![Engr. Adnan Rasheed Mechanical](/img/default-banner.jpg)
- 1 199
- 1 698 289
Engr. Adnan Rasheed Mechanical
Pakistan
Registrace 26. 02. 2021
Free education is the right of all students
IN MY CHANNEL , YOU WILL FIND MECHANICAL ENGINEERING'S SUBJECT REALTED VIDEOS WHERE YOU CAN CLEAR YOUR CONCEPTS.
IN MY CHANNEL , YOU WILL FIND MECHANICAL ENGINEERING'S SUBJECT REALTED VIDEOS WHERE YOU CAN CLEAR YOUR CONCEPTS.
Mechanics of Materials II | Full course | Mechanics of Materials Beer & Johnston
Dear Viewer You can find more videos in the link given below to learn more
Theory Video Lecture of Mechanics of Materials by Beer & Johnston
czcams.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html
287 Problem solutions of all chapter of Mechanics of Materials by Beer & Johnston
czcams.com/play/PLuj5YwfYIVm81VTdkJjQuPCO4F3MQJhPN.html
Chapter 14 Energy Methods of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-PA_G-pJgZTpxfuaFP3kvc.html
Chapter 12 Deflection of Beams and Shaft of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-zYKIRhkcp8T14ca9gKZVM.html
Chapter 11 Design of Beams and Shafts of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-LNfim-eGqefyotIJdSDnH.html
Chapter 9 Stress Transformation of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-hYQnQ1py3DzEYQ5Soxqxg.html
Chapter 8 Combined Loading of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm_Cb-9cfYW-LZc1Fk7jSSEq.html
Chapter 7 Transverse Shear of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm8XgaWLuFz55Me-A2wqY9KV.html
Chapter 6 Bending of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm9CxuqONbS-s67TM9AdIpPg.html
Chapter 5 Torsion of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm8WVZtox6HmH9twnhatiSGV.html
Chapter 4 Axial Loading of Mechanics of Materials rc hibbeler (09th Edition) czcams.com/play/PLuj5YwfYIVm-r7fIpVRkrKmAd-3y9oQrY.html
Chapter 3 Mechanical Properties of Materials of Mechanics of Materials rc hibbeler (09th Edition) czcams.com/play/PLuj5YwfYIVm-c8udJe90nd5IwZnfliXKe.html
Chapter 2 Strain of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm_gzYUFcDE33LeGcn-PfrIy.html
Chapter 1 Stress- Internal Loading of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-LUJemLDD3dPUXZhksGCHu.html
#mechanicsofsolids #strengthofmaterialstutorials #mechanicsofmaterials
Theory Video Lecture of Mechanics of Materials by Beer & Johnston
czcams.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html
287 Problem solutions of all chapter of Mechanics of Materials by Beer & Johnston
czcams.com/play/PLuj5YwfYIVm81VTdkJjQuPCO4F3MQJhPN.html
Chapter 14 Energy Methods of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-PA_G-pJgZTpxfuaFP3kvc.html
Chapter 12 Deflection of Beams and Shaft of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-zYKIRhkcp8T14ca9gKZVM.html
Chapter 11 Design of Beams and Shafts of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-LNfim-eGqefyotIJdSDnH.html
Chapter 9 Stress Transformation of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-hYQnQ1py3DzEYQ5Soxqxg.html
Chapter 8 Combined Loading of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm_Cb-9cfYW-LZc1Fk7jSSEq.html
Chapter 7 Transverse Shear of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm8XgaWLuFz55Me-A2wqY9KV.html
Chapter 6 Bending of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm9CxuqONbS-s67TM9AdIpPg.html
Chapter 5 Torsion of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm8WVZtox6HmH9twnhatiSGV.html
Chapter 4 Axial Loading of Mechanics of Materials rc hibbeler (09th Edition) czcams.com/play/PLuj5YwfYIVm-r7fIpVRkrKmAd-3y9oQrY.html
Chapter 3 Mechanical Properties of Materials of Mechanics of Materials rc hibbeler (09th Edition) czcams.com/play/PLuj5YwfYIVm-c8udJe90nd5IwZnfliXKe.html
Chapter 2 Strain of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm_gzYUFcDE33LeGcn-PfrIy.html
Chapter 1 Stress- Internal Loading of Mechanics of Materials rc hibbeler (09th Edition)
czcams.com/play/PLuj5YwfYIVm-LUJemLDD3dPUXZhksGCHu.html
#mechanicsofsolids #strengthofmaterialstutorials #mechanicsofmaterials
zhlédnutí: 214
Video
Mechanics of materials | axial load | Energy Methods | Engr. Adnan Rasheed Mechanical
zhlédnutí 144Před 21 hodinou
1-84. The frame is subjected to the load of 4 kN which acts on member ABD at D . Determine the required diameter of the pins at D and C if the allowable shear stress for the material is tallow = 40 MPa. Pin C is subjected to double shear, whereas pin D is subjected to single shear. 1-86. The two aluminum rods support the vertical force of P = 20 kN. Determine their required diameters if the all...
