China | A Nice Algebra Problem | Math Olympiad
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- čas přidán 8. 07. 2024
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a^2+b^2+ab=(a-b)^2+3ab=(33-16)^2+3*33*16=289+99*16=289+1600-16=1873
Excellent, nice and beautiful
I was correct.
I did it in my head.
U n
Mind is wise.
(33^4+16^4+49^4)÷(33^2+16^2+49^2) =1873
1873=(33^2+16^2+49^2)/2 🤣🤣🤣🤣
Excellent presentation
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