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How to find logarithm without log tables|Tricks and tips series for JEE|CBSE| NEET|CET
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- čas přidán 17. 06. 2018
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How to find anti-logarithm without log tables?
• 🔥 Anti-log (0.05) ? Ho...
Just memorize log2=0.3010 log3=0.4771 log5=0.699 and log7=0.8451 only.
log(6.1) = log (6+0.1) = log6 + 0.4*0.1/6 = log2 + log3 + 0.0067 = 0.3010+0.4771+0.0067 = 0.7848
what if log(137)=log(140-3)=log2+log7+log10-0.4*3/140 = 0.3010+0.8451+1-0.0086= 2.1375 (approx)
remember: delta x(increment/decrement) should be much more smaller than 'x'
• 💥 Find Log 2300 withou...
how to find perfect log. must watch.
• 💎 How to find Logarith...
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Example 2:
log (0.6) = log (6/10) = log6 - log 10 = log (2*3) - 1 = log2 +log3 -1
=0.3010 +0.4771 -1 = -0.2219
Example 3:
log(737) as log (736) = log (32*23) =log (2^5) +log 23
=5log2 +log (24-1) = 5*0.3010+ log24 - 0.4* 1/24
= 1.505 + log(2*2*2*3)-0.016 6=1.505 +3log2 + log 3 + 0.4771 -0.016; now 1.489 +3*0.3010 + 0.4771 -0.016=2.88 approx
Example 4:
log23.32 = log(2.332*10)= log (2+0.332 ) + 1 =
log 2 + 0.4 *0.332/2 + 1 = 0.3010 + 0.066 +1 =1.367approx
• 💥 Find Log 2300 withou...
note: take approximate nearest number and apply logarithm
example(i) log (49.78999 ) as log(50); (b) log(2.3789) as log(24/10)
(c) log (0.004568) as log(45/10000) (apply log(3) +log3 +log5 -
log 10000 (d) log (23779) as log (24000) (apply log 24 + log 1000
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Just memorize log2=0.3010 log3=0.4771 log5=0.699 log7=0.8451
Example 1:
log(6.1) = log (6+0.1) = log6 + 0.4*0.1/6 = log2 + log3 + 0.0067 = 0.3010+0.4771+0.0067 = 0.7848
what if log(137)=log(140-3)=log2+log7+log10-0.4*3/140 = 0.3010+0.8451+1-0.0086= 2.1375 (approx)
Example 2:
log (0.6) = log (6/10) = log6 - log 10 = log (2*3) - 1 = log2 +log3 -1
=0.3010 +0.4771 -1 = -0.2219
Example 3:
log(737) as log (736) = log (32*23) =log (2^5) +log 23
=5log2 +log (24-1) = 5*0.3010+ log24 - 0.4* 1/24
= 1.505 + log(2*2*2*3)-0.016 6=1.505 +3log2 + log 3 + 0.4771 -0.016; now 1.489 +3*0.3010 + 0.4771 -0.016=2.88 approx
Example 4:
log23.32 = log(2.332*10)= log (2+0.332 ) + 1 =
log 2 + 0.4 *0.332/2) + 1 = 0.3010 + 0.066 +1 =1.367approx
czcams.com/video/eKdOPrWobhw/video.html
note: take approximate nearest number and apply logarithm
example(i) log (49.78999 ) as log(50); (b) log(2.3789) as log(24/10)
(c) log (0.004568) as log(45/10000) (apply log(3) +log3 +log5 -
log 10000 (d) log (23779) as log (24000) (apply log 24 + log 1000
Madam we have come over here to remember those values not memorise them . Make us understand not be able to mug up values.
Okkk
Finally!! after watching many videos ,I found this method to be the most convenient one! thank you so much mam .It is very helpful🙏🏻
This procedure is really helpful in solving equilibrium and chemical kinetics so much and really easy... Really comes in handy for a competitive exam
Happy learning
You sound like you have cold 😦..still you are teaching so well ..thank you soo much mam for your help♥️
thank you mam it will be really helpful for us to solve numericals fast during our exams
Log 5 can be derived using log a/b= log a- logb,log 10/2=log10-log2 =0.7
Thank you mam I was really helpful while solving numericals.... U made this look so easy or else I had to waste lot of time in solving sums but now it's so easy to get the accurate answers THANK YOU👍
Ty you so much madam,after seeing this video ,solved all my problem
Mam! You are using mathematical identity log(a)+log(b)=log(ab), am I right mam?
That's Awesome trick ma'am ❤️🔥 You just make it easier 👍 Thank you so much ma'am
Thanku mam this is really helpful for me but I face a problem in finding the value of log of decimal no. Mam please also prepare video for that. That will be great help from Ur side please mam.....
czcams.com/video/MXwIDTH-l-g/video.html
Mam you are awesome. You study very well. Thanks mam. May God bless you
Thank you so much ma'am❤ you really made me understand log in just 8 mins. Thank you
a BIG thanks mam .But what about logarithmic decimal values.I REQUEST you to make another video on them and also include anti logarithmic values in it because we can not cram whole log table. It would surely treat us in solving our numerical problems . Thank you MAM - one of your student who will be anxiously waiting for your next video.
czcams.com/play/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0.html
Thank you so much ❤️😘 Ma'am ❣️ after watching so many videos 😊 finally I found your video easy 😁 and simple ❤️🤗Vvvvvvveeeeeerrrrrryyyyyyy helpful 😊
Thank you Nikita ..Happy learning
Thank you ma'am. It is very helpful to NEET aspirants like me.
