My first thought was add the areas of the 10x8 and 10x14 rectangles and subtract the 200 for the 10x20 rectangle. Love that there are multiple ways to get the same answer.
I did it like this: The unknown lenght of the rectangle is the same as the overlap of the 2 known lengths. I make a formula: 20 = 8 + 14 - X swap it up : x = -20 + 8 +14 add it up: x = 2 now for the rectangle: 10 * 2 = 20 sq. units
As soon as I figured it out (in my head and quite quickly), my assumption was that there must have been a trick somewhere Why was THIS heavily requested?
@@dorinsmith2033 Mind you when I did A level Maths the pass rate was about 45%, now it's 95%, I don't believe today's teenagers are twice as intelligent as I was lol.
I like to picture these questions where there are overlapping measurements as if they were planks. You saw the extra from one side so we can glue both sides together and have a little spare, in this case it's the rectangle's base. Add both overlapping values and get 22, so if you know the big rectangle's base is 20 you can tell the "extra" piece has to be 2. That helped me solve without calculating anything else, and it helps visualizing a lot more stuff.
I thought the 8 arrow included the shaded area. And the 14 arrow included the shaded area. First get the width of non-shaded area: 20-8= 12 and 20-14= 6. For a total non-shaded width: 12+6=18. Now to get the width of shaded area: 20-18=2. Now area of shaded: 2x10=20.
This one looks pretty simple. Add the 14 and the 8 and then subtract 20. This will give you what is overlapped between 8 and 14, which is 2, and that's the width of the shaded region. Then you just multiply it by 10, the height, and you get the area of 20.
A little overly complicated. Overall length is 20, minus 14 for the longer sub section, equals 6 left in the unshaded part of the smaller rectangle. Overall length of the smaller rectangle is 8, minus 6 for the non-overlapped portion, leaves 2. 2*10 = 20 sq units. No algebra required. Just simple logic.
I could do this intuitively just on a visual level but i appreciate seeing the algebraic approach to it, I need to be able to think in these terms more often. Cheers
The obvious way is to just calculate the length where it overlaps, but I also liked the mathematical solution since that's how we're gonna be solving shit 90% of the time
since the shaded area was where the 14 and 8 measurements overlaped I just took the remaining part that wasn't covered by the 14 distance and substracted it from the total so 20-14=6 , that is the width of the 8 distance that DOESN'T overlap with the 14, so to know the width of the overlap just do 8-6=2 and you have your X then just 2x10 as normal for the area
It is nice to see it solves it algebraically. For example if you were to try to abstract this into something generic that could be programmed to be calculated by computers. But I did the same as you to come up with the answer.
Is it possible that this problem is harder than it looks? Why are we assuming we're working with rectangles? Nothing is labeled as a rectangle. There are no angles marked as right angles. Is there a way to do this without making such assumptions?
i just labeled every part as x, y, and z we know: x+y=8 y+z=14 x+y+z=20 this means y+z+6=x+y+z, subtract y+z from both sides to get 6=x x=6, therefore 6+y=8, and y=2. A = 2*10 = 20
The algebraic solution is just superfluous; it's a waste of time. Both squares next to each other would be 22 units long, which means one was shifted 2 units to get to a situation where they're only 20 units long. The shaded area is 2x10. Problem solved, 5 seconds.
you couldve done it much faster like i did area = x*10 x = 20 - ((20-14) + (20-8)) = 2 So area is 2*10 which is 20 this can only work if they both overlap and stop at the corners
I’m even surprised you were requested with that
I bet the picture threw people off. The shaded area doesn't look like 10% of the area of the rectangle.
isnt it just 20 since the overlap should be 2 (from 14+8-20) and 2x10=20?
Yeah that's what I did, way easier
yeah lol i thought the same thing
I did that too. imo it is easier
That how he did, but using math as a way to show it, where you've included words
lol i thought this visually looking at the thumbnail to come see a more complex written out algebraic form lol
My first thought was add the areas of the 10x8 and 10x14 rectangles and subtract the 200 for the 10x20 rectangle. Love that there are multiple ways to get the same answer.
I did the same thing...😂😂😂
This one made me feel smart, which I appreciate because they usually make me feel dumb. Thank you.
Came here to post this same comment.
I did it like this:
The unknown lenght of the rectangle is the same as the overlap of the 2 known lengths.
I make a formula: 20 = 8 + 14 - X
swap it up : x = -20 + 8 +14
add it up: x = 2
now for the rectangle: 10 * 2 = 20 sq. units
I did it in my head and then spent 5 mins wondering why it was so easy, all you had to do was take 12 from 14 then multiply by 10.
As soon as I figured it out (in my head and quite quickly), my assumption was that there must have been a trick somewhere
Why was THIS heavily requested?
@@dorinsmith2033 Mind you when I did A level Maths the pass rate was about 45%, now it's 95%, I don't believe today's teenagers are twice as intelligent as I was lol.
