Determine the force in the supporting cables DA, DB, and DC.
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- čas přidán 9. 09. 2024
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If the bucket and its contents have a total weight of
20 lb, determine the force in the supporting cables DA, DB,
and DC.
you dont know how helpful this is, better than my hour long lectures in college
I believe practice makes perfect, do a lot of problems and you should be fine!
Thank you so much for this! I'm just learning statics and dynamics this summer and the 3D problems still confuse me a lot!
you know it was some dude with a business major or an architect who disliked this video!!
why does the coordinate of DB equal -1k? shouldn't it be -1.5k, since it's along the y axis?
He jumped right to the unit vector of UB.
SO yes, DB is: 0i -1.5j +0k
then for the unit vector U_DB we need to divide by the magnitude: sqrt(0^2+ (-1.5)^2 +0^2)=1.5
U_DB = (0i -1.5j +0k)/1.5 = (0i -1.0j +0k)
(I think you accidentally switched your j and k but if you have questions about why it is j and not k: k is used when there is a value in the z-direction, both point B and D have no value in the z-direction so the k component of the DB vector is 0)
You are the beeeest one Thx guide ❤️❤️❤️❤️❤️❤️❤️❤️
You are the best! Thank you again!
Thank you sir!
Thank you 🤗
KINDLY EXPLAIN HOW YOU GET THE DB, AND DC SIR THANK YOU
Thank you very much
amazing thanks
Is dc magnitude = 2.5 ?
why EQ3 musltiplying -1?
so, this is what nerds do on Christmas?
Sergio Ornelas yep hahaha
Which app you use to write on screen smoothly
why is the Ubucket = -1k?
Is it possible to write on smartphones with so ease and accuracy
why don't you have solutions for chapter 8 and 7? I love your solutions thank you
I'm so confuse why is Y=0 for vector A
The position vector for A has a 0 value in the y-direction (j-hat) because it lies in the xz-plane.
So the position vector for A is: 4.5i + 0j + 3k
The vector for the rope between D and A does have a j-hat component. This vector is the position vector for A minus the positon vector for D (which lies in the xy-plane is: 1.5i +1.5j + 0k
This works out as such: position vector A 4.5i + 0.0j + 3.0k
- position vector D 1.5i + 1.5j + 0.0k
___________________________________
Vector DA 3.0i - 1.5j + 3.0k
The next step is to find the magnitude of vector DA: sqrt(3.0^2 +(-1.5)^2 +3.0^2) = 4.5
Then divide vector DA by its magnitude to find the unit vector U_DA: 0.667i + 0.333j +0.667k
How B is in i
1:23 B. ?
You are a little bit confusing🤔😕😵😅 about B
Udb = -1.5j not -1j
uDB is -1j
@@DedikTutorial why? He have in b 0 j and in D 1.5j, so 0 - 1.5 is = to -1.5. So im also wondering where he found the 1?
I mean it doesnt make scence! or well jaj
@@esveyditorres9972 This is a bit late but.... if you take vector DB divided by the magnitude of DB, you get -1j...