Worked example: Determining a rate law using initial rates data | AP Chemistry | Khan Academy

The rate law for a chemical reaction can be determined using the method of initial rates, which involves measuring the initial reaction rate at several different initial reactant concentrations. In this video, we'll use initial rates data to determine the rate law, overall order, and rate constant for the reaction between nitrogen dioxide and hydrogen gas. View more lessons or practice this subject at www.khanacademy.org/science/a...
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[@mohamedalalami8936]

BRO thank u i couldn't understand my **** professor.

[@aliceofei2813]

omg thank you sm! this made 0 sense to me in class lmao

[@opufy]

7:27 RIP, my teacher would dock marks with a big smile for saying ".005 M" for sig figs because it's supposed to be "0.0050 M"

[@coolguy3513]

God bless

[@coolguy3513]

God bless again (exam edition)

[@Bulbasauros]

For u lazy bois out there u can do ( ln ((r1/r2) ) / ( ln ( [1] / [2] ) )
[ ☆ ] Concentration
1 and 2 is for experiment 1 and 2 not other substance
r stands for initial rate
Make sure the concentration of the other reactant stays the same and this will give u the order of reaction without any thinking necessary

[@nadeemakhtar3886]

What if we get a fraction?

[@boySomebody98]

hey, isn't 250 * 0,012^2 * 0,006 = 2,16*10^-4 ? (the answer to the last part of exercise)

[@kaonesebonego2510]

KvotheTheVegan Its to 2 decimal places

[@zekeskulski7146]

Anybody know where I can get some sample problems?

[@marciewalters143]

Zeke Skulski Do you have a text book? Usually in the chapter there are practice problems.

[@KM-wb1yd]

omg Can you be my chemistry prof please

[@salemalmuhairi4284]

:)

[@monikakhobragade1062]

Hi, if we arent given the experimental data how to determine the orders
and can you give an example of methane and air order of reaction
order of oxygen

[@PonzooonTheGreat]

I had a question where my rate constant units were mmol^(-5/2) L^(5/2) s^(-1)
How do I change this into the sensible mmol L^(-1) s^(-1)??

[@dazzlelight711]

what do you do if the rate determine step is the second step?

[@CassieGrey21]

What if you get something like k [Y]^ x [Z]^ y? The data gives me 2^x = 2.5. Then x would approximately be 1.322 to get 2.500 on the calculator. If I end up with k [Y]^ 1.322 x [Z]^2, would the order of Y be 1.32 or 1?

[@hammedyusrah4912]

Please you did not make use of the temperature

[@missmak559]

Asalam-O-Alaikum.....thank u sooo much......but.....isn't there anyway to find the order of reaction without experimental values???

[@JTurn916]

There is not

[@Jennieve_]

Is it possible to get the rate constant if one of the concentrations was never kept constant

[@sarakazi9451]

But what if we have no rates to compare to?

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exactly why i donate lol

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aderinsola abayomi clean your ears!!!!!