Mechanics of Materials 1 | Full Course | Mechanics
zhlédnutí 288Před 14 dny
Dear Viewer You can find more videos in the link given below to learn more and more Video Lecture of Mechanics of Materials by Beer & Jhonston czcams.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 260 Problem solutions of all chapter of Mechanics of Materials by Beer & Jhonston czcams.com/play/PLuj5YwfYIVm81VTdkJjQuPCO4F3MQJhPN.html Chapter 8 of Mechanics of Matereials rc hibbeler (09th Editi...
Mechanics of materials | 10 Problems | Mechanics | Mechanics of materials RC Hibbeler
zhlédnutí 214Před 28 dny
Dear Viewer You can find more videos in the link given below to learn more and more Theory Video Lecture of Mechanics of Materials by Beer & Johnston czcams.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html 287 Problem solutions of all chapter of Mechanics of Materials by Beer & Johnston czcams.com/play/PLuj5YwfYIVm81VTdkJjQuPCO4F3MQJhPN.html Chapter 14 Energy Methods of Mechanics of Materials r...
Axial Load | Mechanics | Mechanics of Materials RC Hibbeler
zhlédnutí 177Před měsícem
4-101. The rigid lever arm is supported by two A-36 steel wires having the same diameter of 4 mm. If a force of P = 3 kN is applied to the handle, determine the force developed in both wires and their corresponding elongations. Consider A-36 steel as an elastic-perfectly plastic material. 4-102. The rigid lever arm is supported by two A-36 steel wires having the same diameter of 4 mm. Determine...
4-102 | Determine force P that will cause both wire to yield | Mechanics of Materials RC Hibbeler
zhlédnutí 207Před 2 měsíci
4-102. The rigid lever arm is supported by two A-36 steel wires having the same diameter of 4 mm. Determine the smallest force P that will cause (a) only one of the wires to yield; (b) both wires to yield. Consider A-36 steel as an elastic-perfectly plastic material. Dear Viewer You can find more videos in the link given below to learn more and more Theory Video Lecture of Mechanics of Material...
4-101 Determine the force developed in both wires & elongation | Mechanics of Materials RC Hibbeler
zhlédnutí 275Před 2 měsíci
4-101. The rigid lever arm is supported by two A-36 steel wires having the same diameter of 4 mm. If a force of P = 3 kN is applied to the handle, determine the force developed in both wires and their corresponding elongations. Consider A-36 steel as an elastic-perfectly plastic material. Dear Viewer You can find more videos in the link given below to learn more and more Theory Video Lecture of...
Properties of Fluids | Fluid Mechanics | Fluid | Lecture 2 | Engr Adnan Rasheed Mechanical
zhlédnutí 320Před 2 měsíci
In this very first lecture, i have discussed Properties of Fluids 1. Density or Mass Density 2. Weight Density 3. Specific Gravity or Relative Density 4. Viscosity 5. Capillarity This is initial lecture and needs further improvement but i hope with the passage of time it will also improved. Dear Viewer You can find more videos in the link given below to learn more and more Theory Video Lecture ...
