Digital SAT Prep: Easy Desmos Hack for the Hardest Math Problems!

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  • čas přidán 5. 09. 2023
  • Do you want to know the BEST trick for tackling the hardest digital SAT math questions on BlueBook Module 2? Using the Desmos calculator is the key to getting the toughest SAT math questions correct quickly and easily. I walk you through and explain four different math problems from BlueBook Practice Test 4. So you can be prepared for the October digital SAT or the PSAT in 2023 and beyond! Get your digital SAT goal score with these few simple adjustments in your SAT math strategies. I'd recommend you watch my other digital SAT study guide videos from this past year as well to improve your SAT score :) Learn how to score 100 points higher, 200 points higher, or even perfect on the SAT math and get into your dream college!
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Komentáře • 76

  • @chadchampion7985
    @chadchampion7985 Před 3 měsíci +66

    Here's an alternative solution to the last problem:
    a+b+c is f(1). Since the parabola is open upwards, (9, -14) is the minimum value of f(x). Thus, f(1) (whatever it is) must be greater than 14 i.e. a+b+c > -14
    Only choice d fulfills this criteria.

    • @derinwithaq5811
      @derinwithaq5811 Před měsícem +11

      that's actually very helpful, and much better than her very not rigorous "well it's probably mostly positive" explanation

    • @abdullah_abisola
      @abdullah_abisola Před měsícem +1

      That is mad
      I am blown away by this method
      I happened to try this on my own and landed at College Board's explanation but I also thought of this
      Cause Ik that 2a = 2nd diff 3a +b = 1st diff and a + b + c = 1st Term
      Thanks
      Alot

    • @psych0-shorts
      @psych0-shorts Před měsícem +3

      Dude I was trying to look for a proof that a+b+c = f(1) for like 10 mins. Then I just plugged in a 1… I felt so stupid bro LMFAO

    • @bexqmish3699
      @bexqmish3699 Před měsícem +2

      Took me a sec to understand it, but that's really clever

    • @disdot7465
      @disdot7465 Před měsícem

      @@bexqmish3699 bro I don't get it can u help

  • @savvas637
    @savvas637 Před 8 měsíci +120

    Another very easy solution for question 2 I think would be to know that the Product = c / a so because c = ab and a = 57 , c/a = ab/57 = kab . The ab’s cancel out and we’re left with 1/57 = k

    • @harshithgogineni7093
      @harshithgogineni7093 Před 7 měsíci +3

      would've never thought of this. wow!

    • @armaan7381
      @armaan7381 Před 6 měsíci +3

      vietta's formula

    • @emmazhang2418
      @emmazhang2418 Před měsícem +1

      why is a 57?

    • @savvas637
      @savvas637 Před měsícem +1

      @@emmazhang2418Because the formula for a quadratic equation is: ax^2 + bx +c = 0 so by comparing this to the equation given in the question a is 57

    • @vivianlee2509
      @vivianlee2509 Před 3 dny +1

      how do you know that c=ab ?

  • @adityabhambhani207
    @adityabhambhani207 Před 6 měsíci +4

    This right here is a goldmine!! Thanksss! rlly helpful!!

  • @meadowxchannel
    @meadowxchannel Před 3 měsíci +2

    This was so helpful, thanks so much!

  • @letsgotousa679
    @letsgotousa679 Před 8 měsíci +7

    Please make a video on "hard reading questions" on module 2

  • @shehlabtskz
    @shehlabtskz Před 8 měsíci

    Thank you so much teacher it was so helpful to me❤. We are waiting for the part 2

  • @symply..rachell
    @symply..rachell Před 7 měsíci +1

    Thank u sooooo much ...u hv no idea how this really helped..

  • @mathwithmelissa617
    @mathwithmelissa617 Před 5 měsíci

    Great tips! Thanks for sharing

  • @user-qw1do9qt4n
    @user-qw1do9qt4n Před 4 měsíci

    for the last question would it also work if I add the minimum plus the x intercept plus the y intercept? It also gives 12 but I don't know if that is a correct way to solve.

  • @nahomdesta1237
    @nahomdesta1237 Před 6 měsíci +3

    Thank you for what you do to help us, Laura. I've been watching your videos for a while now and I really appreciate what you do.
    But, I have a question on the second question. Why exactly did we set a and b as 1?

