 lety +6

    This video was pure miracle 😁 helped me a lot to understand this topic ! Thank you !!

  • @highschoolphysics9459
    @highschoolphysics9459 Před 3 lety +7

    Very cool animations and timing for your teaching content. My students appreciate your work.

  • @juliette0523
    @juliette0523 Před 2 lety +4

    You made it so much easier for me to understand this stuff, thank you so much!

  • @mandysgainedmomentum9555
    @mandysgainedmomentum9555 Před 2 lety +1

    I am an IB physics teacher and I like this video. He is an experienced IB teacher although he looks young.

    • @AndyMasley
      @AndyMasley  Před 2 lety +1

      Skincare routine is key. Thank you!

  • @Mrvicoloco666
    @Mrvicoloco666 Před 2 lety +3

    Hey ANDY, greetings from Ecuador, you just saved some my first classes. I was struggling a lot about how to introduce the important concepts of UCM. Master!!!

    • @AndyMasley
      @AndyMasley  Před 2 lety

      So glad to hear this was helpful!

  • @vandal3603
    @vandal3603 Před rokem +3

    Hey man, thanks for making this video, physics is alot harder than I anticipated, so vids like yours helps me out a lot.

  • @jenniferbello-ld3rp
    @jenniferbello-ld3rp Před 9 měsíci +1

    I have an exam on this unit and this video was really helpful. So glad I found this video

  • @kelvinthehuman
    @kelvinthehuman Před 2 lety +1

    Waooo....amazing explanation, without a waste. Hats off to you, Mr. Masley. Greetings from the Dominican Republic.

  • @altonmiles4027
    @altonmiles4027 Před 3 lety +4

    Amazing video! Very concise and easy to understand. You saved me hours of studying so thank you

  • @md_rifat_chawdhury
    @md_rifat_chawdhury Před 2 lety +2

    LOVE FROM BANGLADESH. PLEASE MAKE MORE VIDEOS ON PHYSICS . YOUR TECHNIQUE IS REALLY GREAT.

  • @danhnguyenthanh7178
    @danhnguyenthanh7178 Před rokem +1

    this guy answer my biggest doubt. why acceleration point toward the center? what is the role? why not in the same direction as the velocity?
    timestamp: 3:48

  • @natrs2335
    @natrs2335 Před 2 lety +2

    Thank you so much, I understood in 15 minutes what I didn’t understand in class in 2 hours

  • @bautistabaiocchi-lora1339

    Exactly what I was looking for, thank you sir.

  • @jfrkhrfn
    @jfrkhrfn Před 2 měsíci +1

    bro literally i cant thank you enough. keep it up man.

  • @RinaNewhouse
    @RinaNewhouse Před rokem +3

    Hi Andy!
    Your level of teaching is superb! I, in all honesty, learn the most from YOU! One thing, though: I believe the answer to a_c (time stamp: 13:48), is supposed to be 5.94E-1 m/s^2, or 0.594 m/s^2, assuming all previous answers to be correct, would it not? I calculated it twice, once on my calculator, and once again on Desmos, and both gave me the answer of 0.593609625668.
    Would you wanna quickly double check?
    Other than that super minor thing, I cannot thank you enough for posting these lessons for all of us to learn from. You are single-handedly getting us through our physics classes.
    Best,
    Rina

    • @AndyMasley
      @AndyMasley  Před rokem +1

      Yes you're correct! I made a mistake in that section

    • @AndyMasley
      @AndyMasley  Před rokem +1

      And thanks so much for the kind words, so happy the videos are helping!

    • @RinaNewhouse
      @RinaNewhouse Před rokem +1

      @@AndyMasley It did help! I did well on my first exam because of you!

  • @yabool2001
    @yabool2001 Před rokem +1

    Man. It's awesome! Not overdone like many other movies.

