ive been wondering how of organometallic can contain platinum, the most strong metal, is it possible? or there already like dimethyl or not dimethly platinum? like the dimethyl mercury, hm... confusing
There are plenty of organometallic platinum species. A very famous example is Zeise's salt, which features a platinum bonded to ethene. While platinum metal is generally unreactive (I'm assuming that's what you mean by 'strong'), you can get it to react. You just have to use some forcing conditions.
The titanium atom doesn't have a charge of 0; contributes 0 electrons. Titanium is a d4 metal; the 2 cyclopentadienyl (Cp) and 2 chlorine (Cl) ligands are all anionic, and thus influence the oxidation state of the titanium from d4 to d0, which is why it only contributes 0 electrons.
The number of electrons should be 16, because this is a square planar structure. Octahedral complexes usually contain 18 electrons, but these numbers can vary from time to time depending on the ligands, such as with olefins. He did count the Cl electrons; he write 2(Cl-) = 4 e's.
Thank you very much sir!
Thanks giving the great video.
Great vid! Thanks 👍
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Excellent
ive been wondering how of organometallic can contain platinum, the most strong metal, is it possible? or there already like dimethyl or not dimethly platinum? like the dimethyl mercury, hm... confusing
There are plenty of organometallic platinum species. A very famous example is Zeise's salt, which features a platinum bonded to ethene. While platinum metal is generally unreactive (I'm assuming that's what you mean by 'strong'), you can get it to react. You just have to use some forcing conditions.
I have some reservation on the way you compute TiCp2Cl2. Why is Titanium having a charge of 0?
The titanium atom doesn't have a charge of 0; contributes 0 electrons. Titanium is a d4 metal; the 2 cyclopentadienyl (Cp) and 2 chlorine (Cl) ligands are all anionic, and thus influence the oxidation state of the titanium from d4 to d0, which is why it only contributes 0 electrons.
could someone explain at 7:17, why is the iron a zero iron? thank you in advance.
CO is a neural ligand if we were to remove it, it would be neural CO
Can you help me to answer my homework in 18 electron 🤦🏻♀️🥺😭😭
Thank yu
, the number of e for TiCp2Cl2 is 18 as I think, why you didn't count cl electrons?
The number of electrons should be 16, because this is a square planar structure. Octahedral complexes usually contain 18 electrons, but these numbers can vary from time to time depending on the ligands, such as with olefins. He did count the Cl electrons; he write 2(Cl-) = 4 e's.
the symbol for lead is Pb not Pd.
Fe(0) is 4s2 3d6, not 3d8; and Mn(0) is 4s2 3d5, not 3d7?
d7 is representing the number of valence e-
When transition metals are bonded the 3d orbitals get occupied first, the 3d orbital becomes lower in energy than the 4s.
@@jakesmith6544 I'm studying for a test and bewildered by this because I haven't come across it in my lecture notes.
Pd is palladium d- block element
he made a little mistake, its supposed to be Pb not Pd
You meant Pb in the beginning, but wrote Pd
Thank you for your comment - I couldn't understand why he would call Palladium a p-block element.
Me tooo 😂
Iraq 😻