Binomial Probability Distribution
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- čas přidán 27. 09. 2020
- The video covers the Binomial Probability Distribution with respect to the formula, properties and worked examples.
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Probability and Probability Distribution: • Probability and Probab...
Thanks sir, much appreciated from south Africa here.
This is really good
Explained in such the simplest way 🙂🙂
WELL DONE!
Thanks a lots for very good explanation 😊
your lessons are just incredible. thank you so much for sharing with us
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Thanks so much.
Hello good day. Why does in example 1 letter C you included Probability of 0? We are talking about of having a head right?
In the example 2 sir how did you get the success(p) and failure (q).
Thank you for this wonderful tutorial, well explained 😍
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In example 1 how did you got the 32 and 64?
This is well explained 🥰🥰
Thank you so much!
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Thanks 😊 for sharing
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Endeavour to like and share the video to others.
But a good concept
Thank you so much sir.
This helped me alot
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We are glad you enjoyed the video.
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Pls how did you get 1/2 in the first example
Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.
thanks sir
What do you mean by 6c4 is 15 I'm not getting it clearly
Sir please how did you get the probability of success as p and q as a failure from the given question
You may need to watch the introductory videos on probability for clear understanding of binomial probability distribution.
See the link of the playlist containing all the videos on Probability and Probability Distribution: czcams.com/play/PLYwM9CzPztOkBlVGFRjyxyZLu4UcI-moj.html
Sir how are we getting 1/2 for p and q?
On atmost question.. it is possible to use combination of 2 itself and only? Excluding 0?
We don't actually know the particular question you are referring to. Meanwhile, any other way will give you the same answer.
how did you get 1/2??
Pls the final answer how do we do it
I have a question for you 🙋♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.
probability and statsics
Probability and statistics, at the University of Zambia Mat2901/2602
Also data management course
Thank You Sir
You are welcome.
Pls how did you get p=1/2 and q=1/2
God bless you
Amen
How you came out with 1 half and the rest
Have gotten it
How did you derive 6 combination 5 to be 6?
Thank you for watching.
We appreciate your feedback. You can input 6C5 in your calculator.
Warm regards.
Sir pls how did you get you success (p) and failure (q) in question 2&3 its confusing
He got 1/2 from the sides of a coin (head and tail)
I don't know how get the 0.2 but u are doing very well
q is obtained by the equation (1-p), so p is 0.8 hence (1-0.8)=0.2
@@shereenmmadi8385 thank you
How did you get 1/4 and 3/4 in the third question
Thank you for your feedback.
There are 4 options for each multiple choice question in which only one option is correct.
Probability of answering each question correctly is ¼ which is equal to p. Probability of answering it wrongly is ¾ which is q. You may need to watch the video on basic problem on probability for further clarification.
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Thanks bro
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In the examole 2, 2/3 to the third is 2/27, not 8/27. Reputability check. Unless my calc has got an internal issue.
(2/3)³ = 2³/3³ = 8/27 sir.
Change your calculator or check your input.
Thanks
You are welcome
How did you get P1/2??
Hi
Remember coin has two sides ,, that means head is one side and other side there's a tail ..therefore if we toss it once one may get head or tail which is 1/2
❤❤❤❤❤
How did u get failure 0.2
P(success) = 0.8
P(failure) = 1- 0.8 = 0.2
Success and failure are complementary events and their individual probability sum up to 1.
Moral is good
Pls how is 6c4 =15
3:49 how do u get 1/2
A coin has two faces, head(H) and tail(T).
p = Pr(H) = ½
q = Pr(T) = ½
Please watch the video below for further clarification.
czcams.com/video/Z49J9lLCtm4/video.html
Thanks sir
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recheck Q1
Thanks so much
You're welcome!
You're welcome!
How is 6c4 15
i use a casio fx-82za plus calculator so for me is just put in 6-shift (the devide button which is your C) 4 that will give you 15... hope this helps XD
the example 2 / b id didn't understand very well why you didnt inclidees even the probabibilty p(x=6) when calculating p(x>,=4 )?
Thank you for your feedback.
On your question, we didn't include p(x=6) because there is no need for it since the number of trials in the question is 5 (n = 5). You may need to watch the video again for further clarification.
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@@OninabResources thank you
We have seen what is p as probability of success but we don't know how we seek a number P
Thank you for your feedback.
The value of p is either given in the question or use the information in the question to calculate it.
Pls how can I get the failure
You just have to think of a number that will make the number of success whole or complete.
For example, u were given a success or (p) of 2/5 then think of a number that will make 2 a 5 and that is 3. So, your failure or (q) is 3/5
how is in (b) 6*1/(1/32) is equal to 6/64? it is wrong
Thank you for your feedback.
You may need to watch the video again. What we have in b is 6× ¹/32 × ½ which gives 6/64.
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Okay of this one
p: it rains
q: there will be flood
Sorry at least 5 it supposed to be 0,1,2,3,4,5
Consult with your English teacher for more clarification on at least and at most. Thank you.
At least means the smallest figure should be 5 which implies that it's only 5 and 6.
This is for at most 5 not at least 5
John M Sesay
Thank you so much for your feedback.
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Yeah
Good but too long solutions ..
oh i got it now
recheck Q1