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Convert to binary

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Ответ "й"

a=7 , b=0 or a=25 , b= 24

😂😂😂😂😂

X=5 ; Y=1

148=128+16+4=2^7+2^4+2^2

And this is a lengthy quadratic equation

If y=1 : x=5/13 and if y=6/7 x=5/14

Перенес 36 влево а знак оставил +... баран...

What is w( )?

×= Логарифм 75 по основанию 5

Да Простите Ошиблась

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Все уже решила в уме, все комментарии прочитала, а он все пишет и пишет, решает и решает... М-да...

Interesting🎉

Too wordy. We can immediatly calculate the value of 5¹¹, then we calculate the value of (5¹¹ - 3²)

il risultato dell'equazione è X = 2

X×X×X+X=10 X³+X=10 X(X²+1)=10 >>>10=2×5 =2(4+1) =10 >>>X=2

That is too easy, you immediately see the solution

令5^x=a 則a^2+a=20. 則a=4 則x=log4/log5

x = u - 3/2 √(u + 5/2) - √(u - 5/2) = 1 √(2u + 5) - √(2u - 5) = √2 (2u + 5) + (2u - 5) - 2√(4u² - 25) = 2 2√(4u² - 25) = 4u - 2 √(4u² - 25) = 2u - 1 4u² - 25 = 4u² - 4u + 1 4u = 26 => u = 13/2 x = u - 3/2 => *x = 5*

The 2sqrt(2)s cancel out.

Quadratic. As usual and again. Why has my stove/oven neutral been lost again?

Х и Y изменяются, в случае умножения максимальное число, в случае сложения минимальное

последнее не стал расписывать)

x^3 + x - 10 = 0 (x - 2)(x^2 + 2x + 5) = 0 x = 2, -1 +/- 2i

Короче: что то там получилось запредельное. Самое главное, что с этим встречаемся каждый день, и без этого НЕ ПРОЖИТЬ!!?

No work required. 2

Aplicando el triángulo de Pascal

x=2

=> 5x²-34x+57=0 => => x=(34±4)/10 => => x=3.8 X; x=3 V

I don't get it, how the solution couldn't be as easy as (x^3)^1/3 = (5^3)^1/3 and then x =5?

Unnecessary complicated. Moving sqrt(x-1) to the right and squaring gives x + 4 = x - 1 + 2*sqrt(x-1) + 1 => 2*sqrt(x - 1) = 4 => sqrt(x - 1) = 2 => x - 1 = 4 and thus x = 5.

3x = (√x)/3 9x = √x √x(9√x - 1) = 0 √x = 0 => *x = 0* √x = 1/9 => *x = 1/81*

I did it using the same base method. I don't want to sound rude but that was awfully long

2.5別鬧了

Usando la proprietà delle potenze si trova x=x-5 che è un'equazione impossibile, ma essendo l'esponente pari, si può avere anche l'equazione x=-(x-5) che porta alla soluzione x=5/2