I love your teaching style and I love that you devoted your time for chalking on blackboard. Now I understand clearly about the Schottky and nearly Ohmic. Thank you so much.
it is a very useful lecture. Professor, could you please advise in the case of junction between Au and In2O3? What metal is best for In2O3 so that I could get a very near Ohmic contact? Thank you very much.
Is the case where the work function of metal is lower than the electron affinity of the semiconductor like a 2DEG where electrons are trapped in potential well?
1. When you connect two different materials (metal and semiconductor in this case) without any external bias, charges flow from one material to another until the Fermi levels align. This corresponds to the “Equilibrium energy band diagram” 2. When you apply voltage across a device which has achieved equilibrium, you add energy to (or subtract energy from, depending on the polarity) every energy state in the bulk of one of the materials relative to the other material. Hence, for this reverse biased case which you asked about, every energy state (Ec, Ev, EF and Evacuum included) in the bulk of the semiconductor moves “downward” in energy relative to the metal. (Note however that the energy levels at the junction are pinned) Hence, the Fermi levels are not aligned any more. Long story short, Fermi levels align only under equilibrium (applies to semiconductor-semiconductor junctions also)
Came for Schottky barrier, sat for the full lecture. Thank you sir!
i'm from Tunisia and i like to thank u alot for your explanation .. pls come to tunisia and teach our teachers how to teach .
hahahahaha broooo u jus killled me. hahahahaha
Andk hak Walh
😂😂
😂😂😂😂lol
Prof. M.R.Shenoy explained very simple language , I like this type of teaching . he explained like Prof H.C.Verma.
I ended up watching all his lectures! Simple yet so informative!
He is the best
This teacher can make someone pursue a PhD in semiconductor physics! Simply amazing teaching. Thank you.
One of the best teachers I have encountered.
Crystalline_Clear Explanation. Thanks you Sir, for such a wonderful lectures.
Simply the best. TOday is my solid state device exam and came for Schottky contact ; end up watching the entire video.
I love your teaching style and I love that you devoted your time for chalking on blackboard. Now I understand clearly about the Schottky and nearly Ohmic.
Thank you so much.
Well explained. Thanks so much! Regards from Salamanca, Spain.
I like this professor. He has lighter (almost none) accent!
awesome!
you did what my lecturer can't in just 1 hour.
Thank you!
Amazing explanation,simple language nd proud to have like this teachers in our country(India) and intitutions.
It didn't seem like an Hour lecture. Loved it!!!
tunneling explanation was the beauty of the lecture, excellent lecture
You are fantastic sir! I understood, finally!!
جزاك الله خير الجزاء
i can see complete dedication of this sir to draw multiple diagram to teach the students
You are fantastic!
Thank you much sir for this easy explanation.. regards from IIT Gandhinagar
He is so good at teaching, I can easily understand.
Good basics about Schottky and ohmic contact Thanks a lot iit.
Thank you sir, i learn more
Tqs sir your teaching manner is very clear and very easy
Excellent explanation! thank you so much professor!
Very nice explanation thank you...sir 🙂
Schottky starts at 21:30
Excellent teaching
Very good lecture
Greetings from Brazil
Sir, Apni BOSS....
8 yrs....still the best
Thanks sir for my concept building 🙏🏻🙏🏻👍🏻
awesome lecture ......very easy to understand
Very good lecture..clearing the doubts....
Nice explanation. Thank you sir!
Excellent Sir.
You are a great profesör thank you🙏
Thank you for your explanation Prof
Really great video! Thanks for uploading!
thanks a lot! now i know why the diagram looks like that in my lecture note TT
it is a very useful lecture. Professor, could you please advise in the case of junction between Au and In2O3? What metal is best for In2O3 so that I could get a very near Ohmic contact? Thank you very much.
Thank you Prof, very clear explanation
Thank you sir😄
Thanks sir 🙏
Very illustrative....,.
amazing content
Verey nice lecture and explanations
Thank you very much sir. Great explanation...
Thank you very much sir.
Fantastic lecture. Thank you
i like your explination thnk you sir good luck
thanks sir,it is very helpful to carrier builder
excellent!
Great detailed explaining.
Very intresting.
Very good lecture, Thank you sir
wonderful teacher.
Sir i want to know how p-type semiconductor form Schottky junction?
21:30
Impressive lecture
Interesting!!
very helpful, thanks a lot
Is the case where the work function of metal is lower than the electron affinity of the semiconductor like a 2DEG where electrons are trapped in potential well?
thanku sir,
7 years sir similar impact
Thank you professor
excellent
wonderful.....
Any of you know where to find a detailed explanation for p-type and metal Schottky junction?
49:50 when it is reversed biased, why is the fermi level of semiconductor and of metal not aligned? Please answer sir. Btw great lecture
1. When you connect two different materials (metal and semiconductor in this case) without any external bias, charges flow from one material to another until the Fermi levels align. This corresponds to the “Equilibrium energy band diagram”
2. When you apply voltage across a device which has achieved equilibrium, you add energy to (or subtract energy from, depending on the polarity) every energy state in the bulk of one of the materials relative to the other material. Hence, for this reverse biased case which you asked about, every energy state (Ec, Ev, EF and Evacuum included) in the bulk of the semiconductor moves “downward” in energy relative to the metal. (Note however that the energy levels at the junction are pinned) Hence, the Fermi levels are not aligned any more.
Long story short, Fermi levels align only under equilibrium (applies to semiconductor-semiconductor junctions also)
when there is no bias fermi levels on both sides are equal.when ever it is biased fermilevels on both sides become unequal.
Why does the discountinuity arise only for schottkey diodes but not for ohmic contacts?
wonderful
Thank you
Thanks a lot
In the end of the lecture the question that he gave Al and InAs with 4.4eV and 4.9eV, How it doesn't have any schottky barrier ? Isn't it 0.5eV ?
thank u sir
can you please provide Answer figure for the quiz ?
Great Great Great!!!
Very clean explanation but: what are the conditions to form a Shottky barrier for a Shottky diode? Can someone please tell me the answer?
Work function of metal should greater than work function of semicondictor
Brilliant
left side first row students don't like they are below 20
Why metal has high work function than semiconductor? As metal is conductive and according to phtoelectric effect it needs low energy to eject electron
Ur dumb
good
U first year ECE student?
Where I can find all lectures?
Please answer me
thnks awesome :)
can any one tell the name of the book please
christoph waltz tone at 16:11
Can someone share the answer to the quiz?
Can anyone share the answer to Quiz-5? (At the end of the video).
Can u give notes on this
Class lecture