Second Derivative Test
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- čas přidán 3. 03. 2018
- This calculus video tutorial provides a basic introduction into the second derivative test. It explains how to use the second derivative test to identify the presence of a relative maximum or a relative minimum at a critical point. If the second derivative is positive at a critical number - a local minimum is present. If the second derivative is negative at a critical number - a local maximum is present. So to identify the relative extrema, find the first derivative, set it equal to zero and identify the critical numbers. Plug the critical numbers into the second derivative function to determine the concavity of the function to see if its concave up or concave down. If it's concave up - it's a relative maximum. If it's concave down, it's a relative minimum. You can confirm the results of the second derivative test using the first derivative test with a sign chart on a number line.
Introduction to Limits:
• Calculus 1 - Introduct...
Derivatives - Fast Review:
• Calculus 1 - Derivatives
Introduction to Related Rates:
• Introduction to Relate...
_____________________________
Extreme Value Theorem:
• Extreme Value Theorem
Finding Critical Numbers:
• Finding Critical Numbers
Local Maximum & Minimum:
• Finding Local Maximum ...
Absolute Extrema:
• Finding Absolute Maxim...
Rolle's Theorem:
• Rolle's Theorem
________________________________
Mean Value Theorem:
• Mean Value Theorem
Increasing and Decreasing Functions:
• Increasing and Decreas...
First Derivative Test:
• First Derivative Test
Concavity & Inflection Points:
• Concavity, Inflection ...
Second Derivative Test:
• Second Derivative Test
_________________________________
L'Hopital's Rule:
• L'hopital's rule
Curve Sketching With Derivatives:
• Curve Sketching - Grap...
Newton's Method:
• Newton's Method
Optimization Problems:
• Optimization Problems ...
_______________________________________
Final Exams and Video Playlists:
www.video-tutor.net/
Full-Length Videos and Worksheets:
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Final Exams and Video Playlists: www.video-tutor.net/
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Indeed
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@@ian.ambrose They can’t really “save a week” of time though since they’re obligated to go to class anyway lol
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Can you do some examples with trig functions? Use the second derivative test to find local extrema of a sine or cosine function
?
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Professor Organic Chemistry Tutor, thank you for showing students/nonstudents How to use /apply the Second Derivative Test to find Relative Maximum/Minimum at a critical point in Calculus. This is an error free video/lecture on CZcams TV with the Organic Chemistry Tutor.
Best tutor in the world
Thank you sir.
To find the actual point of the extrema, would we plug our x value that we got from the second derivative test back into the first function?
is the change in slope (i.e the second derevitive) of a * maxima * or a * minima * must always be * negetive dec. * or
* positive inc. * respectively or can it be * zero * at any of them aswell?
Thank you🙏🏽
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thank you
Nice explanation
Gr8 work
Thank you Sir.
thank you soo much
Trying to find the inflection point of an equation of curve. y=5.075e^(.2136x). equation goes from positive to negative. I have a lot of these to do so would like an online calculator. Can you point me in right direction. Did I give you enough information ?
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at 1:37, if f’(c) = 0 and f’’(c) is just the slope of the derivative at x value of c. why isnt f’’(c) just equal to 0?
So what is the benefit of using the second derivative test vs the first..?
After putting the critical values in the second derivative if f"(c) = 0 then we go back to first derivative test ...
Actually both tests are used but it depends on you which one to use ....
Well I would say learn both the tests because you could be asked to apply any one of them
Hope this helps...
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I am at 1:08 and already had all my answers thank you :D
What if there is the same sign in critical number?
I understand the calculations. What I don't understand is why, when I graph the equation in Geobegra, that a turning point appears to be (-3, -26) and not (-2,-15). Anyone can help me to understand? Thank you.
Thank you
Why is the 2nd derivative negative with a relative maximum and positive with a relative minimum, and what happens if the 2nd derivative is 0
2nd derivative -ve → concave down→relative maximum
2nd derivative +ve → concave up → relative minimum
👌
Thanks
What if f'(c) = f''(c)? Would that mean that there are no relative extrema?
what if the 2nd derivative is a constant?
If we can easily find using 1st derivative test, why we need second derivative as well?
thanks alot
This stuff just doesn't register when im in class, thanks for the to the point explanation
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But how this connected with the main function? Explanation is not clear on that part.
What to do incase if double derivative gives 0 at critical points.
Thanks you so much...
Every hero does not wear cloak, thanks a lot.
ok but how would you do it with a rational???
MY TEACHER DID NOT TEACH ME ANYYY OF THIS. THANK YOU!
سپاست مامۆستای بەڕێز
goat?
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so you can only do this if you have critical numbers?
yessir
The first derivative test for extrema, and the second derivative for inflection points seems more intuitive to me.
Yup
That's very cool.
Watching this 30 min before my midterm 😂😭😱
Watching 2 days before my finals ....
Watching the day before
1. Find critical numbers (F'=0)
2. Find out scond derivative (F'') at those critical points
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Z_Boss_23 so then he probably could score a 100
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For you're last example, when 12x^2-12x-24=0, are the roots not x=2 and -1 (instead of -2 and 1) as putting your values in you dont get 0 and my calculator said my x values were correct? Great vid tho helped alot👍🏽
I’m pisssed that I’ve been doing this the harder way
I'm sure we are plenty here watching 5yrs ago video 😊
Is it possible to get 3 critical points and 2 inflection points?
redge fleming yes!
Any function can have any number of either.
Can someone explain to me how 4x cube become 12x squared and 6xsquared become negative 12x i really suck at math
He was using the power rule for derivatives. You may want to look up a separate video to learn that topic first before continuing (you can look for one of his videos, or you can check out mine which I will have linked at the end of this comment). But for the example in this video that you are referring to, the derivative of 4x^3 is done as follows: Multiply the function by the exponent, 3, and then subtract one from the exponent. So you will have 3*4x^(3-1) which then is equal to 12x^2 if you simplify it. The same thing would happen for 6x^2. Hope this helps, and here is the link to the video I mentioned earlier: czcams.com/video/izMX5wx7ZlQ/video.html
I guess it’s a massage into mental math... I can visualize quadratic fn. on all quadrants unless I forget
I was looking for the reason why