Higher Order Derivatives
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- čas přidán 24. 02. 2018
- This calculus video tutorial provides a basic introduction into higher order derivatives. it explains how to find the second derivative of a function.
Derivatives - Fast Review: • Calculus 1 - Derivatives
Equation of the Tangent Line:
• How To Find The Equati...
Derivatives - Horizontal Tangent Line:
• How to Find The Point ...
The Equation of The Normal Line:
• How To Find The Equati...
The Equation of The Secant Line:
• How To Find The Equati...
_________________________________
Average and Instantaneous Velocity:
• Average Velocity and I...
Instantaneous Rate of Change:
• Instantaneous Rate of ...
Derivatives of Rational Functions:
• Derivatives of Rationa...
Derivatives of Radical Functions:
• Derivatives of Radical...
Derivatives of Fractions:
• How To Find The Deriva...
________________________________
Derivatives - Higher Order:
• Higher Order Derivatives
Simplifying Derivatives:
• Simplifying Derivatives
Derivatives - The Product Rule:
• Product Rule For Deriv...
Derivatives - The Quotient Rule:
• Quotient Rule For Deri...
Derivatives - The Chain Rule:
• Chain Rule For Finding...
_______________________________________
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You've been helping me since my first year in college. Thanks man! You're a blessing from the heaven.
Hi my major is computer engineering what is yours?
I’ve started using his videos since senior year of high school.
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junior in high school im screwed.
@@paulwilliams90senior in high school. Were you here for a test like I am right now?
The people who dislikes his videos were probably the university professor 's who didn't like teaching student the easy way.
EURT
What's the use of masters or doctorates if you can't clearly instruct students
Our professor actually sends us this so we can further unserstand the topic
I actually dislike this dude’s videos cuz of his voice and the fact that he doesn’t go over complicated problems. Like most of these are easy in this video.
@@lazlo686 well it says in the description that it is only a basic introduction. He has full length videos if you pay and want to see more.
Great teachers are not only high degree holders, they anyone who can simplify the most complex stuffs using unambiguous words to a dummy. Well done sir.
me: *clicked this video*
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I know, every Calc channel I watch, they have these ads with people saying "YO, WANNA PAY FOR HELP INSTEAD OF WATCHING THIS FREE, COMPREHENSIBLE VIDEO??"
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In Kinematics, the Third, Fourth, Fifth and Sixth derivatives have names. They are (seriously): Jerk, Jounce (also called Snap), Crackle and Pop. They are used by mechanical engineers in the design of cam shafts, railroad track curves, pistons, etc. Acceleration is never really instantaneous. Jerk is the time rate of change of acceleration, that is, the small change in inertia when a constant force is initially applied. Jerk is the time rate of change of Jounce. When you are riding in a car under 'constant' acceleration but over a rough surface, the acceleration is not really constant, but rapidly changing, producing Jerk. To get the smoothest ride on a roller coaster, or on a railroad curve, an engineer considers the Jerk and the Jounce. (Or Snap.) As for Crackle and Pop, they are less used, (if at all), but expressions of the reality that much of applied physics is idealized mechanics. I'm answering my own question, posed below:
best teacher in my life
MR. Organic Chemistry Tutor, Thank you for an outstanding video/lecture on Higher Order Derivatives in Calculus.
Man, u’re helping so much… u doing great, appreciation and congrats…✊🏾
There is a saying when you have a knowledge and you dont share it with people...the knowledge you have will eventually go down but when you continue to share your knowledge with others definitely it will keep on rising. Thanks alot
I learnt full derivatives from your videos thanks a lot sir
Thanks and God bless you endlessly sir!
I saw most of lecture video mainly physics and maths,I proud you what a presentation and presenter real amazing ❤❤❤
Man you’ve saved me so many times now. I still wanna go back in time and tell Isaac Newton to put it back though.
now i will declare that calculus is fcking easyyyyy, depende talaga sa teacher
I'll be having a long quiz on derivatives in the next 6 hours and this really helped
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you're a simplifying machine! god bless your soul
This channel has been single handedly saving my ass from failing math and science subjects since junior high until now at college
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the only thing I don't understand is how I learn so much better from these tutorials than I do from the class I enrolled for
i think this is great....the organic chemistry tutor teaching calculus
Thanks alot, you are a blessing to my future.
Too good man thanku so much for helping me
Thank you so much, the video was helpful
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I got a single formula for getting the higher order derivative during my college days. It can solve the 50th or 100th derivative at once.
What is it?
best teacher
You r the best!
thank u!! ❤️
Nice video again 👍 keep it up
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Salamat po sa inyong turo.
At
Shout out po sa mga kaklase kong pupunta sa video na to.
-nite
What if we wanted to find derivative fiftieth for example? Are there any rules for this?
There is some functions if you want to take many derivatives if you can. A good example would be y=2^x. The nth derivative of that function is y^(n)=2^x(ln(2))^n. The 50th derivative is y^(50)=2^x(ln(2))^50
@@justabunga1 thanks
Thank you
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awesome video
You are great i thank u alot
I searched for partial higher order derivatives but this is I have found only lol.
Thanks 😊
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How about an explanation of the meaning of higher order derivatives. What they signify in a real problem. How they might be of practical use. For instance, in mechanics, the first derivative of distance is velocity. The second derivative of distance - or, that is, the first derivative of velocity - is acceleration. What next? Think about it.
Yes exactly
Who gives a shit
@@frostbitepokin9520 us... students...