  • @simsambros
    @simsambros Před 2 lety +1

    This was the perfect video I could find for circular motion

  • @peter3900
    @peter3900 Před 3 lety +2

    Thanks so much really found this helpful even though im not an IB student

  • @nig786
    @nig786 Před rokem +2

    Thank you so much for explaining this topic, you teach very well FR👍

  • @Opticsport
    @Opticsport Před 2 lety +2

    my fav so far, thanks alot Mr. Masley

  • @levychipapa190
    @levychipapa190 Před 2 lety +1

    wow i just cant believe i just understood 70% of circular motion in jxt a few minutes wooow you dope man

  • @MikeStallings2023
    @MikeStallings2023 Před 10 měsíci +1

    Outstanding teacher. What is "IB"? These lessons are valuable to people like me who have no clue what IB is. And this is very hard to google.

    • @AndyMasley
      @AndyMasley  Před 10 měsíci

      Thanks so much! IB stands for "International Baccalaureate" it's a specific physics curriculum that I was teaching at my school

  • @Mouse-qm8wn
    @Mouse-qm8wn Před 7 měsíci +1

    You are a great Teacher please continue making videos 😊❤

  • @MonSonBro
    @MonSonBro Před rokem +11

    You explained this better than my teacher did in 2hours, thanks!

  • @cloudy7817
    @cloudy7817 Před 2 lety +3

    my physics teacher cant teach for shit. thanks to u I (probably) wont fail my test lol.

  • @jamesluc6506
    @jamesluc6506 Před rokem +3

    Your video is so great. I am in the middle of my May Physics Sl exam. I am sad for finding your channel late but also happy for finding it before my final exam. You explain it so well (much better than my teacher). I am pretty sure all your student get a level 7. Just wonder do you have some IA topic recommandation material that could be shared if you still have it (I know you have left teaching). Thank you for the great content.

    • @AndyMasley
      @AndyMasley  Před rokem +1

      My advice for the IA:
      1: A good IA is often a middle school-level experiment with high school-level analysis. You don't need to do something crazy, just a simple experiment with a clear independent and dependent variable and a pattern that's either linear or that you can linearize.
      2: It's often helpful to look through the IB physics equations and find one that has two variables that you can test. As a very simple example, you could look at F = ma and measure how the acceleration changes when the same force is applied to different masses and rearrange the equation to be a = F(1/m) where a is the dependent and m is the independent variable. Working backwards like this from an equation to an experiment can make it easier to find something you can linearize and analyze in the data analysis section.

    • @jamesluc6506
      @jamesluc6506 Před rokem

      @@AndyMasley Thank you so much for your helpful suggestion. I have another quick question, who will mark our IA? I have heard two statement where one says that the teacher marks your IA and one or two IA of your class will be sent to IB to be reviewed and they will decide to increase/decrease the mark of the IA marked by your teacher. And another one states that the teacher only gives you the predicted mark, the IB will review and gives you the final mark. The reason I asked it is because our teacher clearly tells us if we choose a SL topic, is it at most about level 5 and he always suggest us to choose hl topic ot outside the syllabus of IB, so I am concerned if he will be the person to give us the final mark for IA. Thank you very much!

  • @Palestine194
    @Palestine194 Před 2 lety +1

    very interesting lecture sir.....From Pakistan....well explained.

  • @sabaalameer100
    @sabaalameer100 Před 8 měsíci +1

    you made so easy to understand it

  • @amtulsyed5402
    @amtulsyed5402 Před rokem +2

    Very helpful and concise! Thank you!

  • @Archie1981
    @Archie1981 Před 3 měsíci +1

    Very well explained❤

  • @arindomchakrabarty2254
    @arindomchakrabarty2254 Před 2 lety +1

    Concepts, explained in a simple way.

  • @DingusSquatfordJr.
    @DingusSquatfordJr. Před 3 lety +2

    His explanation is nice and clear compared to my professor.

  • @hoanggiabaotran9025
    @hoanggiabaotran9025 Před rokem +1

    Great video, but I have a question regarding the Example Problem 1! The formula booklet stated that a = v^2/r = (4 x π^2 x r)/T^2, and in the video you used v^2/r to get a = 4.641. But technically, in the given variables, you already have r and T, so would it not be easier if you just substitute everything inside (4 x π^2 x r)/T^2? That is what I did, however I ended up having a = 4.626 instead. Could you help me verify what went wrong? Because essentially they should be giving the same answer.

