Subnetting - CompTIA Network+ N10-005: 1.3
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- čas přidán 21. 03. 2012
- THE N10-005 EXAM HAS BEEN RETIRED. See the latest Network+ videos at www.FreeNetworkPlus.com
Calculating subnets can seem a bit daunting at first, but the process is relatively simple and only requires basic math skills. In this video, you'll learn the subnetting process and how you can calculate subnets to fit your networking requirements. - Věda a technologie
It's actually hilarious to me. I took a networking class in college, and even later on another class for it because it interested me. I passed the class with an A in college and the same in the separate trade class. However, even though I could do the actions I never understood what I was doing until this video. Thank you so much.
This video was a better understanding of networking than a whole semester of Cisco at the community college
Professor Messer.. I really really want to thank that you teach this kind of lesson. I didn't understand this when I was having a cisco class(routing and switching) just 1 cisco.I think this part is one of the most important when doing a networking either by designing and implementing...once again professor THANK YOU VERY MUCH FOR SHARING YOUR KNOWLEDGE FREELY. now i understand them! hahahahah
Best subnetting video I have ever seen
a little complicated but I get it. I will need to watch this vid several times, work it out on paper while your doing it on this vid. awesome set of vids
Been cramming this and some testout practive test to help pass my Network+ this summer. Looking and feeling good so far. Amazing series.
The /31 is an interesting one, because the standards have changed through the years. A special case was made for /31 that would allow the use on point-to-point links which only require two IP addresses. Instead of burning valuable address space on a point-to-point link with a /30, you can use a /31 instead.
It's more accurate to say that the /31 can support two hosts based on RFC 3021, and I'll update future presentations with that caveat.
I love this video!!! Finally figured it all out!!!
Thank for very much - amazing video :). You always make things easy to understand.
Agreed. I've added some annotation to the beginning of the video that links to my Binary Math video. Thanks!
Why can there only be one subnet for a /24 subnet? Can't the network addresses range all the way from 0.0.0.x to 255.255.255.x?
Thanks professor for these great videos, but I would like to understand how did you calculate 65,534 hosts on the network? I do undestand that we have to substruct 2 for the subnet and the broadcast addresses but couldn't figure out the way you calcuated 65,536!
What exactly is a broadcast address?
at the 7:18 mark how did you determine the number of hosts on the network to be 65,534 ?
2 to the power of x - 2, where x represents the number of zeroes in
the subnet mask. 255.255.0.0 in binary has 16 trailing 0s. 2 to the power of 16 - 2 = 65,534
06;00
10.11.12.13 it's class A but here we used class B subnet mask is that okay to assign any subnet mask with private IPs or it is just for example here.
Thanks
How do you find the total number of hosts?
He also ended up getting an address with x.x.255.255 at the end. You can multiply the 255 * 255 to get the same answer.
How did you get 256 possible clients?
ok i get how you got the x2 for the host per network via following the trailing zeros
However how the heck did you fig out how many actual networks calculated?
RapidProgram You take the number of trailing zeros and count them. so in the 10.11.x.x example, there are 16 trailing zeros. You take 2^16 and get 65536. Then subtract 2 for the network and broadcast. So if you have a CIDR of /14, you would have 2^18 (quick CIDR math is 32 - the /number 32-14 is 18). addresses minus the host and broadcast.
Simpler math, take the 256 possible addresses per subsection (256.256.256.256 counting 0's), Using the same 10.11.x.x example, you can say that you take the 256.256 and just multiply 256*256 and get 65536.
+Michael Reynolds ....Still wondering what the answer to the actual question is here? ....How were the total number of Networks calculated? Thanks.
This video saved my life. Thank you!
Many Teachers direct student to Professor Messer He is Great Ill be taking my Net+ exam soon.
Good luck man!
Good luck man!
I still don't understand where 'minus 2' comes from. Someone help, please?
the subnet must have its own address, as the broadcast to, so you can't use them for hosts. From these two comes "minus 2". Look at 2:06
The minus 2 comes from subtracting from the first address and last
Networ.Network.Host.Host each octet is 255 so in this case last 2 octet for host 255.255 and from 0 - 255 =total numbers 256 each octet then 256 multilpy 256 =65,536 -2=65.534.
Had to have some coffee before watching this video. lol.
This is awesome but i still do not understand subnetting. I need to watch this video at least 5 more times...
Why do so many people who make these videos assume viewers know the base 2 numbering system. It has to be confusing for those who dont know it.
Subnetting is has been classless for twenty years. Subnet masks aren't required to strictly follow the class of the IP address.
I guess I figured it out, it is 2 to the power of 16 = 65,536 :)