Differential Forms | The product rule for the exterior derivative.

We give an example calculation of the exterior derivative and present a "generalized" product rule that it satisfies.
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[@user-qi4ly9og4w]

Thank you ton for a good and easy to follow lecture on differential forms, Michael.
I noticed that the lecture 15 around time at 5:14, the exterior derivative of first term has a typo and it continues without correction.
It seems that 2y dy^dx^dz should be x^2 2y dy^dx^dz.

[@benjaminandersson2572]

Yes

[@nickiminster7500]

Dear Michael, thank you very much. I'm studying physics in Hanover and today I have an exam in "
measure and integration theory/function theory" and I never got a hang on differential forms until I found your videos. They really helped me a lot !!! If I pass I will answer how the exam and especially DF's worked out for me but I'm optimistic :))))))

[@Noam_.Menashe]

What happened?

[@giuseppepapari8870]

4:39, isn't there a x^2 missing? (2 * x^2 * y wedge dx wedge dz)? Or maybe I do not completely understand what happens?

[@nozzbean1709]

You're right, I think it was just an error on his part

[@AndyGoth111]

Goofs like this make us into a more attentive audience which helps our learning. Such irony!

[@davidgillies620]

The final result is 2 x^2 y(3 z - 1) dx ^ dy ^ dz

[@JB-ym4up]

It's a plane! It's a m-form! It's Super Algebra!!!

[@zdzichumis]

I might be missing something, but in the proof of product rule for exterior derivative of wedge product of n-form with a k-form shouldn't the index of second sum from the definition be going from 1 to n+k as the wedge product of n-form and k-form is n+k form?

[@goodplacetostop2973]

11:28

[@xriccardo1831]

I always go through the comments after watching the video for your comment

[@phsamuelwork]

Thanks for the clear lecture! Just curious about the proposition. Is the RHS also equal to (dw) ^ u + (du) ^ w?

[@neharupi6373]

Thankyou so much sir😊

[@oskarjung6738]

Yo you studying this.

[@user-zl1sl5cn6j]

So nice, you let me out from the trapped state in reading stokes theorem with confused symbols.

[@senhorkorracha]

Super algebra :O that name is so extra.

[@protosstassadar20]

I think in 4:42 you forgot x^2 when you take the d/dy

[@bobdowling6932]

I'm intrigued by the nomenclature. This is an "exterior derivative". Is there such a thing as an "interior derivative"?

[@biblebot3947]

There’s a Wikipedia article on it

[@Noam_.Menashe]

I think it's just so it isn't confused with the inner product/derivative.

[@mikesteele5935]

I'm missing something. Unless I and J are disjoint, the two forms have a wedge product of 0. OK, let's suppose they are disjoint. Then when we take the d we have various dx_i that distribute over various parts of J. We don't always get m swaps. I told you I was confused !

[@donmcrapsavier4463]

LoVeYoU PROF

[@athoshipner6847]

...minkia...

[@__hannibaalbarca__]

It not need to put segma sum; use Einstein notion

[@________6295]

third

[@3manthing]

czcams.com/video/yUGZwlLoZh0/video.html

[@supramayro434]

Who?

[@Re-lx1md]

7 seconds in and im lost LMFAO