4-100 | Find distributed load w causes one wire to yield | Mechanics of materials RC Hibbeler
zhlédnutí 127Před 2 měsíci
4-100 | Find distributed load w causes one wire to yield | Mechanics of materials RC Hibbeler
4-99 | Determine intensity of the distributed load w | Mechanics of materials RC Hibbeler
zhlédnutí 185Před 2 měsíci
4-99 | Determine intensity of the distributed load w | Mechanics of materials RC Hibbeler
Introduction to Fluid Mechanics | Fluid | Forces in Fluid | Engr Adnan Rasheed Mechanical
zhlédnutí 275Před 2 měsíci
Introduction to Fluid Mechanics | Fluid | Forces in Fluid | Engr Adnan Rasheed Mechanical
8 Problems in 1 Video | axial load | Mechanics | Mechanics of materials RC Hibbeler
zhlédnutí 173Před 2 měsíci
8 Problems in 1 Video | axial load | Mechanics | Mechanics of materials RC Hibbeler
4-93 | Determine the maximum normal stress developed in the bar | Mechanics of materials rc Hibbeler
zhlédnutí 199Před 2 měsíci
4-93 | Determine the maximum normal stress developed in the bar | Mechanics of materials rc Hibbeler
4-92 | Determine the maximum normal stress | Mechanics of materials rc Hibbeler
zhlédnutí 198Před 2 měsíci
4-92 | Determine the maximum normal stress | Mechanics of materials rc Hibbeler
4-91| Determine the maximum axial force P that can be applied to the bar.| Mechanics of materials
zhlédnutí 240Před 2 měsíci
4-91| Determine the maximum axial force P that can be applied to the bar.| Mechanics of materials
4-94 | Find the stress concentration factor for geometry and P | Mechanics of materials RC Hibbeler
zhlédnutí 167Před 2 měsíci
4-94 | Find the stress concentration factor for geometry and P | Mechanics of materials RC Hibbeler
4-96 | Calculating the Maximum Elastic Load for Your Assembly | Mechanics of materials RC Hibbeler
zhlédnutí 182Před 2 měsíci
4-96 | Calculating the Maximum Elastic Load for Your Assembly | Mechanics of materials RC Hibbeler
4-97 | Step-by-Step Guide to Determining Wire Forces in Mechanics of Materials RC Hibbeler
zhlédnutí 108Před 2 měsíci
4-97 | Step-by-Step Guide to Determining Wire Forces in Mechanics of Materials RC Hibbeler
4-95 | How to Find the Maximum P Value for Bolts | Mechanics of Materials RC Hibbeler
zhlédnutí 163Před 2 měsíci
4-95 | How to Find the Maximum P Value for Bolts | Mechanics of Materials RC Hibbeler
4-98 | Calculating Bar Elongation with Mechanics of Materials Rc Hibbeler | Axial load | Elongation
zhlédnutí 155Před 3 měsíci
4-98 | Calculating Bar Elongation with Mechanics of Materials Rc Hibbeler | Axial load | Elongation
Expert Tips: Overcoming Difficulties in Mechanics of Materials by RC Hibbeler | Bending | Axial load
zhlédnutí 512Před 3 měsíci
Expert Tips: Overcoming Difficulties in Mechanics of Materials by RC Hibbeler | Bending | Axial load
4-89 | Axial Force P Calculation Made Easy for Engineers | Mechanics of materials RC Hibbeler
zhlédnutí 247Před 3 měsíci
4-89 | Axial Force P Calculation Made Easy for Engineers | Mechanics of materials RC Hibbeler
Step-by-Step Solutions to Mechanics of Materials Problems | Mechanics of materials rc Hibbeler
zhlédnutí 458Před 3 měsíci
Step-by-Step Solutions to Mechanics of Materials Problems | Mechanics of materials rc Hibbeler
4-90 | Determine maximum axial force P that can be applied to steel plate | Mechanics of materials
zhlédnutí 245Před 3 měsíci
4-90 | Determine maximum axial force P that can be applied to steel plate | Mechanics of materials
4-88 | Determine the maximum axial force P that can be applied to bar | Mechanics of materials
