A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight tow
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- čas přidán 24. 11. 2015
- A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.6 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?
you are the best! you literally explain the question 1000000000000 times easier than my professor!!!!!
Thank you I had been struggling to understand this problem for my homework. Great video!
Thank you for explaining, this helped very much.
Very helpful to understand how to solve these problems.
My teacher kinda did an example really quickly so trying to understand while copying what he's writting was too much.
Thanks!
Thanks for the feedback!
This helped me out so much, thank you.
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This helped me a lot. Thank you!
Very helpful! Thank you!
im in yr 9 and this helped with my probem thx so much
Thanks for this!
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Thank you so much!!
thank you!
thank you sir
How does this guy have the exact problems from our exams!!🤯
My professor is the type to say something the way it is because...reasons. I'm happy I found this video
Thank you! Thais was on my homework and I was stuck!!
great help!
Thank you
You're welcome!
why did you have to use two variables when they tell you that hes 4 meters away as such you could've figured x to be 8 easily and use proportions to find the height of his shadow.
That's what he did, didn't he? He just used the variables to find "3".
Let me say that at first I solved this the same way you did. Then it occurred to me that there is no need to invoke the product rule and you do not need to determine the value of y in order to solve the problem.
To begin with you know dx/dt = 1.6 m/s. Next you have x + 4 = 12 => x = 8. From the chain rule, dy/dt = dy/dx · dx/dt. From the proportion 2/x = y/12 you can find dy/dx directly dy/dx = - 24/x^2. Therefore dy/dt = (-24/8^2)·(1.6 m/s) = -0.6 m/s ◼
thank youuuuuuuuuuuu
You're welcome!
what would you do for this problem in the problem below? i tried the method shown in your video but the question is not the same yours asks for length and the one i am trying to solve asks for height:
A spotlight on the ground shines on a wall 17m away. A person of height 2 m walks toward the wall on a direct
path between the spotlight and the wall at a rate of m/s. How fast is the height of the shadow on the wall
changing when the person is 6m from the wall?
Well, first we need to know the rate the person is going you only gave a rate of m/s not an actual numerical value
its well past my semester now, so there is no point in my trying to look up the question again.
I'm pretty sure he does solve for height here, buddy. Sorry your semester's come and gone. I hope you did well.
Merci beaucoup
When you have the same problem for homework 😏
ur a hero btw
would the ratio not be x and 12-x?
peteuuu fhuck off
A mercury light hangs 12 ft above the island at the center of Ayala Avenue whish is 24 ft wide. A cigarette vendor 5ft tall walks along the curb of the street at a speed of 420 fpm. how fast is the shadow lengthening when it is 16 ft up the street
need helpsir
Why can't my textbook make it this easy.
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I love you