Example 6.12 |Chapter 6| Bending | Mechanics of Material Rc Hibbeler|
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- čas přidán 28. 12. 2022
- Example 6.12 The simply supported beam in Fig. 6-26 a has the cross-sectional area shown in Fig. 6-26 b . Determine the absolute maximum bending stress in the beam and draw the stress distribution over the cross section at this location.
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I wish my teacher taught and explained like this.......
Your content is extremely helpful Sir.
Made the topic extremely easy to understand.
Appreciating every effort of yours.
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Plz solve Example 6.14
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Thank you sir . Please solve this chapter exercise question (bending stress)
czcams.com/play/PLuj5YwfYIVm9CxuqONbS-s67TM9AdIpPg.html
I have shared the link of this chapter playlist...keep watching and sharing....
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Sir please take my humble respect. Sir I have a question. Sir why the stress at point B is negative?
Thank you for your interest. Well you can see that uniformly distributed load on beam is downward causing compression in upper portion above neutral axis which is considered as negative. The negative mean its in compression while lower portion of beam below neutral axis is in tension so stress is positive. The Sam can be demonstrated by flexure formula stress = -(M.y)/I so y is distance from neutral axial either above or below. Upward y is taken as possible so if you put in the formula the stress is negative which mean compression and point B is above neutral axis so that's why it is negative. I hope it will clear your idea. I shall suggest you to watch my theory video of chapter 4 lecture that is about bending. If you feel any difficulty in finding that lecture then do let me know I shall share the link. ❤
@Arnab BARUA did you clear your concept about what you have asked?
Thank you so much Sir,for your kind response.I have understood the concept clearly.
Good to know that....
A 48 ft long plate girder is simply supported at the ends and it has a distributed
load of 2.6 kip/ft and three concentrated loads of 30 kip at x=12 ft, 24 ft, and 36 ft, as shown
below. A designer provided you with a recommendation of using 1"x16" flange plates and
3/8"x63" web plate, as shown below. The girder is constructed from A-36 steel using E60XX
electrodes for all welds.
a) Draw a shear force diagram and find the maximum shear force in kip.
b) Draw a moment diagram and find the maximum moment in kip·ft.
c) Find the maximum bending stress in ksi.
d) The flange plates are welded to the web plate on both sides using matching intermittent 5/8"
fillet welds. What is the minimal total length of the intermittent welds for each side?
e) Bearing stiffeners that are 0.5"×63"×7" are used at the left and right end supports. Find the
minimum fillet weld size of the weld (in inch) that is required to join the bearing stiffeners to
the web plate.
Sir....Can you solve this question on youtube?
If get time I shall try on this as well. Actually I am only following the books that are taught in universities.
Sir.
I don't understand where does the moment 22.5 came from. 7:34
Ok From bending moment diagram you can see the maximum value of bending moment is 22.5 KN.m so it's from BMD (bending moment diagram). I hope it's clear now ❤
@mohammadtabish5949 did you get my answer?
Thank you so much sir
@mohammadtabish5949 you are welcome
Sir please explain moher circle with example
czcams.com/video/DkC-gpzDkxo/video.html you can watch and learn the mohr circle with example
czcams.com/video/czRAytEZshw/video.html
Mohr circle for 3 dimensional state of Stress.
czcams.com/play/PLuj5YwfYIVm81VTdkJjQuPCO4F3MQJhPN.html
In this playlist there are 287 solved problems you can scroll down and find problem 7.31 related to mohr circle. Also you will find many more related to it. Enjoy and learn thank you
SIR
PLZ SOLVE EXAMPLE 6.14
Ok 👌 👍
PLz sir plz upload as fast you can . I have no words to thank you
@FSCTutor-yb9jb at this moment I can't as I am suffering from Malaria.
@@engradnanrasheedmechanical Ok take care of your self . Health is more important, can I have your Gmail or any contact number so when you are good I can remind you. Thanks