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Find log of a number without Log table and Calculator
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- čas přidán 20. 03. 2017
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Here is the trick to find the log of any number without a calculator and log table.
Many times people face problem when they almost solve the problem but get stuck at any log value. It is possible that at that time you don't have the log table, calculator or internet. Worry not, here is the trick to find log with just pen and paper.
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PAYPAL - paypal.me/paytoanshul
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Here is a trick to find antilog. Check it :) czcams.com/video/nx0hFLzdTPE/video.html
Thanks Brother ! I wasn't able to complete the "Chemical Kinetics" numericals I had to leave them at the end, but now I know that how we can slove it! Thanks a lot
Always welcome. This trick has helped me in equilibrium too.
Glad that you liked it. 🙌🙂
@YASH DAHIYA even me I am struggling lot in chemical kinetics and in electrochemistry too to find Kc value 🥺🙏🙏
Hey same here🤟
Same problem,I am a neet aspirant ,I don't know how to find log ......but now I can solve problems.
@@Phoenix77750 ninga neet 2022 va bro
i hardly leave comment only for those who are the best and you made me to leave a comment for your unique trick
Thanks a lot ... great People like you helps us to clear jee main and advanced
U cleared jee mains and advanced?? Pls tell me you are from which iit and you are from where ...also, prescribe some books for me im in class 10
Read ncert text book thoroughly that's enough
@@sakshamsaklani1554 nikal
How do I explain the 2.42
Thank you for this. I find it intriguing. How do you come up with the constant 2.42. I am curious. I used 2.33 for more accurate results. Is this connected to the fact that log10(e) = log10(2.718) = 1/ln(10)?
You know, ln(10) is about 2.3
In the notation below, let lg(x) represent the logarithm to the base 10.
Let ln(x) represent the logarithm to the base e ~=~ 2.718.
If one ever wanted to calculate common logarithms (base 10) by hand
without scientific calculator nor access to Logarithm Tables, it might
suffice to memorize (or write on a small index card) the following
approximations to the logarithms of a handful of the first several prime
integers.
lg(2) ~=~ 0.30103
lg(3) ~=~ 0.47712
lg(5) ~=~ 0.69897
lg(7) ~=~ 0.84510
lg(11) ~=~ 1.04139
In the video above, there is the magical constant 2.42 in the formula:
lg(a + b) = lg(a) + b/(2.42*a)
Notice the following:
e ~=~ 2.718
lg(2.718) ~=~ 1/ln(10) ~=~ 0.43429
ln(10) = 2.30258509299405 ~=~ 2.3
What happens when we replace 2.42 by 2.3?
Then the formula becomes:
lg(a + b) = lg(a) + b/(ln(10)*a)
or, demystifying the constant term even further,
lg(a + b) = lg(a) + lg(2.718)*b/a = lg(a) + lg(e)*b/a
I
can understand how inviting it is to latch on to magical constants, but
it gives more insight when you explain why you use that constant and
can explain how it was derived (and why it works).
As I mentioned, using 2.33 makes for even more accurate approximates.
This is why I am so curious about your constant 2.42.
Could you tell me its significance, please?
Sincerely,
Mike
I'm not sure where he got the 2.42 constant from either, it should be ln(10)≈2.3026 (rounding up to the fourth decimal point). This formula could be derived from the Taylor approximation of lg(1+x)=ln(1+x)/ln10=(x-x^2/2+x^3/3-x^4/4+...)/ln10. If we only take the first term then lg(1+x)≈x/ln10 when x is small enough. So when b/a is small enough with respect to one then lg(a+b)=lg(a)+lg(1+b/a)≈lg(a)+b/(a*ln10). One can take more terms in the Taylor approximation ln(1+x) = (x-x^2/2+x^3/3-x^4/4+.. etc) to get more accurate results.
BTW, it's also useful to memorise the value 1/ln(10)=lg(e)≈0.4343
very nice we appreciate your commitment towards educating the society
i personally found your constant 2.33 more accurate and convincing
thank you!
Do you have any such trick for finding cube root?
pavan raibagi ...
Anshul Kumar upld Kiya kya
yes.. its actually easy..
does this work with a different base?
How did u find this such a great formulae???Thanks a lot
I really wonder that why this video is not celebrated as the most prestigious video for maths. Congrats you are next John Napier...