Some kid asked to solve his school homework lol
I just did 20-14 to get 6 and then 8 - 6 to get the remaining 2 and then 2 x 10 for 20
I like to picture these questions where there are overlapping measurements as if they were planks. You saw the extra from one side so we can glue both sides together and have a little spare, in this case it's the rectangle's base. Add both overlapping values and get 22, so if you know the big rectangle's base is 20 you can tell the "extra" piece has to be 2.
That helped me solve without calculating anything else, and it helps visualizing a lot more stuff.
I thought the 8 arrow included the shaded area. And the 14 arrow included the shaded area. First get the width of non-shaded area: 20-8= 12 and 20-14= 6. For a total non-shaded width: 12+6=18. Now to get the width of shaded area: 20-18=2. Now area of shaded: 2x10=20.
That was exactly how I solved it. I feel like normally he does the easiest solution, but that seemed over complicated lol.
This one looks pretty simple. Add the 14 and the 8 and then subtract 20. This will give you what is overlapped between 8 and 14, which is 2, and that's the width of the shaded region. Then you just multiply it by 10, the height, and you get the area of 20.
my answer was:
14-8 = 6
8-6 = 2 = shaded area horizontally
10 * 2 = 20 square units which is the shaded area
A little overly complicated. Overall length is 20, minus 14 for the longer sub section, equals 6 left in the unshaded part of the smaller rectangle. Overall length of the smaller rectangle is 8, minus 6 for the non-overlapped portion, leaves 2. 2*10 = 20 sq units. No algebra required. Just simple logic.
i thought of it kinda like coordinates
20-14 = 6
0+8=8
8-6 (the distance between the points)=2
I could do this intuitively just on a visual level but i appreciate seeing the algebraic approach to it, I need to be able to think in these terms more often. Cheers
i cant imagine anyone actually finds this hard....
Since rectangles overlap then area if each consist area of needed small. So 10*14+10*8-10*20= needed area
The obvious way is to just calculate the length where it overlaps, but I also liked the mathematical solution since that's how we're gonna be solving shit 90% of the time
since the shaded area was where the 14 and 8 measurements overlaped I just took the remaining part that wasn't covered by the 14 distance and substracted it from the total so 20-14=6 , that is the width of the 8 distance that DOESN'T overlap with the 14, so to know the width of the overlap just do 8-6=2 and you have your X then just 2x10 as normal for the area
It is nice to see it solves it algebraically. For example if you were to try to abstract this into something generic that could be programmed to be calculated by computers. But I did the same as you to come up with the answer.
Is it possible that this problem is harder than it looks? Why are we assuming we're working with rectangles? Nothing is labeled as a rectangle. There are no angles marked as right angles. Is there a way to do this without making such assumptions?
X = 80 square units
Y = 140 square units
Z is the overlapping area
X+Y-Z=200 square units
Solve for Z and you'll get:
Z=20 square units
its my first math problem i did before you started explaining
This one was easy and unexciting
i just labeled every part as x, y, and z
we know:
x+y=8
y+z=14
x+y+z=20
this means y+z+6=x+y+z, subtract y+z from both sides to get 6=x
x=6, therefore 6+y=8, and y=2.
A = 2*10 = 20
You’re making it way too hard for yourself
The algebraic solution is just superfluous; it's a waste of time. Both squares next to each other would be 22 units long, which means one was shifted 2 units to get to a situation where they're only 20 units long. The shaded area is 2x10. Problem solved, 5 seconds.
I think the people who requested this were 6th graders
To make it a lot more simpler, move the shade area to the left of the rectangle, which gives us
X+20=8+14=22
X=2
Shaded area=10x2=20 unit square
Done.
I just did 20 - 14 = 6.
8 - 6 = 2.
2 x 10 = 20
8+14=22 and 22-22=2 after that you just make 2x10=20
Actually, that was one of the easiest problems I have ever saw
Gotta be one of the easiest
I feel like his method of solving was way more complicated than it had to be.
But the way he did it applies to a lot more different problems.
Pretty easy and all, but i cant solve it rapidly
20-14-6=2
Times 10 = 20
8+14-y=20
Shadow=yx10
Love from India 🇮🇳
This one was the first one I actually solved and got right! Love from India ❤
my stupid genius ass just did 14 + 8 = 22, 22 - 20 = 2
I just did 8+14=20+x which is still x=2.
Very easy 😅
This is so easy lol
ITS 20
Hmm, that is too much shallow and easy compared to your other videos
Прикольно! Снимите, пожалуйста, где ещё больше терминов по математике. Интересно как они переводятся на английский
So izi, 20 -14=6, 8= x+6,
8-x+14=20
x=2 :)
top gray = (8+14) - 20 = 4 done. 10x4 = 40 done. Why you used hard way?
you couldve done it much faster like i did
area = x*10
x = 20 - ((20-14) + (20-8))
= 2
So area is 2*10 which is 20
this can only work if they both overlap and stop at the corners
I took 8*10-6*10=20. Felt easy enough.