    • @StrategicTestPrep
      @StrategicTestPrep  Před 6 měsíci +2

      Great question - They’re just easier numbers to work with! You could set a and b as anything. And thank you I appreciate you watching 😊

  • @gregnixon1296
    @gregnixon1296 Před 5 měsíci +4

    Becoming a calculator jockey is an under-rated strategy. A TI-84 Plus CE has functions in the APPS menu that bring high scores well within reach. You don’t need to be a math guru, just understand how to use the allowed tools.

  • @ucheshub23
    @ucheshub23 Před 8 měsíci +7

    You saved my Nigerian Life😩. I could kiss you. Thank you so much Ma'am. ♥️♥️✌️✌️

    • @meadowxchannel
      @meadowxchannel Před 3 měsíci

      Shes about to save mine too

    • @stays4514
      @stays4514 Před 2 měsíci +1

      ​@@meadowxchannelyou're a Nigerian taking the sat this Saturday??

    • @NamGil-ed5bf
      @NamGil-ed5bf Před 2 měsíci

      @@stays4514yes

  • @fredabila
    @fredabila Před 7 měsíci +4

    Your explanation for using the calculator was easy to comprehend but the solution to the questions were quite difficult to understand

  • @dougd120
    @dougd120 Před 8 měsíci

    Another was the day of things.

  • @montysark
    @montysark Před 4 měsíci +2

    If you know a little bit of calculus, you don't even need desmos.
    y = -1.5
    y = x^2 + 8x + a
    you can find the derivative of the second equation then set that equal to 0. then solve for x and that will give you the critical point.
    then insert that solution into x^2 + 8x + a = -1.5
    then solve for a . and you've got it.

    • @StrategicTestPrep
      @StrategicTestPrep  Před 4 měsíci

      Love this!! Very cool

    • @rotimifr
      @rotimifr Před 2 měsíci

      yes. well explained really helpful if you know how to get the derivative.

  • @euniceolaoye2146
    @euniceolaoye2146 Před 6 měsíci

    Hey, i have never used the desmos and my exam is on saturday. Do you advise that i should just stick with using my calculator or get familiar with the desmos?

    • @allisonturner5571
      @allisonturner5571 Před měsícem

      Hi random person, how did it end up going?
      In the same situation I'm wondering if the best is to use desmos as a last resort if I have no idea what to do.

  • @parrotsarecolorful01434
    @parrotsarecolorful01434 Před 8 měsíci +2

    oh my god the lighting how many lights do you have haha
    nevertheless, you always drop banger videos.

  • @Dawodu_Gbolahan_David
    @Dawodu_Gbolahan_David Před 8 měsíci

    Please I want to buy your course but is only English I want to buy because I can't afford both with the price given but I really want to buy the English

  • @mollygarnett5685
    @mollygarnett5685 Před 8 měsíci

    Why is it a(x-9) for Practice 4, question 98?

    • @rodrigue9228
      @rodrigue9228 Před 6 měsíci

      This is the canonic form of the equation : y = a(x-A)^2+B where A and B are the x and y coordinate of the vertex.

  • @lunalinedigital_1733
    @lunalinedigital_1733 Před 2 měsíci

    8:36 I don't get why D is the answer. What if c was less than a and b, wouldn't that make a + b + c answer as positive?

    • @YTAlyx
      @YTAlyx Před 2 měsíci

      Her answer is right, but the method is not. Instead what you can do is write the equation in the form of a(x+b/2a)^2 + c - a*(b/2a)^2 (Squared form to find the vertex)
      and you have the values where b/2a=-9
      And c - a*(b/2a)^2 = -14
      Now find b and c in terms of a
      Substitute in a + b + c to get an equation in a
      You will get 64a-14 = ...
      To get a +ve value for "a". The ... (which is the answer) has to be lesser than 14, since they are all -ve values. Hence D is the answer

  • @bidhyanshu
    @bidhyanshu Před 8 měsíci +16

    I have my exams on Oct 7 🥹 And I am currently hitting only 640 in Maths and 630 in English .I need to improve at least 80 points each in the next 27 days 🙂 Totally scared

  • @psych0-shorts
    @psych0-shorts Před měsícem

    The first one isn’t that bad really. If it says that it only has one solution then it means that the lines only hit once. For that to happen y=-1.5 (the straight line) has to be just touching the bottom part of the parabola (height at vertex). We know that the vertex is x= -b/2a, and height y = f(-b/2a). From there its making the line’s height = to the vertex height.

