I put the integral part on the calculator website, and it said “Antiderivative or integral could not be found. Note that many functions don't have an elementary antiderivative.” , which means there is a solution, but we can’t express without integral, and therefore it is unsolvable.
Unless we allow complex numbers, the expression is undefined. Restricting to the reals, sin^-1(x) is only defined for x between -1 and 1, and sqrt(x) is only defined for x >= 0. So 1+sqrt(1+sqrt(x)) is not larger than 1 + sqrt(2). Since this is less than e, ln(sqrt(1+sqrt(1+sqrt(x)))) < 1/2, so ln(ln(sqrt(...))) < 0, so ln(ln(ln(sqrt(...)))) is undefined. This means there's no value of x for which both the numerator and the denominator in the integral are defined, so there's nothing to solve.
@@thephysicistcuber175 If we're restricting to the reals, then there's no value of x for which the integrand is defined. sin^-1(x) is between -1 and 1, and sqrt(x) is only defined for x >= 0. So the integrand could only be defined for 0
@@sohidulislam6020cos(arcsin(x))-sin(arccos(x)) is equal to zero, integral of zero=0x+c=c=some constant, so the question becomes finding the second derivatives of the numerator only, which is possible to solve but need a very long step.
In differentiation : You are the boss
In Integration : The Function is the boss
Now we all want you to solve this for us.
I put the integral part on the calculator website, and it said “Antiderivative or integral could not be found. Note that many functions don't have an elementary antiderivative.” , which means there is a solution, but we can’t express without integral, and therefore it is unsolvable.
@@BurningShipFractalNo. It's solvable on desmos Graphing calculator (if you add slider l)
@@stewpeed1then what's the written solution?
@@Carsaboy ITS A GRAPH
@@BurningShipFractalmost functions in math aren't elementary or linear. Just create transform it or find an equivalent fourier series.
0:54 * erased derivative *
- Ah what a relief!
0:57 * puts integral *
- AAAAAAAAAAAAAAA....
Unless we allow complex numbers, the expression is undefined. Restricting to the reals, sin^-1(x) is only defined for x between -1 and 1, and sqrt(x) is only defined for x >= 0. So 1+sqrt(1+sqrt(x)) is not larger than 1 + sqrt(2). Since this is less than e, ln(sqrt(1+sqrt(1+sqrt(x)))) < 1/2, so ln(ln(sqrt(...))) < 0, so ln(ln(ln(sqrt(...)))) is undefined. This means there's no value of x for which both the numerator and the denominator in the integral are defined, so there's nothing to solve.
give the value for the complex numbers
@@human6638 Someone should definitely do that and it's not going to be me
@@blythethorn5835 true
I really enjoy maths at school and just started calculus. I hope one day I can solve something like this 😅
Are you a 9th grader
I doubt the integral on the bottom is analytically solvable. Otherwise the rest is just tedious calculation.
@@thephysicistcuber175the integrand’s numerator is zero, so the integral is actually trivial
@@datarioplaysAre you sure? It looks to me like the numerator is sqrt(1-x^2)+x-pi/2.
@@thephysicistcuber175 If we're restricting to the reals, then there's no value of x for which the integrand is defined. sin^-1(x) is between -1 and 1, and sqrt(x) is only defined for x >= 0. So the integrand could only be defined for 0
Can't wait for you to try to solve this in your next video :D
you're gonna make me cry Mr. Chow
If there was no integral sign i would able to solve❤
Anyone can derivative are easy
Dear bprp , we are still waiting for the solution.
Yours forever
XYZ
And eventually they create problems they themselves can't solve🤣🤣
When you changed derivative to integral, I am creamed.
AYO
It's still very easy
Then they wonder why there's 6 people left by the end of the semester and 2 of them are the TA/SI
It's just a joke. Please no one try to solve it.
And finally, differentiate the whole fraction.
Everything was fine untill he put integral....
You can definitely solve the derivative in the numarator but can anyone tell me if you can slove the integral on the denominator
It is undefined
Simplify without products sum and In
Can you talk about the grandi's series? I hate to believe that it equals 1/2 unless you say it
If the denominator is cos(arcsin(x))-sin(arccos(x))
Then we will know the answer immediately
Can you give the solution in detail here pls?
@@sohidulislam6020cos(arcsin(x))-sin(arccos(x)) is equal to zero, integral of zero=0x+c=c=some constant,
so the question becomes finding the second derivatives of the numerator only, which is possible to solve but need a very long step.
@@khoozu7802can you explain y sin(arccos x)=cos(arcsin x)? I dont really see why or how. Thank you.
@@Ninja20704 draw 2 triangles with an angle(theta) by letting theta=arcsin(x) ➡️sin(theta)=x and letting theta=arccos(x) ➡️cos(theta)=x
@@Ninja20704
For first theta u will get
cos(theta)=cos(arcsin(x))=sqrt(1-x^2)
For second theta u will get
sin(theta)=sin(arccos(x))=sqrt(1-x^2)
Now, can we have the solution please?
Integration is so hard but I like your vedios
Tried the equation
Plus three h minus x equal con sin x lol
you have to make a video answering it now
Really 😂
LOL
太好笑了！
Where did your beard go
Are you mad?????🤣🤣
Just hope teachers don't watch these videos 😂😊
Why doesn't he teach anything i would have liked to view his teaching videos
Tui kor!!!