Here is my full solution: 25ˣ + 5ˣ = 20 (5²)ˣ + 5ˣ = 20 (5ˣ)² + 5ˣ = 20 Let u = 5ˣ u² + u = 20 u² + u - 20 = 0 (u + 5)(u - 4) = 0 u = -5 or u = 4 ∴5ˣ = -5 (rejected) or 5ˣ = 4 log₅(5ˣ) = log₅(4) x = log(4) / log(5) x = log(2²) / log(5) x = 2log(2) / log(5)
25ˣ + 5ˣ = 20
(5²)ˣ + 5ˣ = 20
(5ˣ)² + 5ˣ = 20
Let u = 5ˣ
u² + u = 20
u² + u - 20 = 0
(u + 5)(u - 4) = 0
u = -5 or u = 4
∴5ˣ = -5 (rejected) or 5ˣ = 4
log₅(5ˣ) = log₅(4)
x = log(4) / log(5)
x = log(2²) / log(5)
x = 2log(2) / log(5)
令5^x=a 則a^2+a=20. 則a=4
則x=log4/log5
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Here is my full solution:
25ˣ + 5ˣ = 20
(5²)ˣ + 5ˣ = 20
(5ˣ)² + 5ˣ = 20
Let u = 5ˣ
u² + u = 20
u² + u - 20 = 0
(u + 5)(u - 4) = 0
u = -5 or u = 4
∴5ˣ = -5 (rejected) or 5ˣ = 4
log₅(5ˣ) = log₅(4)
x = log(4) / log(5)
x = log(2²) / log(5)
x = 2log(2) / log(5)