  • @leonmaurice1746
    @leonmaurice1746 Před 3 měsíci

    I solved these problems like this:
    92) Use Discriminant D=0; b^2-4ac = 0. Solving for a gives a = 14.5
    95) Use x1*x2 = c/a = ab/57; k= 1/57.
    98) V(9/-14); f(x) = a(x-9)^2 - 14 = ax^2 - 18ax + 81a - 14; a+b+c = 64a - 14.
    Since the parabola touches the x-axis twice and yV = -14, the limit as n->∞ is ∞, and, thus, a>0, from which follows that 64a - 14 > -14. The solution, hence, must be -12.

    • @azretomarrisbay8925
      @azretomarrisbay8925 Před 2 měsíci

      Hi can i ask how did you get 64a-14?

    • @leonmaurice1746
      @leonmaurice1746 Před 2 měsíci

      @@azretomarrisbay8925 Admittedly, my notation was plain wrong there, sorry about that. I should have written a new equation after f(x) = ax^2 -18ax +81a -14. The polynomial equality theorem for polynomials says that if two polynomials are equal to each other for all x∈𝔻, that the coefficients cn of each degree n of x, where n∈ℕ0, have to be equal as well (you don't really need to know this theorem, it's intuitive that the coefficients must be equal). We know that f(x)=ax^2 + bx + c and we derived that f(x)=ax^2 -18ax + 81a - 14 using the vertex form. The vertex and standard form are equivalent, so that ax^2 + bx + c = ax^2 -18ax + 81a -14. Now apply the polynomial equality theorem, from which follows that a=a, b=18a, c=81a-14. It immediately follows that a+b+c= 64a -14.
      The parabola is open upwards (you realize this when visualizing the vertex below the x-axis and the fact the graph touches the x-axis twice, the limit was a mere notational formality), so a>0. Thus, 64a-14 can never be smaller than -14. We, hence, get (D) -12 as our only option.

    • @azretomarrisbay8925
      @azretomarrisbay8925 Před 2 měsíci

      @@leonmaurice1746 my bad, i missed the a+b+c part you wrote and thought u just got ax^2-18ax+81a-14=64a-14, now its clear thx for explanation🙏

    • @leonmaurice1746
      @leonmaurice1746 Před 2 měsíci

      @@azretomarrisbay8925 you're welcome (and were right though btw, I did have it like that before, I corrected it after you commented)

    • @dundundun2383
      @dundundun2383 Před 2 měsíci

      thank you for 98 because i also got 64a-14 but didnt know where to go from there

  • @McKylie151
    @McKylie151 Před 8 měsíci +2

    can we use Desmos during the exam?

  • @elcinseydayev4904
    @elcinseydayev4904 Před 8 měsíci +1

    why we give same number to a and b at question 95.They are actually not the same thing

    • @amena4887
      @amena4887 Před 6 měsíci

      i have the same question !! im so confused

  • @linhnhi4142
    @linhnhi4142 Před 8 měsíci

    but do the desmos on bluebook has a slider? i've done all of the practice tests but never notice there's a slider

    • @StrategicTestPrep
      @StrategicTestPrep  Před 8 měsíci

      There absolutely is a slider when you input a variable other than x or y

  • @orange_turtle3412
    @orange_turtle3412 Před 2 měsíci +1

    Giving testers free access to desmos was the biggest mistake college board ever made. Hehehe…

  • @user-il1tn2rq4w
    @user-il1tn2rq4w Před 8 měsíci +1

    When will the sat score will publish? Of August 26 Digital

  • @dhiraj7b1vallabhaneni30
    @dhiraj7b1vallabhaneni30 Před 8 měsíci +3

    could u do the hardest english questions?

    • @thx1136
      @thx1136 Před 8 měsíci +1

      ... with Desmos

  • @thetechsolutions4420
    @thetechsolutions4420 Před 2 měsíci +1

    Hardest 😂

  • @RiverieEssence
    @RiverieEssence Před měsícem

    she keeps yapping so much.. such a time waste

  • @user-su4ni8eg4s
    @user-su4ni8eg4s Před 6 měsíci

    Laura thank you so much for all your videos. You aren't just smart, you're also super pretty 🥹