Mam. Log 6 = log 3 + log 3. But you have done log 2+ log 3 plz clear doubt
Log 3 × 3 is equal to log 3 + log 3 = log 9
World of chemistry - class 11 and 12 sorry madam. I was confused when you did log 4 ( log 2 * 2 you did). Thank you. It was very helpful. And now i became aware of how to fing log values. Thank you to the core. And sorry for the inconvenience
All the best..Stay connected
Thanks Ma'am It Helped a lot 😊🙏🏻❤️
Omg....life saving tips..... thank you so much....!
Thank you mam for such amazing video👍🏻👍🏻👍🏻👌👌👌
If it is log 6.2 then bcoz in chemical kinetics in example log 6.2 is mentioned plz gives the easiest method to solve these types
Yes me too confused at that
must memorize log2=0.3010 log3=0.4771 log5=0.699 log7=0.8451
log(6.2) = log (6+0.2) = log6 + 0.4*0.2/6 = log2 + log3 + 0.013= 0.3010+0.4771+0.013 = 0.7911 approximate
what if log(137)=log(140-3)=log (140) -0.4*3/140 = log2+log7+log10-0.4*3/140 = 0.3010+0.8451+1-0.0086= 2.1375 (approx)
czcams.com/video/eKdOPrWobhw/video.html
thanks mam such a easier trick to find the log without log table . thanks for giving us so much good video.thanks
Been looking for this for a while now.....Thanks
Perfect explanation, now no space for more confusion .... Thnxx u so much .. keep.it up ma'am
Thank you so much arham
Wow maa'm kitna accha trick hai
Thanku so much
💯👍🏼 You are the Best teacher mam ur teaching is exllent v very thanks for this video🙏✨️😇👌
Thank you so much..Happy learning
U are great ma'am. Thank you for your help. Upload more!!!
Thanks your very much mame god bless you and help to make your future brighter. Your video lectures are very much helpful for me
Thank you so much for your wishes..All the best..
Thank you ma'am. It is very helpful 🙏🙏🙏🙏
I had been searching for this videos since last month...... 😍😍😋thanks mam......
Log(mn) = log(m)+log(n) formula is used above
Yes
Thanks so much this was so helpful 😊😊😊😊
Happy learning
Why log 6 was written as log 2 + log 3 ??
log mn = log m + log n
Thank you mam
It is very impotant in hsc exam
Thaks again and again!!!
I always struggled with numericals having log in it. but mam today your video helped me a lot and now i can solve log questions easily.
Great Akash..Happy learning
Thanku mam...🤗....it is very helpful...✨❣️
Thanks a lot mam 😊😊😊😊😊
Thank you maam your trick really helped me ☺️🤗
But mam we can't find log of every type of numbers, like which are in 4 digit or in 5 digit and also the numbers which are in decimals
eg 6 digit : log ( 240010) = approximately log (24 * 10^4) = log (24) + 4 = log(2*2*2) + log (3) +4 = 3*.3010 +0.4771 +4 =5.380
amazing mam thanks it helps us a lot during exam..
Thank you so much mam .
I really understand the concept
Thank you so much mam
But I have a doubt on how to find log 4 /3 please tell me as soon as you can mam
I got it
Nice ,thanku mam....
Greatest Video of all time 🔥🔥🔥
Yesssss
Ma'am..i think you might be mistaken on log 5 =0.699 it supposed to be 0.6990 i.e you miss 0.🥰
In log 85,can't I approximate it to log 86 and find answer? Why should I use log 84?
you can do
Thank u mam it is easy to apply in exam
Mam there is doubt to me that is when Adding or Multiplying then you were adding in case of multiplying what would happing mam..
Basics of logarithms you must know
Log (ab)= log a + log b ( with base 10 or e )
Mam pls help me find log 1.9, pls pls
Madam in vedio u turned page next log6 means u written log2+log3 then it become log5 Na madam
WATCH MY LOG VIDEOS . log(x) + log(y) = log(xy) czcams.com/play/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0.html
I am watching from Nigeria
And i found your teaching so helpful.
Thank you for this maam
Thank you so much .. Happy learning
How to find the value of log 38 how we will take approx of it as how we can expand it into 39 or 37 this two can't be expanded to 2-11 logs value 😢pls anyone answer 🙏🏼
czcams.com/video/V-CUOc_7Qgw/video.htmlsi=aLJXrbFEmf6hvKWm
As log 38 or log 39 nearest values, we take approximation.
To find accurate values kindly go through the above video.
