Finding The Probability of a Binomial Distribution Plus Mean & Standard Deviation
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- čas přidán 30. 06. 2024
- This Statistics video tutorial explains how to find the probability of a binomial distribution as well as calculating the mean and standard deviation. You need to know how to use the combination formula in order to solve the example problems presented in this video.
Introduction to Probability:
• Introduction to Probab...
Probability Formulas:
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Probability Explained:
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Probability With Geometry:
• Probability With Geome...
Probability of Complementary Events:
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Conditional Probability:
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Independent and Dependent Events:
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Probability of Mutual Exclusive Events:
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Multiplication and Addition Rule:
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Compound Probability:
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Expected Value:
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Probability Tree Diagrams:
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Bayes Theorem:
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Probability - Binomial Distribution:
• Finding The Probabilit...
Probability - Geometric Distribution:
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Probability - Poisson Distribution:
• Introduction to Poisso...
Continuous Probability Distributions:
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Probability Density Functions:
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Probability - Normal Distributions (Calculus):
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Probability - The Law of Large Numbers:
• Law of Large Numbers
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14:00 He should consider x= 0 as that is also possible, which if we employ the formula, would be 0.75^30 which would be an extremely small number. It would logically make sense, usually we would have a number closer to 25% taking algebra, the chances that 0% take it from a samoke is highly unlikely BUT possible....
Less than 5 STUDENTS...I don't think zero needs to be included since we're talking about people...my thoughts tho....
No it shouldn't as if it should then my calculator would give me diff answers
Yes, correct.
Less than five simply would mean we have 0 or very negligible chances of having 0 😱
You have a point.
P(0) =~ 0.000178... in this case.
P(1) =~ 0.00178... which is an interesting correlation.
This is because,
P(1) = (30 * 0.25) * 0.75^29
P(1) = (7.5) * 0.75^29
P(1) = (10 * 0.75) * 0.75^29
P(1) = 10 * 0.75^1 * 0.75^29
P(1) = 10 * 0.75^(1+29)
P(1) = 10 * 0.75^30
And P(0) = 0.75^30
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Amazing learn this more than what I’ve learnt in lecture! Could you please do a video on approximating binomial probability using normal distribution as well, with the use of continuity correction? It would help me a lot! All in all, a big fan of yours!
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for Problem 3 b) we need to also include P(0) . since there could be 0 students taking algebra which is also less than 5.
Same doubt for me too...p(0) should be added right
I think since the question says 25% are taking algebra there is at least 1 student have taking algebra out of 30.
@@yarachesu2604yes so there is no need of p(0)
@@yarachesu2604 That is not a valid point since we do not know exact total no. of students in the high school. Say that there are 200 students in the high school XYZ. Then total no.of students taking algebra will be 50(25%). So, other 150 will not be taking algebra. So, since the 30 students are chosen randomly, there is at least a small chance that all 30 are selected from that remaining 150. So, there will be a small probability for p(0) which is actually 0.018%
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I think had to consider P(0) in the last question when we calculate P (X
Yes that is my thought
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Q b infact
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Hi, Please kindly explain question 3(b)! I thought there is a possibility of picking none on those doing algebra on less than 5 students, making P(0)+P(1)+P(2)+(P3)+P(4)= P(X
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Siddhartha, Jz posted about how to find PROBABILITY using BINOMIAL DISTRIBUTION....
I hope it's helpful..... Would love to hear some feed back too
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Why we didn't consider P(0) in the last question when we calculate P (X
Yess I am wondering
Just a little mistake.
I was gonna comment that. Then i found your comment. I think it's a mistake & it will be clear if he pins a comment or say it in the description.
was wondering the same thing. Glad I saw this comment. P(0) needs to be calculated as well.
Becoj in p (0) there n c x is coming 0 ..when we solve this here 0 will come so no need..
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Jz posted about how to find PROBABILITY using BINOMIAL DISTRIBUTION....
I hope it's helpful..... Would love to hear some feed back too
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