Ynvisible Electrochromic Displays Ultra Low Power...PT1

I wanted to save power over LED displays and came across ynvisible' s line of electrochromic displays, these are not your off the shelf displays as there currently made to order but I have suggested to them that maybe they should create some standard displays and sell them as a line, this way people can get to use them without needing thousands to get a good price.
They use perhaps 1 microwatt per cm2 compared to 400mW for LED,
They kindly sent me a kit to play with so here is the initial look, testing with their provided modules, driver boards and code, in the next video I will demonstrate how easy they are to interface using a standard Arduino Uno.
More info here:- www.ynvisible.com/
Code and libraries i used are here:- www.ynvisible.com/getting-sta...

[@ynvisible]

Thanks for sharing this great video! We're glad that you appreciate our displays and their features.

[@leehewitt9559]

Awesome 👌👌👌

[@pecilijevelicanstveni4973]

Great video! Thank you! I always learn something new from you.
If you allow me a small correction: you said that the units are "microjoules" but they are actually "millijoules" ([mJ] or 10-3[J], just like "milliamperes" or [mA]. I'm sure it's an accidental mistake (Greek letter "μ", than it will be [μJ] or 10-6[J]).

[@TheBreadboardca]

I do understand the different units of measure for sure :), that does not mean I may have made a typo during post edit, what I can confirm is that the display consumes a maximum of 0,28µW per cm2 segment area, micro watts not milliwatts, If memory serves me correctly that would also mean 0.28µJ (1Watt = 1 joule second)

[@TheBreadboardca]

The site (ynvisible) seems to have so mixed use of units or im not reading it right :) ,
when it shows calculations it refers to 0.28µW/cm2 (Static display with refresh) but in other areas like here www.ynvisible.com/products/segment-display#Energy it ends up with a mJ figure. but in their example 0.1cm2 segment size * 21 segments = 2.1cm2, and lets say we switch every 60 seconds so 1440 per day, using this calc from same page P = 0,28 + 0,01 × n µW/cm2 we would end up with 0.28µW + 0.01 * 1440 = 14.68µW/cm2 so * 2.1 = 30.82µW so were still talking µJ here unless im completly missing something, ill reach out to ynvisible for clarification

[@pecilijevelicanstveni4973]

@@TheBreadboardca OK! Everything is fine! I totally agree. I just wanted to point out an accidental mistake in reading the units. Nothing else :-).