Mechanics of Materials: Lesson 31 - The Flexure Formula, Beam Bending Example
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you are a combination of a cool dad and a great teacher
I_2 = (7(1)^3)/12 + 7(10.5-7.85)^2 = 49.74in^4. Yes, In the video it appears that he makes an Algebra Error. for the Final Answers when done correctly I am getting: NetI= 235.13in^4, N.A.= 7.85in., Max Tension = 1.60 ksi, Max Compression = 0.64 Ksi.
yh u right
Thank you so much
You’re right
yep I noticed this as well
Ty
my textbook did nothing for me this week. Read it and had zero idea what was going on. These videos are a life saver!
I just wanna say, I have probably watched dozens of these videos now between my professors using them and just going back for help. Thank you for all you do! You're very helpful and it's a nice way to learn!
Thank you for the help, graduating with my associate's this year and I need to do well on the exam. Your video really helped! Best luck to you and everyone in your future endeavors!
For the middle calculation for Ix' I got [(1/12)(7)(1)^3]+7(2.65^2)= 49.74. Am I doing something wrong?
I think Jeff made a mistake there. You did it right.
Yeah, I believe it was just a simple algebra mistake. Thank God computers do the algebra for us in the field.
Yeah he just made a mistake and got 7 instead of 10.5 you are correct sir
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
Our professor is making us teach ourselves Mech of Mat, thank you so much for this.
I must say: thank you very much for your fascinating lecture, I am addicted to it 。
Thank you I’m reviewing this for my mechanical design class
The whole time I looked at the beam section as if it is a side profile and so it never made sense to me.
You are literally the only one that explained (with your hands) how the moment acts on the beam, and now all makes so much sense.
Out of all my course mates (about 240 people) nobody knows this. Bad students or a bad teacher?
Nevertheless, I you have thanks!
You are the best lecture... Thank you sir very much..
sir for Inertia of Area 2, it should be 49.74 in^4...
yes I agree
Thank You! Hopefully this helps on my exam
I love you jeff! have a beautiful existence!
I need help with regular stresses, shear and cornering, and the transfer of regular or clipping force from the permissible to his cross section. Thank you.
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Why does the end blur out and the sound go away?
How do you know which side is in compression or in tension, I cannot visualize it
Material towards the bottom has to get longer as the surface is stretched due to the direction of the moment applied thus in tension. Material towards the top is being squeezed together due to the direction of the moment thus compressive.
T-beam, what is the Top (Tension) and bottom (compression) will be if we bend the shape in an opposite direction downwards, not upward as illustrated?
yes
Wise old man.
شكرآ
sir ,for bar 3 & 4 is it not y=10 inches ?
yeah it should be
The height from the base to the top is 11 inches, and the centriod of parts 3,4 is 1.5 so 11-1.5=9.5
2:41 for cat meow
** one of the Ixx answers is wrong. 62.87 should be 49.7
shouldn't compression stress be -.609 ksi? not positive
Labeling it as compressive is equivalent to using a negative sign. So if you labeled it as compressive and used a negative sign that would actually mean positive (tensile). I hope this helps
why doesn't d come out negative in a*d^2? pretty sure 7.85-10.5 comes out negative
yes but a square always results positive
can centroid be smaller than the y
Not sure what you are asking here?
While he is calculating the second line of Ix', he pressed on his calculator the buttons 9 then 8 for 2.98^2 instead of pressing 6 then 5 for 2.65^2 that is simply what happened with him.
You'd have to reconsider your degree if you're disliking these videos.
there is a mistake, it is 49.74 not 62.87.
Your answer is wrong
Thank you Jeff.