Extreme Sudoku: Sue-De-Coq And Empty Rectangles
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- čas přidán 13. 02. 2019
- Simon tackles a monstrous puzzle from a viewer. This needs several advanced techniques (hence the length of the video) including XY Chains, Empty Rectangles and the rarely seen Sue-De-Coq.
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This was absolutely brilliant mate. Makes me realize there's a level of Sudoku solving I'll never reach. Anywho well done!
I have to say that feel a lot better about my own struggles with Sudoku after watching you struggle with this one Simon. Thanks for all of the great videos and help with Sudoku.
You're absolutely amazing Simon! I picked up two new techniques just by watching you solve this one. =)
Wow... Thanks for working through this. I can follow along, and can maybe hope to someday spot the logical steps that you find. Very much enjoy your posts.
Very enlightening. I'm learning more here than any other place. Thanks
Thanks Simon for doing this puzzle
At the end of initial stage of using regular sudoku moves I found column 1 interesting because only two cells were left. One of these, C1R5, was yelling out to be an 8 because, if you adapt Mark's method, you will readily see that an 8 there creates a lot of havoc elsewhere. The 8 turned out to be correct and the rest of the puzzle crumbled. Happy Valentine's Day Mark, your approached led me to the 8 that cracked the cryptic.
Seems to me that the harder the puzzle, the more poignant the vulnerable cell, in this case C1R5.
I then sat back and enjoyed Simon's Solve, again a very humbling experience. Well done, Simon and Happy Valentine's Day to you too!
Now that one was a challenge! Thanks for solving it and posting it, even if it did take you quite some time to finish!
Wow! Great solve.
Very nice. The tough ones are the best to watch
Incredible... I was palm to forehead when you didn't lock in the 3-7, 4-8 pairs in column 6 at the outset (you had a 5-8 in box 8 instead) and then mistrusted the correct notation due to the original omission.
Much better now that you can differentiate notation in the current software!
Your ability to key into the best weak spots & see the needed strategy is awesome.
I have no trouble following your logic... I just can't find the points of attack.
This solve was especially impressive.
Love these videos. I get stuck with basic Sudoku but I’ll learn. Thanks!
I am very new and unexperienced in solving hard sudokus. I started learning on this channel about 2 weeks ago and with this tecknique of snyder pencil marking I honestly couldn't solve a single puzzle. Then I shifted to just stupidly filling in every possible pencil mark and working from there and since then I solved 8 out of 9. And even this one was relatively easy because it was not so hard to spot numbers that could be eliminated from rows, columns and squares. It still took me a bit longer than him but given I have no practice I consider this one of the easier "hard puzzles"
In column 1, putting either 6 or 8, all other numbers can be checked. If row 2 is 6, you get all numbers correct.
Excellent, I learned 3 techniques.
I had never heard of Sue-de-coq until a couple of days ago, now I see them everywhere lol
As a pencil-and-paper solver, I circle all "Bi-Value Cells" while still using Snyder. It obviously gets around wondering later "Is that 3 and 7 in the cell indicating ONLY 3 or 7 can go there? " Too bad the software doesn't seem to allow that indication. Nice solve! I doubt I ever would have got it, but I practice every day. The LA Times "diabolical" is usually not all that hard - a finned X-wing and a Turbot Fish or something and boom, that's it!
He ... I'm no beginner at Sudoku, but chains of THIS length is a bit (way!) too steep for me at this point!
Hat's off! ;O)
If you want to understand chains I highly recommend Sodoku Swami's videos.
yea, tooooo long chain.
Great video!! At 26:20, you could have eliminated 2 and 3 from H4 because of the single solution rule. Also, the 8 on C5 could be eliminated early on with a finned skyscraper in columns 6 and 9.
7:20 I'm curious to see if you spot the Y-wing of R7C6 (37), R9C4 (23 you just penciled in), and R9C3. As far as I could tell, it was useless.
8:40 You found it. Also, I reversed the order of the 237 triple and 89 pair: found the triple first, to place the pair.
I know I've come late to this one, but did anybody else solve this without reference to NY times logic, y-quadruples, empty rectangles or long chains? Well I did, and I don't think I made any assumptions as Simon inadvertantly did on that alleged 3-7 pair in the bottom middle box.
Looking back, I think I did more complete Snyder notation and the odd trick of my own on skew triples within a box. I soon had more rows and columns with 6 or 7 digits in (including pairs) and my longest chain was a 3.
This is the first puzzle I've finished significantly quicker than Simon did. Not to knock you, Simon - you often crack puzzles I get absolutely nowhere with.
While it took 62 minutes to solve this puzzle, I used all the basic techniques, including your Sneider technique with swordfish.
