Newton’s Second Law of Motion - Force and Laws of Motion | Class 9 Physics

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✅ In this video,
✔️ Class: 9
✔️ Subject: Physics
✔️ Chapter: Force and Laws of Motion
✔️ Topic Name: Newton’s Second Law of Motion
===============================================
00:00 Introduction: Force and Laws of Motion
00:04 Newton’s Second Law of Motion
25:20 Website Overview
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Newton’s Second Law of Motion
Change in momentum can be calculated as:
Case 1: P = Pf - Pi
= mv - mu
= 2(5) - 2(0)
P = 10 kg m/s
Case 2: P = Pf - Pi
= mv - mu
= 2(10) - 2 (0)
= 20 kg m/s
Hence proved
Force ∝ Change in momentum
More the force more will be change in momentum.
Force ∝ 1/t
Where, t = time at which momentum velocity changes
Comparing both the concepts
Force ∝ p/t
Force ∝ (mv -mu)/t
Force ∝ m(v -u)/t
Force ∝ ma
Force = Kma (k = proportionality constant i.e. value of k in SI unit is 1)
Force = mass x acceleration .
Disclaimer: "This video is for educational and informational purposes only and is not intended to infringe on any copyrights. If you believe that this video has used any copyrighted material in a way that constitutes copyright infringement, please contact us at [e-mail] and we will take appropriate action."

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Ma'am but change in p in i case of glass will be -10 as m(0-10) but you have written 10

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We should subtract final velocity-initial velocity and not initial velocity-final velocity, v=10, u=0 tha thats why she did so

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In the first example of glass breaking in floor change in momentum would be (-10 kg.m/s)

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11:14 Mam change in momentum will be,0-10=-10kg m/s

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11:12 it is -10m/s mam because it is 0 - 10 not 10 - 0

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Then the momentum of the glass falling on the floor will be lesser than the other example....
This is making me confused

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maam change in momentum and rate of change in momentum are different ...pls tell me maam

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In the first example of glass breaking in floor change in momentum would be -10 kg.m/s

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the rate of change of momentum directly proportional to the force applied on it and takes place in the direction in which the force applied on it

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Why we took 5m/s as our final velocity
I think we should take it zero because the glass stopped at a point and stop means it's velocity finally became zero.
[( At 12:36)]

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Initial velocity mention nahi hai it mean chalne ke pehle vo ball rest per the agr koi bhi object ruka hua hai fir vo chalna start karta hai it means uski Jo initial velocity Hogi it becomes 0 .I hope it will help u .if u like then please reply me

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* Distance travelled will increase
* Velocity will increase
Is it right

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F ∝ V
&
F ∝ M
So, F ∝ M×V
Or F ∝ p (i.e. momentum)
We can also say that F ∝ ∆p(i.e. change in momentum)_____(1)
Or the greater the force is, the greater will be the change in momentum of the body because force applied means the velocity will change and therefore momentum will change as well.
But we can also observe that F ∝ 1/ T( time)
How? For example: We have a large box and we want to push it to the end point.
CASE 1- We apply lesser force to push the box, so the time that it will take to reach to the other end will be more.
CASE 2- We apply greater force , so it will take lesser time to reach till the end.
So, F ∝ 1/ T
By combining we get this with (1),
F ∝ ∆p/ T
Or F ∝ rate of change of momentum
By expanding this equation,
F= mVf - mVi/T
F = m( Vf - Vi)/T
F = m× ∆v/T
( We know a= ∆v/T)
So, F = ma
Summarising: The rate of change of momentum of a body is directly proportional to the applied force and takes place in the direction of force.
In short, F ∝∆p / T

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11:12 ma’am u wrote 10 kg m/s I think the answer should be -10 kg m/s.... but even if we take -10kg m/s then also the change in momentum is less (-5kg m/s) than that compared to the glass in the next case (cushion) ... but u told the change in momentum in the first case should be greater than the second one... can anyone explain this to me

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In glass case you say in 1 case momentum is 10kgm/s but if we subtract (0-10) answer is -10kgm/s
This is a basic thing i don't think u should do this
then why ?

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Mam I have a confusion 🤔 at 13.10 you have written that in first problem momentum is 10m/s but when you are solving the first problem m(0-10)kg
= -10kgms^-1 here -10 comes and you have written +10

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Yess that was supposed to be (-10 kg.m/s)

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Mam in the case when grass broken in this why you have not taken(-10) because 0-10 is there

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0

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0

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[@sakshikanswal6842]

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[@arunchoudhary8095]

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