How to use the SECOND DERIVATIVE TEST (KristaKingMath)
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- čas přidán 4. 08. 2024
- ► My Applications of Derivatives course: www.kristakingmath.com/applic...
The second derivative test is a test you can use to find the extrema of a function. In order to use it, you'll need to be able to take the first and second derivatives of the function. You'll use the equation of the first derivative to find the critical points of the function. You'll use the second derivative to test those critical points.
If you plug a critical point into the second derivative and the result is positive, it means the critical point represents a local minimum. If, on the other hand, you plug a critical point into the second derivative and the result is negative, it means the critical point represents a local maximum.
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WOW. SO glad I just found your channel! This made so much more sense than my textbook, thank you.
You're welcome, Alex! I'm so glad it helped! :D
I've been looking all over for a good explanation, thank you so much!
Thanks for the tutorial, I am self-studying calculus and had been confused by this subject for a few weeks now(my textbook doesn't talk about this). Thx
I am a bit confused. How does this process compare to the second derivative sign analysis test? Are they not telling you the same result? How do I know which method to use?
you're an absolute saint! God bless you. Whatever you believe in, I hope it blesses you.
Thank you for making it so simple!! This video helped me tremendously!!
I'm so glad to hear that, Jamie! Thanks for letting me know that it helped! :)
Hi if i can find globle maxima and minima by the same process then how would i be able to figure out that my critical point is local max./min. or globle max./min. ???
THANK YOU! you just saved me hours! The way they explain that in my textbook is so confusing!
Glad it could help! :)
Wow what a brief and concise tutorial . Well done
Thanks!
Great video! Very helpful! Do you have a video on the first derivative test, and do you know how to use it on trigonometric functions i.e. h(x) = sin(x) + cos(x)?
Here's the first derivative test video: czcams.com/video/MPcJdny-uTY/video.html And there's nothing different about the way you use it with trig functions compared to other kinds of functions. :)
God bless you.
this helped so much omg thank you !
You're welcome, Audrey! I'm so glad it helped! :D
👍👍👍👍excellent video
thank you so much!!
:D
what if you get 0 as a result when you plug in your critical point in the f''(x)?
this video was insanely helpful
I'm so glad it helped, Mark! :D
God bless you a short and accurate video
love you mam from India
now my confusion is totally cleared
Oh good! I'm so glad it helped, Shekhar! :)
Why didn't you factor out a 3 out of the first derivative
Hi, how did the derivative = 3x squared - 3? I only have just started studying Maximum, minimum and points of inflections
Isabelle Yap constants go away, multiply the degree number into the coefficient and drop the degree by 1
@@Bigstu27 Thank you.
OMG I LOVE YOU SO MUCH
THANK YOU THANK YOU THANK YOU(':
You are so welcome! I'm glad I can help!
Vey good instruction
Thanks Charles!
What if both of the critical points give you a value of f''(c)=0 using the second derivative test ????
this means the second derivative test have failed so you choose two values to the left and right of the critical value. So if the critical value of 2 gives you 0 you would try to plug in 1 and 3
Question! What happens when f''(c) = 0?
If f''(c) = 0, then the second derivative test fails and you have to use the first derivative test. :).
If f"(c) = 0, then c is a possible point of inflection. The only way that it could be a point of inflection is if the concavity changes. So, you would need to perform a sign analysis test to determine that. Test a value less than c and test a value greater than c. If the sign changes, it is a point of inflection. If the sign does not change, then it is not a point of inflection.
Well, it helped me alot. Thanks. Do you still prefer to teach? I mean i am watching this old video.
thank you so much lol
now I just need to figure out how to graph.
And when 2nd derivative is zero than ..?
Did you ever find out? I need to know too!
than watch her previous video.
Let's dispel any rumors right now. Would you date a guy from the CZcams comments?
Let’s dispel once and for all with this fiction that Barack Obama doesn’t know what he’s doing. He knows exactly what he’s doing.
Calc expert? What happened to InttegralCalc???
Arsal Khan She has obviously re-branded! It makes sense as integralcalc can easily be confused as integral calculator, plus she does a lot more than just videos on integration! Calclus Expert is a better name, more descriptive and easier to find on google.
Chris James Exactly! Easier to say, easier to spell, more descriptive...at least that is what I was going for!
Calculus Expert Well then I think you have achieved what you were going for; I prefer it! :)
Chris James Awesome! Thanks!
😉
Omg omg omg e
zero understanding, i hate school x)