Thank you bala for your appreciation and comparison with great Scottish Mathematician John Napier but no one can match him. :)
Can I ask about the 2.42? What is the most exact number to represent that?
Actually someone in comments pointed 2.33 is giving more accurate answer. End of the day, it's approximation and we can't get accurate answer but we can get near to accurate answer.
So 2.33 is more accurate .
@@AnshulBITSPilani thank you very much sir.
Good anshul share some more simple tricks
Thank you so much!! Very useful especially in chapters like Ionic Equilibrium! Thanks a lot
Oh boi..its 12:49 a.m right now and have an exam tomorrow..thank you soooooo much 💙🌺💙
Thanku bhaiya...I was frustrated with problems of chemical kinetics ...this video solved most of it
Welcome :). Glad it helped you. Kinetics aur Equilibrium me bahot kaam aata hai.
I tried it yaar! Worked for me! Thanks for making it easier....
that is just plain awesome man!
Thank you very much. Please like and subscribe to support.
Wow sir...its very helpful for me
Sir is there any tricky way to find the values of trignomentric functions?
Glad you liked it, don't forget to like and subscribe. Well, I guess there's no way to find values like sin(71.89), cos (85.23), etc without calculator.
Awesome bro... Thank u so much
Very good explanation ,hope u get above 100 subscribers soon
Great way of doing it. You can also use Maclaurin series or approximation for the natural logarithm and then divide by ln of 10.
Wow bhaiya; nicely explained
2 things:-
1) u dont need to learn log 5 bcoz log 5 can be written as log 10/2 and then 1 + log 2.
2) and also for log 7 it could also be broken as 3 and 4, but by ur formula it comes as 1.028 and in reality its 0.845, so the formula doesn't always work or maybe there are some restrictions that u didnt mentioned, so pls remake this vid
and except these 2 it was nice.
First point is also a way to write, nice.
For the second point, in the formula, you need to make "b" as small as you can.
So instead of 7 = 3+4 you can choose, 7 = 6.9 + 0.1 this will give you more accurate answer. But you don't know the value of 6.9 without calc. That's why I said to remember 2,3,5 and 7.
@@AnshulBITSPilani alright thanks
Great ✌️
Omg u have saved the lives of manyyy people😭😭😭 thanks a lottttt!!!
What to do if we get log 6 + something, we don't have value of log 6
log6 = log(2x3) = log2 + log3. That is the property of log.
Thank you
Sir that was amazing trick for finding log of any no, sir if you have any tricks for iit jee plz make videos
Thank you bro this log table will be very useful for my neet exam thanks a lot bro make many more videos
How did you get the lof 7 without using calculator or tables?
Thank you soooo much... Ur trick helped me a lot.. Thnkx a lot
Welcome. Glad that it helped you. All the very best :)
bhai yaar.........aapne to katayi kamaal shikha diya.
More examples please...☺
I want the videos for solving decimal numbers log
Thankyou so much sir...
Thank you for this concept.
Tnks a lot for your explanation...Will u make a video giving tips to get a seat in bits pilani...this is my request!!
Request accepted. Good idea. I will be uploading a video in 2-3 days.
Man your trick is awesome!!!!
best video on the internet before my chem exam
Thanks man.
Pls solve log 1.9 by same method
Nice Video But How I Will Find Log For The No. Like 0.58,0.98 Etc..
Just put (-b) instead of b in formula
Thanks Anshul, that was very helpful
Thank you from the bottom of my heart. I have been searching for such a formula for my upcoming exam.
Welcome:)
Great
Thanks man.
amazing work!
Thanks bro for this Superb and
Very simple formula
this become very helpful for me
nice work and thank u for the formula
Honestly.Excellent, log become easy.
Thank you sir. Lot of help in intermediate 🙏🙏
Happy that it helped you. Always welcome :)
Thnx bro... plz upload how to find antilog without using calculator and log table
Man can you give me the more exact value of that constant (2.42)please?
Sorry man I don't have the derivation with me still.
Thank you sir
Bro i calculated log(6.2)
As =log(3+3.2)
=log3+3.2/(2.42*3)
=0.477+0.4407
=0.9177
But actual value of log(6.2) is 0.7923
Its coming wrong howcome?
Please reply..
Good.
See, you need to make b as much small as you can.
