ULN2803 Low-Side Drivers and UDN2983 High-Side Drivers

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  • čas přidán 12. 07. 2024
  • The ULN280x Low-Side drivers and UDN298x High-Side drivers are useful for many applications.
    Support Roger on Patreon: / kainkalabs
    Roger explains some features of the chips and its limitations.
    Datasheet ULN280x: kainkalabs.com/upload/?f=156c...
    Datasheet UDN298x: kainkalabs.com/upload/?f=156c...
    Shop: www.ak-modul-bus.de/stat/labor...
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Komentáře • 27

  • @ninjaturtle7281
    @ninjaturtle7281 Před rokem +3

    Bless the boomers that share their knowledge on this kind of youtube channels.

  • @blackbox330
    @blackbox330 Před 7 měsíci +1

    Sir, The best video on ULN family. Thanks

  • @planker
    @planker Před rokem

    Cool, I'm setting up for VFD's and It looks like high side drivers are on the shopping list. Well done

  • @idallkeybachdar7463
    @idallkeybachdar7463 Před 7 lety +4

    this is great video..thank u

  • @omaral-halabiah2851
    @omaral-halabiah2851 Před 4 lety +1

    thank you sir

  • @kausalyabaissonale4804
    @kausalyabaissonale4804 Před 8 lety +1

    It was very good !!!

  • @emremutlu44
    @emremutlu44 Před 5 lety +1

    I got some of these ULN2803 ICs but the *fake* ones or which is called as Potato ICs in here :) they are not capable of sinking all the current down (like 20-30mA @ 5V) while sourcing the base with furious 5V GPIO. That was a total surprise. I have ordered it as smd, from some another source and that one works like it is expected. Characteristics are just like a single dalington npn for a pulse like 10us @ 5V.

  • @SubwayJack919
    @SubwayJack919 Před 2 lety

    Good video

  • @RealDevastatia
    @RealDevastatia Před 10 měsíci

    Which chip to use depends on whether your multi-segment display device is common-cathode or common-anode.

  • @rogerwalter2500
    @rogerwalter2500 Před 11 měsíci

    I'm using uln2803 driving relays using 3.3V input from a PIR motion sensor

  • @aritrasinghachowdhury3227

    Good morning, Very useful video. But printed materials can not be seen clearly. They need to be enlarged. Thanks.

  • @dvignesh5
    @dvignesh5 Před 6 lety

    Im currently using Irf3205 n-channel mosfet and ir2110 MOSFET driver for Bldc Motor control using Arduino. MOSFET is not completely turning on by the MOSFET driver IC ?

    • @KainkaLabs
      @KainkaLabs  Před 6 lety +1

      You should describe your setuup a bit more detailed.
      The ULN/UDN Driver-chips are not well suited as gate-drivers for power-MOSFETs (too slow, no push-pull output).
      Use special push-pull MOSFET-driver ICs for switching power MOSFET.

  • @althuelectronics5158
    @althuelectronics5158 Před 5 lety +1

    wery naise your clase ant wery slow your teacghing am stading this metheed
    am wery happy to waching this video
    (god +you ) thanks teacher

  • @Dc_tech386
    @Dc_tech386 Před 4 lety

    If the gate drivers turn off with the mosfet turn off aswell

    • @KainkaLabs
      @KainkaLabs  Před 4 lety

      Is that a question or a statement? The ULN and UDN drivers are bipolar and not MOSFET (and not intended as MOSFET gate-drivers)

  • @Enigma758
    @Enigma758 Před 3 měsíci

    3:42, current rises, but I don't believe it rises linearly.

    • @KainkaLabs
      @KainkaLabs  Před 3 měsíci

      That´s basic electronics: Put a constant voltage at an inductor and current rises linearly (until either ohmic resistance or saturation of the ferrite material sets in)

    • @Enigma758
      @Enigma758 Před 3 měsíci

      @@KainkaLabs But I=V/R(1-e^(1-tR/L)), so with V being constant, I believe it's an exponential rise.

    • @KainkaLabs
      @KainkaLabs  Před 3 měsíci

      read carefully what I wrote, also that in the brackets. Look up your textbook or wikipedia about inductors and capacitors. Capacitors are the inverse elements to inductors. Exchange I and V and you understand the other part. With a capacitor, charge it with a constant current and you get a linearly rising voltage --> with an inductor, put a constant voltage to it´and you get a linearly rising current (until........... see above)! Case closed.

    • @Enigma758
      @Enigma758 Před 3 měsíci

      @@KainkaLabs We are both correct in a sense. The current in an ideal inductor in isolation will rise linearly when charged with a constant voltage. However, ideal inductors don't actually exist. In that case there is always some resistance, and when resistance is present, the current in the inductor will rise exponentially as per the formula I provided. I hope we can agree on that.

    • @Enigma758
      @Enigma758 Před 3 měsíci

      Yes, it is basic electronics. I recommend Michel van Biezen's video "Electrical Engineering: Ch 7: Inductors (7 of 24) DC Current Through an Inductor" where he explains the exponential behavior of current through an inductor with constant voltage and takes into consideration the resistance with time constant L/R. Seems like you were unaware of that.