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so in other words higher order derivatives, scond, third and fourth derivatives are like composite functions you are saying?
it means its more difficult X'(
is it allowed to have a final answer in a certain derivative in which negative exponent is implied?
I suggest you put it to fraction form.
yeah i agree
@@igit7745
Best expression
Lesssgoooo miss anj
you're better than my paid teachers lol
4:10 the derivative of first part wouldn't it be 2 rather than 2x
Why can't I find any example of what my teacher's giving to us...
same!!! annoying when the teachers only show easy ass examples and explain easy ones but then give super hard versions on the test or homework without explaining or teaching how
@@Kekkndslgnlwnh exactly what my teacher does.
I have one with three components being multiplied, not just two, wherein the Product Rule is easily applied..
I can be your teacher
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When I finish my Diploma am going to make it my mission to come shake your hand 🤝❤️
Thanks for helping me.🙂🙂
what if we were told to find 56 derivative of function?
There will always be a pattern. Usually the questions with the 56th derivative include sin or cos but if it were x^42, then we would know that the derivative would result in 0 because every time we took a derivative, the exponent got subtracted by 1
use Leibniz nth derivative formula, d^n(f*g)/dx=sum of (n k)*f^(n-k) *g^k from k to n
Do they ask like this too??
thankyouuu
still cant believe this our topic in 10th grade lmao
thank you again ;--;
thanks
hello guys, can someone explain to me why we need to multiply (-1) to ycos(xy) / 1-xcos (xy) on both numerator and denominator ? i hope someone help me with this one. 😅
do you still need help 3 years later?
in 5:00 the answer should be 2cosx+4xsinx-x^2cosx right? those two -2xsinx will add up to +4xsinx correct me if im wrong
ure not right ..tho I'm late -2-2=-4
when you multiply -2 by -2 then you get +4 but when you add -2 and -2 you get -4 so The Organic Chemistry Tutor is correct
TWICE add -2 = -4
TWICE multiply -2 =+4
4 years later ur still wrong
@@babyshark8958 don't worry I figured it out long time ago 😂
man these are starting to get a LOT more tedious
Im so confused about how to determine which rule should be used. Like product rule, quotient rule etc. Will someone tell me.
Product rule for f(x) * g(x), quotient for f(x)/g(x)
you use product rule when the question is in the form of brackets, ex: (a+b)(c+d) while for quotient you use it when there's a fraction
Sometimes I just wing it and I end up stressing so much during tests so I write my name on the paper and hand it in without any answers filled (meanwhile its 5 minutes into the exam) every other student in my class stops and stares at me, while my teacher stops me and whispers "You didn't write anything on your exam...". So I tell him "Yeah, I don't know anything...". Even though he insists I try the problems for part marks, I tell him it would only make my situation worse. My life has become a huge fucking mess, I'm 28 and still in night school. My friends stopped talking to me, and every family member won't lend me any money over how much of a disgrace I am. If you're looking for a job in Vermont, I work at a KFC off the highway. Names Andy, please don't be like me.
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Cool 😎
I have a question..
What will be the third derivative if the second derivative is a single number? Cuz in the second derivative i got +10, what will be the third one now??
0 because 10 is constant
The derivative of a constant(single number) is always zero.
yeah i agree
@@kunalkhare1706
yeah i agree
@@lessthanpinochet
I dont konw english but I can understand what you say you save me
nice
1:25 can i do 60x³+ 12x
60(3x²)+ 12(1) then
180x² + 12
180( 2x) + 12(0)
360x
360(1)
360
360(0)
= 0
😂😂 i try to do more if i am wrong you can right me
Our prof is freaking crazy asking for 222nd derivative of sin5x
is there a formula to find the higher derivatives?
Dislikers must be our school/ college teachers
ikr
What would be the derivative of (ln) or (e)?
there's no such thing as derviative of (ln) or (x) u prolly asked the wrong question or u're prolly confused
The derivative of the natural log of x, or ln(x), would be 1/x. And the derivative of e^x is just the same thing, e^x. Those are some rules you learn later on in calculus. If you were asking about the number e and not the function e^x, then the derivative is just 0 since the number e is a constant and the derivative of any constant is just 0. Hope that helps!
People here writing on professor and university i am studying in class11 cmon guys...hod is easy i just came here for some brush up.
Why can't we use the quotient rule for the last problem at 9:10
No x in the numerator
Vauron I would like to point out that you CAN use the quotient rule to solve 5/(x^2). The quotient rule is: (LH’-HL’)/(L^2). I like to write my terms down so I will do that here: H = 5; H’ = d/dx 5 = 0; L = x^2; L’= d/dx x^2 = 2x. Now we substitute those values in to get: [(x^2 * 0) - (5 * 2x)] / (x^2)^2. Simplify: -10x/(x*x*x*x). We have an x on top and bottom so they are equal to one and cancel. We are then left with -10/x^3.
The quotient rule is just a different way of writing the product rule and vice versa. Afaik, any equation that can be differentiated with the product rule can be differentiated with the quotient rule. Hope this helps! (Any questions or misplaced steps please tell me so I can help future people if they also have the same question)
You can use quotient rule but it's going to be a longer method
@@braedenbertz1063so the answer is wrong? his answer on the vid was 5x^-2. I also used the quotient rule and my answer is -10/x^3 .
@@shaneconwell253 when he manipulate the expression is it already the second derivative?! 9;10 - 9;25
🙂🙂🙂
Cbu😂
Poorly presented
Khan academy
I hate calculus so much
Thank you