You can write 6.2 as 6+0.2 or 3+3.2 or 1+5.2 or many. But you will get most accurate for 6+0.2 as "b" here is 0.2 which is small.
@@AnshulBITSPilani thanks good to see u replied on a comment for a video u uploaded 3 years ago😅
😂 Yeah, I have a habit to reply everyone.
Nice bro...
Antilog ki koi trik h
Thanks a lot bro ❤ really helped me
Always welcome 😊✌️
hey ur hand writing iz cool bro
What was so spcl in his handwriting?🤷♀️
The cursive is pretty good .😃
Too gud sir .... soo easy and right
Thank you amazing teaching bro
Thnx a lot ur trick helped me alot in my chemistry exam....tysm for Ur trick 😘
Bhaiiiiiiiii thank u soooooooooooooo much
pooora 1 day waste kiya tha but tabhi bhi ni seekh paaya log but aapki video se ek hi baar mei seekh gaya
thank u sooooo much
Welcome :) Aapko video pasand aayi aur aapki madad ho gayi, yahi kaafi hai mere liye.
Khush rahiye hamesha ✌️
amazing thanks a lot you just got a new subscriber
Thank you very much.
NOW THATS A COOL TRICK , THANKS BUDDY !!!!
Thank you very much. Glad that you liked it. 🙂🙏
Very nice trick
good work man...apreciable...really helping
Bro then how t find antilog
but how can we find the value of 13,17,19
Where you find the log a+b formula ?
It was using Taylor series.
The most important scientific result of your example is that noisy children will emerge in the background whenever mathematics is being examined.
how to do it when we have to find log of a 0. decimal no. like for eg. 0.952
Thank you sir it is very useful to me 👌👌👌🙏🙏🧚♀️🧚♀️🧚♀️🧚♀️
How to take log (0.58) ??
why cant i find log55 using this method
Bro I will be always grateful to you
Lovely video beautiful
Keep up the good work
Thanks
Thank you for these kind words. Keep smiling. :)
But can u help in finding logs of 1.6,1.5,1.9
Thanks
Thanks for ur amazing trick
Ramchandra Prabodh nj
tanishka Sharma then the formula would reduce down to log(b) ;)
How to find log 660
can u make a video about chracterstic and mantisa
This was really helpful...thank you so much
what is the value of log1000
What will be the log of 4688
It works but can we remember 4 5 8 9 values similarly...
What would log3.4×10 to the power -3 be?
Hey bro , the log(a+b) you use in the video is standard formula. Is it written in any book or you get it from somewhere else?
Thanks this video is really helpful
How to find log of 0.1 or 0.02 or no.s like that using this trick?
log (0.02)
log( 2 x 10 ^-2 )
log 2 + (-2) log 10
0.301 - 2
-1.699
Thankuuuuuuuuu veeeerrrrryyyyy muuuuuccccchhhhhh☺️
It was a great help anshul 💙💙
Sir, Please upload a video on finding an ANTILOG VALUE of any number without using calculator or log tables.....
@@AnshulBITSPilani plz help in finding antilog too without using calculator or table
I think apko vedantu ma Arora sir ka video dekhna chahiye for antilog
Very good
Please bro please give the trick for tan inverse for physics
I find it mostly using properties or sometimes using calculator. Don't have trick like this for tan inverse. Sorry :(
Thankyou so much :)
How to find log1.8
How to find log23
Plz ipload how to calculate th3 antilog of a number
How do we find the value if there's a base
Eg: log 20 base 6?
log20 base 6 can be written as (log 20)/(log 6) both as base 10. It is a property.
I really like this video. Ty for making this video...
Is there any trick to find sin,cos and tan
I don't think so. I tried to get the values of sin, cos without calculator but wasn't able to get them with high accuracy.
Thank you.would u pls explain log0.08 ie below 1, with out calculator
Yes. Let's see.
log(0.08) = log(8x10^-2)
-2+ log8
-2+ 3log2
-2 + 0.903
-1.096 is the answer.
Thank you so much for this....God bless you.
Welcome. Very happy that you liked it.
God bless you too. :)
Thankyou
Thank u very much bro
Bit how to find the value of log 0.6, log 0.7 etc?
Thax u bro
Thank you so much for this!!!
Always welcome :) . Glad that it helped you.
u r awesome bro. plz make a video on anti log without antilog table...
thank u very much .thank u extreamly .u made my day