zhlédnutí 354Před 3 měsíci
4-88 | Determine the maximum axial force P that can be applied to bar | Mechanics of materials
4-87 | Determine the maximum normal stress developed in the bar | Mechanics of materials Rc Hibbeler
zhlédnutí 394Před 3 měsíci
4-87 | Determine the maximum normal stress developed in the bar | Mechanics of materials Rc Hibbeler
14-35 | Determine the slope of the beam at the pin support A | Mechanics of materials Rc Hibbeler
zhlédnutí 222Před 3 měsíci
14-35 | Determine the slope of the beam at the pin support A | Mechanics of materials Rc Hibbeler
14-32 | Determine the slope at point A of the beam | Mechanics of materials rc Hibbeler
zhlédnutí 214Před 3 měsíci
14-32 | Determine the slope at point A of the beam | Mechanics of materials rc Hibbeler
Strain Energy in Frames and Beams - Ultimate Guide for Engineers | Mechanics of Materials RC Hib
zhlédnutí 234Před 3 měsíci
Strain Energy in Frames and Beams - Ultimate Guide for Engineers | Mechanics of Materials RC Hib
Strain Energy | Energy Method | Bending strain energy | Axial strain energy | Mechanics of Materials
zhlédnutí 229Před 3 měsíci
Strain Energy | Energy Method | Bending strain energy | Axial strain energy | Mechanics of Materials
i wish all the teachers are as articulated, intelligent and caring as you!!
Thank you
should've been 67.5 x 10^6 right?
It's 67.5 KN.m or 67.5 x 10^3 N.m
Well explained sir. May Allah bless you
Thanks alot 💝
zbr10sir
How did you get the 0.5? Thanks!
In question diameter of rod is given as 1 so radius =c = (1÷2)= 0.5
a boundary condition is in x2 = 0, v2 = 0 right? so...can c4 be 0?
Best channel on youtube for egineering students🎉
Thank you 😊 💓
sir what is L at 4:49:30 plz explain L
L is the total length of the beam....
sir g ya video hum deakh raha hain pass ho jaya ga
Daikhny aor seekhny main farq ha. Seekhoge to khud ba khud pass hoge
Thank's sir
You are welcome and after a long time you commented 😊
Great lectures, anyway, love them
Thank you 😊 💓
Thank you ❤🎉 for the video
You are welcome 😊
Really enjoyed watching the solution
Thank you and keep watching
Excellent ❤🎉
Thank you 😊 💓
Sir, i want to make videos too. Which program do you use for solutions? It automatically corrects your lines and gives you the opportunity to write
Excellent you should start it. The software is Good Notes. It's apple in app store of Apple Ipad.
How did you get 1.6 kip/ft?
You can see that triangular load is 0.8 kip/ft over a length of 9ft. So If we extend this load over a length of 18 ft it will be 1.6 kip/ft.
@@engradnanrasheedmechanical thank you! 🤗
@garciajomel5507 you are welcome 😊
Thank you so much for lesson. Please keep going to make this videos. Could you make problem solutions videos for this course like you do on your mechanics of materials lecture.
I have intentions to start them as soon as I get free time. Currently I am too much busy in MOM 1 and Mom 2 course in summer semester
is this in the course of mechanical enginering,i am in first year but i want to study it should i if not then what shoud i read other than first year ,i am just curious
Yes it's a major course in Mechanical engineering ....the building block as well
@@engradnanrasheedmechanical i searched it in my mechanical syllabus but did not find,what could be its another name,i am from neduet
@user-vl6qt1zr1z it will be solid mechanics or strength of materials or mechanics of deformable bodies otr mechanics of solid
For the given problem and data the answer should be 28.2 kips.
The links aren't working!