    • @AndyMasley
      @AndyMasley  Před rokem

      You're correct that those formulas are equivalent to each other. Ultimately physics has many formulas that can be rewritten based on convenience. F = ma could also be F = m(Vf -Vi/t) if the variables called for it. Our answers are so close that it's possible that I just rounded incorrectly!

    • @AndyMasley
      @AndyMasley  Před rokem

      I might have used a slightly less exact number for pi, like 3.14 instead of 3.1415926 etc.

    • @hoanggiabaotran9025
      @hoanggiabaotran9025 Před rokem +1

      @@AndyMasley I see. Thanks for replying!

  • @budderrrr4855
    @budderrrr4855 Před 2 lety +3

    you deserve my real teachers salary

  • @nadirenuryasar2729
    @nadirenuryasar2729 Před 4 měsíci +1

    example 1 should be 4626N since you shouldn't round up 11.7809... to 11.8

  • @gloryeruka2501
    @gloryeruka2501 Před rokem +1

    What a great video 😲 thank you so much sir!

  • @cartoonic6039
    @cartoonic6039 Před 8 měsíci

    I have a very simple but question.
    Why doesnt the object collapse into the point.
    Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre.
    For example:
    The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy.
    But objects in the real world dont have fixed energy level so what keeps them in circular path?
    Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular

  • @Mrabosaleh4ever
    @Mrabosaleh4ever Před 3 lety +5

    Thank you

    • @nikolasolakov1232
      @nikolasolakov1232 Před 3 lety +1

      @@AndyMasley no he's actually right, after staring at it for a good 30 minutes and solving i saw that it is actually correct and its not 10^5 but 10^4

    • @JenniferRokks
      @JenniferRokks Před 3 lety

      @@nikolasolakov1232 how?

    • @amznani2023
      @amznani2023 Před 3 lety

      @@nikolasolakov1232 how???

  • @zh-vu7zc
    @zh-vu7zc Před 2 lety +1

    Best Explanation. Appreciate it ❤️💐

  • @maggiiuwu3022
    @maggiiuwu3022 Před rokem +1

    ur a king

  • @Booooscared
    @Booooscared Před rokem +1

    u absolute madlad

  • @alirazanasir5992
    @alirazanasir5992 Před rokem +1

    Thank you

  • @vd4538
    @vd4538 Před 4 měsíci

    Hi Andy, thanks for all your efforts in helping us all. I just had a small doubt for the second example problem... By using the formula I was getting 2 π x 149,600,000 x 10^3/ 365 x 24 x 60 x 60. Which was giving me the answer of 29,806 m/s. However you got the answer of 2.98 x 10^5 which is 298,000 m/s. I just wanted to ask if I went wrong in the calculations anywhere or was the displayed answer a typo? Thanks again.

    • @neotiwari3772
      @neotiwari3772 Před 4 měsíci

      It is 2.98 x 10^4 m/s, he probably made a typo

  • @abel_kidus
    @abel_kidus Před rokem

    Thanks for making me understand the concept.

  • @nsfw9087
    @nsfw9087 Před 2 lety +2

    I'm a little confused in example 2, isn't the earth's orbit around the sun not in uniform motion? (Kepler's law) orbit's shape is an ellipse, not a perfect circle.

    • @AndyMasley
      @AndyMasley  Před 2 lety +3

      Correct! It's actually an almost-perfect circle, the ellipse is usually exaggerated in diagrams, but it's technically not uniform circular motion. I find it has enough of the same properties as uniform circular motion (centripetal force and tangential velocity) that it's a useful example to explain UCM, but it's technically not perfectly uniform.

  • @giancarriedo715
    @giancarriedo715 Před 2 lety +1

    I WISH I FOUND THIS BEFORE MY PHYSICS EXAM AAAAAAH

  • @akankshabhatt3357
    @akankshabhatt3357 Před 2 lety +1

    Thankyou so much for this video, was trying to make sense of this fromone of my mcat books and it just wasn't clicking.

