Totally Bounded

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  • čas přidán 20. 08. 2024
  • In this video, we define total boundedness, which is a beautiful concept from topology, and we show that any compact space must be totally bounded. Enjoy!
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Komentáře • 31

  • @NH-zh8mp
    @NH-zh8mp Před 3 lety +4

    Dr Peyam works very hard and energetically on the field of functional analysis and topology

  • @iabervon
    @iabervon Před 3 lety +3

    The thing that's hard to think about is how a set can be bounded, but not totally bounded. (That is, why we need this.) I think you need a metric space with infinite area a finite distance from a point, which is weird, but I can't think of any reason it couldn't happen.

  • @subhrajitdasgupta3868
    @subhrajitdasgupta3868 Před 3 lety +1

    I really like how much effort you put into a video to make the students understand the concepts lucidly! Thanks a lot professor!

  • @umerfarooq4831
    @umerfarooq4831 Před 3 lety +1

    Interesting...the colorful thumbnail was mesmerizing

  • @geraltofrivia9424
    @geraltofrivia9424 Před rokem

    Great content, as usual

  • @ThePhysicsMathsWizard
    @ThePhysicsMathsWizard Před 3 lety +1

    Well explained, good, keep it up.

  • @rohanvermaiitbhu918
    @rohanvermaiitbhu918 Před 3 lety +2

    Really nice sir, make video on JEE ADVANCED asked question ,love from india

  • @tripasect1271
    @tripasect1271 Před 2 lety

    You're a good person Dr Peyam.

  • @devaiyer9040
    @devaiyer9040 Před 2 lety

    The way you pronounce Borel is just- 🥵👌👌👌

  • @rohanvermaiitbhu918
    @rohanvermaiitbhu918 Před 3 lety +1

    Sir please make video PRINCIPLE OF INCLUSION AND EXCLUSION

  • @dgrandlapinblanc
    @dgrandlapinblanc Před 2 lety

    Ok. Strange thing this notion of countable and uncountable. Thanks.

  • @honghong324nt5
    @honghong324nt5 Před 4 lety +1

    Could I have prove the fact that F is dense in E by showing that the closure of F is E?

  • @wenanyaugustine3311
    @wenanyaugustine3311 Před 6 měsíci +1

    Who 😢are you ? You make it look so easy 😢. OMG wish you were my professor 😮. Thanks I found this 😊

  • @riadsouissi
    @riadsouissi Před 3 lety +1

    Dr. Peyam, can you please suggest non trivial counter examples (bounded but not totally bounded, etc) ?

    • @drpeyam
      @drpeyam  Před 3 lety +1

      I don’t think such an example exists. If a set is bounded you can cover it with a large ball, hence finitely many balls of any radius you want

    • @riadsouissi
      @riadsouissi Před 3 lety

      @@drpeyam Makes sense. Then totally bounded but not bounded ? I cannot think of one. If no such example exists, there both would be equivalent, wouldn't they ?

    • @akrishna1729
      @akrishna1729 Před 7 měsíci

      A counterexample for bounded but not totally bounded should be the unit ball in an infinite-dimensional Banach space; take l^{\infty} for instance.

  • @masoudsakha
    @masoudsakha Před rokem

    Is there any set that is bounded but not totally bounded?

  • @gowharnazir3540
    @gowharnazir3540 Před 3 lety

    Dr peyam looks like actor Mark Ruffalo

  • @Happy_Abe
    @Happy_Abe Před 3 lety

    Why is F countable if the radius can take on any real valued number?

    • @drpeyam
      @drpeyam  Před 3 lety +1

      No? The radii of F are rational numbers, of the form 1/n

    • @Happy_Abe
      @Happy_Abe Před 3 lety

      @@drpeyam oh, I was under the impression that radii can be any real valued number. Seemed that way in the beginning by r>0

    • @drpeyam
      @drpeyam  Před 3 lety

      At the beginning yes, but at the end I talk about something different

    • @Happy_Abe
      @Happy_Abe Před 3 lety

      @@drpeyam thank you, sorry for misunderstanding

  • @victormd1100
    @victormd1100 Před 3 lety

    At 13:31, we know that F is dense but how do we know if it is a subset of E? It seems like the centers of the balls could all be outside of the set ( or at least most of them be ). We need F to be a dense subset for E to be separable, but we only seem to have density guaranteed.

    • @geraltofrivia9424
      @geraltofrivia9424 Před rokem

      Dude... This is literally a set of points which are all in F. If this is not a subset of E, I don't know what is.

  • @jeemain9071
    @jeemain9071 Před 3 lety +1

    Why this👇👇👇👇 comment is 4 months old