Which link?
one of my favorite subject. learnt most from your videos
Happy to hear that!
Sir yeh website open nahi hota.. server issue dikhata hai net connection
It works only on official days and office times.
Adnan I fucking love you man :), you're the best.
Share my videos with your friends as well.
Very useful video
Thank you 😊 💓
What book is this
Book name is given on thumbnail and its mechanics of materials by rc hibbeler. Thank you
Thank you sir ❤❤❤❤
So nice of you
Glad to see you back sir 🎉🎉
These are older lectures but i have compiled all lectures of Mechanics of materials 1 in just single video. Soon i shall come back to CZcams with new videos inshallah.
how do we know there is shear force in bolt? where is the formula for n coming from?
The two shafts are join by coupln as shown in th fig by bolts. The shaft is experiencing twisting moment therefore bolt will be having shear stress due to twisting torque. For n number of bolts we can find shear stress by using formula of shear stress due to torsion.
Why you take 5kips in negative. The load seems to be tensile..
You can see that net force is 5 kip towards right side so in order to keep it in equilibrium 5 kips load will act towards left side which is creating compression so that's why it is taken as negative.
Thank you 😘
You are welcome and keep watching
jazakallah
thank you 🙏
is there another method of solving these long problems?
These are the methods for solving these problems
When does we know if the internal torque diagram is in negative and positive?
You have to check the overall effect of external torque if overall external torque acting come out to be positive then internal torque should be clockwise and vice versa
Nice
Thanks
Congratulation sir🎉
Thank you 😊 💓
waw Es me Reverse bhe he 😊
Yes all features
@@engradnanrasheedmechanical Sir as we know that for FYP one have to implement a new idea...Like students have to make some innovation...So tell us. What is the innovation in this achievement through a brief video .please
@salmankhanmohmand9174 hahahahaha the interviews of this student is available, if you want I can send you
@@engradnanrasheedmechanical oK sir
Thank you for all your help. You are the best!
You are always welcome bro...
Assalam o Alaikum sir, can you please upload the theory lectures?
W.salam here is the link for all Theory lectures Mechanics of Materials Beer & Johnston online Lectures: czcams.com/play/PLuj5YwfYIVm9GBcC6S4-ZgHS1szlF7s1Y.html
why you neglected the 3kip force?
You can take it and it will be 3 <x-18> but for x is less or equal to 18 this term will become zero that's why we neglect it to minimise the solving time. I hope it will be clear now
@@engradnanrasheedmechanical i understand, thank u so much
@kalaaaa0403 you are welcome and enjoy your day.
I love you Adnan Rasheed!
Thank you so much for your love. Kindly share my channel with your friends and help me in growing further.
Hi, i think there's an error when converting 95mm to m . It should be 0.095 m
Yes it should be.
Thank you 🌻
You are welcome 😊
what happened?
Thank you very much for your detailed video
Glad it was helpful!
Hello can you cover problem 4-23? I have some questions on how to use poisons formula when trying to find deformation.
czcams.com/video/HjODIULH_Ek/video.html Here is the link for Problem 4-23
may I know why the 20kN of the right hand side is not considered when making the moment equation?
Because when you take it the term <x-6> will become zero for x is less than 6 or equal to 6. I hope you will understand now.
@@engradnanrasheedmechanical oh I see thank you so mucj
@lohguowei7559 you are welcome 😊
Sen nasıl bir kralsın Türkiyeden bir öğrenci olarak yazıyorum bu güzel içerikleriniz için çok teşekkür ederim.🙂🙂🙂
Harika yorumlarınız için teşekkür ederim ve kanalımı arkadaşlarınıza da tavsiye edin. iyi günler
you do all the questions I asked for assignment and exam
it's good for you enjoy 😉
do recommend my channel to your friends as well
Why you didn't include the tension? I'm confused.
Where?
The cable. Why it is not included in your fbd?
@@treilevoug5137because it is connected with vertical member AB
Oh. I see. Thank you.
@treilevoug5137 you are welcome 😊