  • @berserkjr6154
    @berserkjr6154 Před 2 lety +2

    👍 ty for good videos

  • @charleskoripamo7488
    @charleskoripamo7488 Před měsícem

    Is it wrong to say the direction of the force on the object changes, therefore the direction of acceleration changes?

  • @zh-vu7zc
    @zh-vu7zc Před 2 lety +2

    Sir , Do you have any videos on banking angles of road?

    • @AndyMasley
      @AndyMasley  Před 2 lety

      Yes! Here: czcams.com/video/94krMSdxA48/video.html

  • @suraphelendalu4070
    @suraphelendalu4070 Před 2 lety +1

    Thank you so much

  • @jabbedcrab
    @jabbedcrab Před rokem

    Correct me if im wrong, but when calculating Vt in the last example problem, the answer is actually 2.98x10^4, i kept getting the wrong final answer with 10^-5!!

  • @lanapark6099
    @lanapark6099 Před 2 lety +1

    thank you so much

  • @OscarSL
    @OscarSL Před 5 měsíci

    You had Vt's order of magnitude as 5, even though it should have been 4. (In example problem 2)

  • @islamdowidar1930
    @islamdowidar1930 Před rokem +1

    Amazing

  • @nadirenuryasar2729
    @nadirenuryasar2729 Před 4 měsíci +1

    example 2 is also wrong vt=2.98x10^4m/s

  • @iqrajabbar5287
    @iqrajabbar5287 Před 11 měsíci +1

    V v v v v v nice....❤

  • @mahlanesophonia3080
    @mahlanesophonia3080 Před 3 lety +1

    THANK YOU SO MUCH

  • @isabeldevalenzuela7892
    @isabeldevalenzuela7892 Před 2 lety +1

    thank you so much!

  • @harunosakura9798
    @harunosakura9798 Před 2 lety +3

    sorry I only have a question that why delta 0 = 2.pi ( 8:58) ?
    and thank you so much, I have learned this lesson for at least 15 times ( included learning from my teacher and internet ) and I still don't understand till I find yours. Its just too easy to understand, and the way you put all of the base-knowledge in just 14:01 video is just so amazing, it really helps me a lot.
    I have subscribed your channel after only 5 minutes watching yours, and hope that you will make more great video, especially 10 grade physics cause I'm at grade 10 now ^^
    hope you will answer my question soon.
    have a nice day !

    • @AndyMasley
      @AndyMasley  Před 2 lety +1

      So happy it's helpful! Delta theta is 2 pi because that's how many radians one complete circle is. If you need help reviewing radians use this: www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:trig/x2ec2f6f830c9fb89:radians/e/degrees_to_radians

    • @harunosakura9798
      @harunosakura9798 Před 2 lety

      @@AndyMasley omg thank you so muchhhhh

  • @amznani2023
    @amznani2023 Před 3 lety +2

    ok but how did you get the 2.98 x 10^5 m/s in example 2?

  • @wrentay2306
    @wrentay2306 Před 2 lety +4

    for example problem 2, the velocity should be 2.98 * 10^4 not 10^5 when you calculate it, and even for the acceleration, 5.9 * 10^-3 is yielded when we use 2.98 * 10^-4

  • @basesixty6739
    @basesixty6739 Před 9 měsíci

    tangential velocity for last question should be 2.98*10^4

  • @yinkak3921
    @yinkak3921 Před 2 lety +1

    Doesn’t the formula for tangential velocity assume that there is no tangential acceleration?

