Helped me out big time! Was doing a past paper and this is the first time i have seen this type of question... and my exam is tomorrow morning! Many thanks, and wish me luck!
THANK YOU SO MUCH GREAT EXAMPLE. I WAS HAVING TROUBLE IDENTIFYING THE SAMPLE MEAN WHICH IS THE MEAN SALARY OF THE SAMPLE IS GREATER THAN X BAR (THE SIGNS ARE THE INEQUALITIES CONTEXT. ) ALSO GREAT TIP ON JUST PASTING THE QUESTION AND CHANGING IT TO A STATEMENT FOR INTERPRETATION
What if you are trying to find a probability that a simple random sample of 50 provides a sample mean of 7.5 to 9.5? Mu = 8.5 and SD = 2.2 how would you work this type of probability out?
Around 3:00 you say you can use the normal z-score formula if you want to calculate the probability of an individual. According to central limit theorem you cannot assume that the random sample of 1 is normally distributed so you cannot calculate the probability. OR am I wrong?
he says you use the standard z score for normal distribution. here is the sampling distribution for sample mean. if only 1 plumber, there is no sample. so the formula is bit different in which you just divide by sd. for sampling distribution (in this case 42 plumbers), you divide by sd/sqroot(n).
In a certain population, 83% of the people have Rh-positive blood type. Suppose a random sample of n= 10 people is to be chosen from the population and let P represent the Wilson-adjusted proportion of Rh-positive people in the sample. Find (a) Pr [P= 0.714] (b) Pr [P=0.786]
10 years later and you are still the greatest. Preciate it sir
Helped me out big time! Was doing a past paper and this is the first time i have seen this type of question... and my exam is tomorrow morning! Many thanks, and wish me luck!
5 years later how did it go?
I have an exam tomorrow morning too lol
8 year later update: Passed my exam. I have no idea what any of this means anymore! Now a professional dancer.
the calculator part makesnosense my calculator shows lower, upper , etc options
i researched and watched this video to clarfy if my answer's right, im so glad that it is! it helps for my 'self-trust issues' LOL THANKYOU!
thank you so much i was having difficulty understanding central limit theorem but this was the exact example i needed!!
why did you use 99 for the calculation?
where did you get the 99 from ?
Also which calculator did you use?
Good video sir
Helped me alot to understand sampling thank you so much
THANK YOU SO MUCH GREAT EXAMPLE. I WAS HAVING TROUBLE IDENTIFYING THE SAMPLE MEAN WHICH IS THE MEAN SALARY OF THE SAMPLE IS GREATER THAN X BAR
(THE SIGNS ARE THE INEQUALITIES CONTEXT. ) ALSO GREAT TIP ON JUST PASTING THE QUESTION AND CHANGING IT TO A STATEMENT FOR INTERPRETATION
Was you suppose to subtract the area from 1
What if you are trying to find a probability that a simple random sample of 50 provides a sample mean of 7.5 to 9.5? Mu = 8.5 and SD = 2.2 how would you work this type of probability out?
don't you subtract .0009 by 1 which gives you the asnwer of 0.9991
(.0009 found from z score table)
nevermind 😂😂
The right answer is o.ooo9
this was quite helpful, especially since my professor likes to assign word problems of the same subject/layout
Around 3:00 you say you can use the normal z-score formula if you want to calculate the probability of an individual. According to central limit theorem you cannot assume that the random sample of 1 is normally distributed so you cannot calculate the probability. OR am I wrong?
he says you use the standard z score for normal distribution. here is the sampling distribution for sample mean. if only 1 plumber, there is no sample. so the formula is bit different in which you just divide by sd. for sampling distribution (in this case 42 plumbers), you divide by sd/sqroot(n).
can i get d last part of calculation using casio fx-991ES plus .?
i'm confused for when you would divide the 44,000 by 42?
Very nice and simple
You're a lifer saver!
Good stuff!! Very good!
In a certain population, 83% of the people have Rh-positive blood type. Suppose a random sample of n= 10 people is to be chosen from the population and let P represent the Wilson-adjusted proportion of Rh-positive people in the sample. Find
(a) Pr [P= 0.714]
(b) Pr [P=0.786]
a
help. you find that for n=9 woman, the sample mean is x = 85 and the sample variance is s = 160,78. estimate the standard error of the sample mean.
Where can I download that calculator?
Thanks
you are the man!!!
OMG THANKUUUUU SO MUCH
very helpful video
Thank you.
there's no 3.12 in my z-table
Jesus is coming soon. Accept him and repent from all your sins before it's too late.
are you sure
because dont you set the upper z score to infinity
You really had to make two videos of each 10 minutes for something that could be explained within 3 minutes? This is atrocious.