19:45 I think i will never get into multi number chains, just because it seems so arbitrary where to start or what to look for. might as well guess with pencil at this point.
I fear anything at a difficulty of 28 or above. This was a 75! #FEAR.
Fear starts at 300 (km/h).
Instead of doing the open rectangle on 5s in box 8, doing it on 7s in box 9 gives even more quickly the same result, starting with proofing that r3c4 = 3. However, the initial Sue the Coq and other rectangle I did not spot so easily....
Could you please add the link to this puzzle for us to try? Thanks!
How does a bent quadruple work? Sometimes you do advanced logic methods, but I don't understand when they do/don't work
What is the system you use above the puzzle
Very helpful walk through! Just wondering how did you highlight/color the cells in Duncan's Sudoku Solver?
I didn't! I have to add the highlighting afterwards using video editing software on the raw webcam footage!!! :)
@@CrackingTheCryptic Ahhhh, i thought it was a premium function or something. thanks for replying. I am really learning a lot. thank you
Just wondering why you didn't complete the Snyder notation for at least the 5s and the 4s. I'm guessing that things are different when you're recording and attempting a fast solve.
I've found recently I've struggled on some of the very difficult puzzles to keep track of the "normal" pencil marks as well as the Snyder pencil-marks. This is easy on paper because I can use a different colour or position of the pencil-mark but (at least I find it) tricky using the computer - which only allows me to make one form. I might check whether Hodoku allows me to shade a cell a different colour if it eg contains a pair! For this puzzle, I wasn't seeing much at all by way of Snyder method but I was seeing loads of early pairs... just felt better to switch!
I found that at enjoysudoku.com I can use coloring cells pretty easily, and use coloring again to highlight possibilities . If you can find something similar it might work.
This guy plays 4D sudoku
What software do you use for solving sudoku?
it looks like DUNCAN'S SUDOKU SOLVER. (free download)
Sudokuwiki.org is probably the best solver I know.
It is not possible for an usual human to find the chain at 20:03 )))
At 09:32, consider a 4 in row 5 column 7, which implies a 4 in row 3 column 4. But the former implies a 7 in row 7 column 7 and the latter implies a 3 in row 1 column 6. The two taken together rule out all the possible assignments for row 7 column 6. So, a 4 in row 5 column 7 must be ruled out. By applying (mostly) elementary rules, eliminate the 9 in row 7 column 8 and the 5 in row 1 column 3.
Next, consider a 6 in row 2 column 8, which implies a 6 in row 4 column 1. The former implies a 9 in row 1 column 8, the latter an 8 in row 5 column 3. But these rule out the remaining two possibilities for row 1 column 3. So, a 6 in row 2 column 8 must be ruled out. The solution now follows from elementary rules.
In each case, the pattern consists of a pair of cells in a column or row that contain the only two possibilities for a "6" or "4", respectively (I call this configuration a "two-way", you call it a pair), coupled with a further cell in a shared row or column which contains a possibility for the "number", a sort of partial X-wing pattern. Is there a name for this pattern?
I realize that there is a way of looking at this solve that is a bit closer to the way Simon usually talks it through. Consider the cell in row 3 column 7. If it is a "4", then the "4" in row 5 column 7 is ruled out. But if the cell dows not have a "4", then row 3 column 4 must have a "4", which implies that row 1 column 6 has a "3", row 7 column 6 has a "7", and row 5 column 7 is forced to have a "7", eliminating the "4". So that, in any case, there could not be a "4" in row 5 column 7.
It is possible to solve the puzzle from here using standard rules and elementary techniques.
Yes, it is, but it is very difficult to find. How did you spot it????
To anyone that is trying to learn how to start... 1-9 and mark only where 2 of those numbers can be.
@ 19:41 you have reached a contradiction which resolves row 9 column 3 as 7 - isn't it the case?
Not sure it's a contradiction. The interaction of the chain starting in r9c3 forces the 2/3 pair in row 9, which in turn rules out the 2 from r9c3... this then forces that cell to be a 7.
@@CrackingTheCryptic if r9c3 is 2 then you get r5c2 as 7. in the meanwhile it is also clear that row 9 c2 is also 7. hence it is a contradiction. that means r9c3 cant be 2 but has to be 7.
Yep, I see what you mean now. I think we're actually saying the same thing, just in different ways :)
My Sudoku program says there are multiple solutions to this puzzle/
Stop apologizing! I stare at the screen a lot longer than you do! LOL
Most of us do. Occasionally one can spot a naked single saying "hello" while Simon is still intensively skimming the small ads for more geometrically perverted vectors.
well I never
It's a good thing they moved on from this software. It's awful for this puzzle.
You are borrowing