    • @yinkak3921
      @yinkak3921 Před 2 lety +1

      Nvm just realized the title says uniform circular motion

  • @madhyapradesh8841
    @madhyapradesh8841 Před rokem

    Wow thank you so much sir

  • @jamesmatheson9624
    @jamesmatheson9624 Před rokem

    We need to investigate adding multiple rings aounrd the first ring and using smaller and bigger balls. In the rings to change the force to fully understand how the forces are changing

  • @chijinduegbo5640
    @chijinduegbo5640 Před rokem

    velocity is not consant speed is constant because velocity is speed with respect to direction and in circular motion direction is not constant

  • @user-vq5uc4lm2t
    @user-vq5uc4lm2t Před rokem +2

    erika and candace

  • @zahraaalhadi4451
    @zahraaalhadi4451 Před 2 lety +1

    You channel is a real treasure (:
    but I wish you could download the slides you are explaining as pdfs

  • @paulduggar5888
    @paulduggar5888 Před 2 lety +1

    Mr. Masley thank you so much i think i can get an A tmrw bc of u i didnt know UCM until just now

  • @shamelsinha1626
    @shamelsinha1626 Před 3 lety +6

    Ur the reason I ditched my textbook and no longer attend online class!!!

  • @teguhgumilar6868
    @teguhgumilar6868 Před 2 měsíci

    Hi , I am a physics teacher, can you tell us what application/software to make animation on your slides? Thanks

    • @AndyMasley
      @AndyMasley  Před 2 měsíci

      Apple Keynote! Explained here czcams.com/video/hW7vr8Tbsrg/video.html

    • @teguhgumilar6868
      @teguhgumilar6868 Před 2 měsíci

      @@AndyMasley would you like to share your slide to use ? thanks

  • @dullahanan4371
    @dullahanan4371 Před 3 lety +1

    I have a question in uniform c.m net force should constant

    • @AndyMasley
      @AndyMasley  Před 3 lety

      Yeah usually we assume the net force is constant. If the net force changes but the radius and mass stay the same, that implies that the velocity changed, so the circular motion is no longer uniform (at one speed).

  • @edinsonorlandodoradodorado9101

    Man, you are awesome, congratulations

  • @yanyaZhao
    @yanyaZhao Před 3 měsíci

    May I ask why the time is 16 seconds.

  • @isoheilhsni
    @isoheilhsni Před 3 lety +1

    This video was awesome
    Super helpful 👍👍👍👍

  • @joshuankrumah3532
    @joshuankrumah3532 Před 3 lety +2

    that what i was looking for

  • @karlalerma4231
    @karlalerma4231 Před 3 lety +1

    I need help :( so I have a problem " a 2.0 kg object is attached to a 1.5m long string and swung in a horizontal circle at a constant speed using a centripetal force of 192N. What is the speed of the object?" I'm very confused I looked up vids but can't find one for my scenario:(

  • @blackhand441
    @blackhand441 Před 6 měsíci

    Why is tangential velocity 2πr/T ?
    I thought it would be zero since there is no displacement 😢

    • @AndyMasley
      @AndyMasley  Před 6 měsíci

      It's a poorly named term that the IB uses, tangential speed would make more sense! You're exactly right and the IB is just a little lazy with this variable

    • @blackhand441
      @blackhand441 Před 6 měsíci

      @@AndyMasley Thank you for your reply

  • @Mutabaruka-8
    @Mutabaruka-8 Před 2 lety +1

    This is really helpful.

  • @sarahkim9546
    @sarahkim9546 Před 3 lety +1

    You are really good.

  • @leylay1447
    @leylay1447 Před 3 lety +1

    Thank you this was very helpful!

  • @vinayguduri2163
    @vinayguduri2163 Před 3 lety +1

    thank you very much sir it helped me a lot😁😁😄

  • @saidaliamini2754
    @saidaliamini2754 Před 3 lety +1

    Perfect...!👌

  • @lawalolamide7770
    @lawalolamide7770 Před 2 lety

    Pls can u write that radius for me in full digit. 149.6million km. I don't really know how u got 1.496×10^11. I know that a million has 6 zeros

  • @TrucNguyen-ef9lr
    @TrucNguyen-ef9lr Před 2 lety +1

    Thank you so much!!!!

  • @shakasty2943
    @shakasty2943 Před 3 lety +1

    Thank you🤓🙏🏼

  • @desisagreat1961
    @desisagreat1961 Před 3 lety

    Sir thanks so much. Please keep it up and do the exercise and examples