14:48 Glycolysis actually produces 4 ATPs but uses 2 ATPs in the process. So, while glycolysis produces 4 ATPs, the net production is: 4 ATPs produced -- 2 ATPs used = 2 ATPs produced (net).
26:00 Professor states: "All of the remaining C atoms that made up that glucose are now carbon dioxide." So, 2 CO2 molecules are lost in Glycolysis. Then, the 2-carbon Acetyl group (from Glycolysis) combines with Oxaloacetate to form Citrate (or Citric Acid), which is a 6-C molecule. But remember, 2 Acetyl groups are formed from Glycolysis. So, each glucose molecule actually makes 2 Acetyl groups, each of which go through the Krebs Cycle (starting out by combining with Oxaloacetate to form Citrate). Only one of the Acetyl groups is shown here, so you have to double the number of C atoms to get an accurate count. [At the beginning of the Krebs Cycle, two molecules of Citrate are produced NOT one.] TWO CO2 molecules released per cycle x 2 cycles = 4 molecules of CO2 lost (total). 4 C atoms released as CO2 during KREBS CYCLE + 2 CO2 molecules released during the breakdown of ONE C6H12O6 molecule (glucose) during GLYCOLYSIS = 6 C atoms lost (altogether). 6 C atoms lost = the 6 C atoms of the original glucose molecule (C6H12O6).
Even though I wasn't used to enjoying science classes back then and I'm kinda overwhelmed by these infos, I learned a lot this far in your lectures. You made it very entertaining. Thank you very much.
14:48 Glycolysis actually produces 4 ATPs but uses 2 ATPs in the process. So, while glycolysis produces 4 ATPs, the net production is: 4 ATPs produced -- 2 ATPs used = 2 ATPs produced (net).
im watching this in june 2021 to get me ready for a&p! thank you so much!
26:00 Professor states: "All of the remaining C atoms that made up that glucose are now carbon dioxide." So, 2 CO2 molecules are lost in Glycolysis. Then, the 2-carbon Acetyl group (from Glycolysis) combines with Oxaloacetate to form Citrate (or Citric Acid), which is a 6-C molecule. But remember, 2 Acetyl groups are formed from Glycolysis.
So, each glucose molecule actually makes 2 Acetyl groups, each of which go through the Krebs Cycle (starting out by combining with Oxaloacetate to form Citrate). Only one of the Acetyl groups is shown here, so you have to double the number of C atoms to get an accurate count. [At the beginning of the Krebs Cycle, two molecules of Citrate are produced NOT one.]
TWO CO2 molecules released per cycle x 2 cycles = 4 molecules of CO2 lost (total). 4 C atoms released as CO2 during KREBS CYCLE + 2 CO2 molecules released during the breakdown of ONE C6H12O6 molecule (glucose) during GLYCOLYSIS = 6 C atoms lost (altogether). 6 C atoms lost = the 6 C atoms of the original glucose molecule (C6H12O6).
24:37 Citrate and citric acid are synonymous; they are the same thing.
Even though I wasn't used to enjoying science classes back then and I'm kinda overwhelmed by these infos, I learned a lot this far in your lectures. You made it very entertaining. Thank you very much.
Excellent video
Thank you for the lecture Sir! Amazing as ever💕