What is the physical process that reduces the maximum current? I mean, what happens to the minority and the majority carriers in the depletion regions when you apply a negative Vgs? Does the current decrease because Vgs now pulls the electrons backwards?
EC Academy i understand that... But when I = I (dss) i think the chanel is closed because the depletion reason is widening and prevent the electrons from flowing... So why the Ids not decrease to 0??? Where was i wrong or how the ids continue to remain in idss??please explain that to me thanks
I don't understand, first Source was negative and electrons flowed to the positive Drain. Then you connect positive to source, how does that work? positive to Source and Drain?
Both the deletion region does not touch each other, it appears as if both are touching each other. There will be narrow gap between both the depletion region hence the amount of charge flow between the region will become constant… hence current become constant. Hope this is helpful… Do subscribe and keep supporting EC Academy ✌️
It is similar to n channel JFET… only the polarities changes and explanation remains the same…. Hope this is helpful… Do subscribe and keep supporting EC Academy ✌️
Super explanation 👍🏻
Thank you sir. Your explanation is awesome.
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Thank you for Good and understandible explanation ,God may bless you
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Superbb explanation brother....Really helpful 💛🧡... thankyou so much..anna
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Sir do u have any notes for this
Very well explained, thank you
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Simple and clear cut explanation..
Thank you so much sir..❤
Love you EC Academy...💗
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great explanation thank you engineer
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What is the physical process that reduces the maximum current? I mean, what happens to the minority and the majority carriers in the depletion regions when you apply a negative Vgs? Does the current decrease because Vgs now pulls the electrons backwards?
It's very useful sir good explain
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Thanks sir awesome explained
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U r really appreciative teacher ❤️😊, thank you so much sir
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@@ECAcademy binod
Thank you sir, nicely explained.
Mehaboob Khalandar thank you need your support to EC Academy 👍
@@ECAcademy binod
This channel is really helpful for me 💖
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@@ECAcademy Sure..... Sir 🤘
Hey guy can you show me that .....
When U(DS) =u(p).... There still the flow of electrons and the I(D) =IDSS not 0 ???
Please look at the graph.... when Vds = Vp then Id = Idss and not zero. This condition is known as pinch off condition. Hope you understood 👍
EC Academy i understand that... But when I = I (dss) i think the chanel is closed because the depletion reason is widening and prevent the electrons from flowing... So why the Ids not decrease to 0???
Where was i wrong or how the ids continue to remain in idss??please explain that to me thanks
Brilliant explanation
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Thank you sir it's helpful for me
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Super ga chappuvu anna
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Nice explanation
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Thank you very much
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Thanks pls do some subtitle you're lesson is very understandable than my proof thank Subcribe to you
thank you.... share the link with your friends....
Good lec ☝️
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thank you sir
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Tq so much sir
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Tqsm
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Very nice
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🙏🏻🙏🏻
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Very well explained sir
Super sir
And explanation is awesome 👌
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I don't understand, first Source was negative and electrons flowed to the positive Drain. Then you connect positive to source, how does that work? positive to Source and Drain?
How current constant even both depletion regions touch each other?
Both the deletion region does not touch each other, it appears as if both are touching each other. There will be narrow gap between both the depletion region hence the amount of charge flow between the region will become constant… hence current become constant.
Hope this is helpful…
Do subscribe and keep supporting EC Academy ✌️
Sir ya working of jfet m bhi likh sakte h na
Yes... you can write
Sir, Idss means?
Today is my final sem exam... Now I'm watching this🙂.. Very helpful sir❤
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@@ECAcademy sir wrote this today's exam. 😃 once again thank you sir❤
Hope you have done well… 😄
Same bro today is my sem exam iam watching this....
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Sir please make video on bridge rectifier
Bridge rectifier 👉czcams.com/video/34hWklTgzbI/video.htmlsi=WpQylb2yWoIhlJAx
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@@ECAcademy thank you 😍😍
Sir will you make video on working of p- channel jfet 🥺🥺🥺plzzz sir it's much needed
It is similar to n channel JFET… only the polarities changes and explanation remains the same….
Hope this is helpful…
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Here is written n channel JFET but int the video n channel FET .... Could you tell me what it is actually .....
Both are same…..
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Sir please provide online notes if available
I have not scanned the notes...
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Sir can I get notes for this
I have not scanned the notes...
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Notes pettandi sir
Where is the p channel working
Working if p channel is same as n channel FET. Only change the polarities of the circuit.
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Binod
still cant find him..!!!
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Thank you sir
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