Thanks mam its nice , can u tell how to find log for 1.667
Log(5/3) =
Log5 - log3= 0.699-0.4771=0.2219
Mam doubt: how to find log 179,can u help pls
Approx and exact methods are there. Let us take it as 180.
Then it is 3*3*2*2*5 : 2log3+2log2+log5= 2*0.4771+2*0.3010+0.699
Superb explanation
Mam,
How to use log for volumetric analysis..pls make video mam
czcams.com/video/yD3CYfnVDEI/video.html
Thanks a lot Ma'am... It helped a lot.
How to calculate value of log 2 and log 3 reply
you have not fully watched the video. The aim of this video is if you remember log2, log3, log5 and log7 values, you can find the other values with approximation.
Thank you so much
God bless you
Mam how to do log 95 ?
take approx log96; log(3*2^5) = log3 + 5 log2 = 0.477 + 5*0.3 = 1.977 approx
Helped me a lot. You are great mam
Superb madam thnsks for u r tricks..
Thank you ma'am
What about log(3/5)
log3 - log 5 = 0.4771 - 0.699 = -0.2219 (or -1 + 0.7781)
@@Worldofchemistryclass11and12 thank you for replying ma'am really appreciated
mam then what do we do for log and antilog of decimals
For log, convert the decimal number into non decimal number by multiplying and dividing with 10,100 etc.
Thankyousomuchh ma’am 😍
Tq mam tq very much 🤩
How u did log 6?? U just added log 2 and log 3...but 2 plus 3 is 5....how did u do that?
log2 + log3; log(mn) = Log(m) + log(n)
Nice mam it was very helpful
Continue this tricks series
Superb!Mam how to find log in decimals? log 1.06
LOG(1+0.06) = LOG 1 + 0.4 * (0.06/1) = 0 + 0.024 = 0.024 ( this is just nearest approximation) look at my video how to find perfect log
Log 2 + log 3 = log 6. How's but?
ma'am prime no.s for example 13 ka log kaise nikale?
miss what about if i got to find such prime numbers like 17.....etc
for approximation; take value in between 16 and 18. I did log video for exact values also.
awesome ma'am
Thanku so much really it is very helpful to us 😘😘
Welcome..Happy learning
Log 19? With step
you take log 20 for approximation; log2 + log 10 = 0.3010 + 1 =1.3010; so log 19 will be slightly less than 1.3; exact value also can be known ; watch my log videos. playlist: czcams.com/play/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0.html
Thank you. Maaamm..❤❤
Thank u so much 😀😀😀reallly great
mam but for log 6 .. i thought at last u will add log 1 to it bez log( 1+2+3) makes log 6 ... is my understanding crt mam ???
Log(2*3) is log 2 + log 3
I like this. Only want to say we may not memorise log 5 as it is log10-log2
Yes.
Ma'am how to find value of log (1.062)
1.062 lies in between 1.05 and 1.08; (a) Take 1.05 in place of 1.062 now log(1.05) = Log(3x5x7) x 10^(-2) = log3+log5+log7 - 2log10 = 0.4771+0.699+0.8451 -2 =0.0212; (b) take approx 1.08 in place of 1.062 Now log(1.08) log(3^3 x 2^2) + 10^(-2) = 3log3+2log2 - 2 = 3x0.4771+2x0.3010 -2 = 0.033. now the value lies in between 0.0212 and 0.033; hence the answer is 0.027 approx
Is this for neet exam im a PCB student i dont have maths so is it compulsory to learn this?
useful for numerical problems
Really mam I am grateful to you
Happy learning
Thank u so much mam it's really help in medical test
Tq it's very use to me tq do much mam
Mam I am a bio student so mam without gaining a lot more knowledge about logarithms can I just solve all the chemistry class 12 numerical based on your this trick only ?
It depends on the type of problems.
mam how to find log of three digit numbers
Complete log based Concepts are done and kept in playlists..pls do check czcams.com/video/MXwIDTH-l-g/video.html
thank you very much mam 💖💖💖💖👌🏻👌🏻👌🏻❤️❤️
mam understand very well but use in some numericals of intermediate level mcq it is more helpfull
Please watch log videos in the link:
czcams.com/play/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0.html
Mam log 6·2 how to find mam give trick mam
(1) you can take approx value as log 6; then log(3x2) it is log 3 + log 2 = 0.4771 +0.3020 =0.7791
(2) since it is log 6.2 (not log6 as we calculated) , you can approximate 0.7791 to either 0.78 or 0.79.
Thank you mam
@@Worldofchemistryclass11and12 thank you mam
Thank you ma'am 😊❤️👍
Thanks
Log 3*log3 =???? Please give me the answer
0.4771*0.4771 =0.2276
Thank you so much mam
Good use
Thank you mam it really helped
Thanks mam it is very helpful.......... 👍👍
Thank you ma'am 😢❤
Welcome and Happy learning
what if the log is in fraction ?
log(0.02) = log (2x 10^(-2))
Thankyou mam😌❤
thank you mam it was reallhy helpful