Coulomb's Law (5 of 7) Force from Three Charges in a Straight Line
Vložit
- čas přidán 5. 02. 2014
- How to use Coulomb's law to calculate the net force on one charge from two other charges. Coulomb's law states that the magnitude of the force between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. If the sign of the charges is the same, both positive or both negative, then there will be a force of repulsion between the charges. If they have the opposite sign then there will be a force of attraction between the objects. The force is along the straight line joining the two charges. The SI unit for the force is the newton.
The force between the charged bodies at rest is commonly known as the electrostatic force. Coulomb's law is an inverse-square law and is similar to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.
The law is named after the French physicist Charles-Augustin de Coulomb who first discovered it in 1785. The SI unit for electric charge was named after him.
This video can be shared at: • Coulomb's Law (5 of 7)...
Almost a decade later, and your content is still relevant to students. You helped me so much. Thank you deeply.
Happy to hear that and wishing you the best!
Thank you so much Mr Swarthout your tutorial video has actually saved my destiny.
I would have NEVER figured this out on my own. This was a big help for me. Thanks so much! Very simple and comprehensive.
+Sparxs II You are very welcome. Great that it was helpful. You can see a listing of all my videos at my website, www.stepbystepscience.com
Just stumbled along your video and it's helping me understand my class much more. Thank you so so so much for this video!
You are very welcome, thanks for watching and commenting.
I had no idea how to do this 15 minutes ago but now I understand! Thank you!
Great, thanks for watching and commenting.
YOU SAVED MY LIFE IM ETERNALLY GRATEFUL
Appreciate how informative you were!!
Kimberly Ann Great and thank you very such for commenting!
My professor went over it briefly but this reeeeeeally helped a lot! Thanks!!
Donna Herrera Awesome, thanks for commenting.
Thank you, very simple to understand and grateful that you explained every step.
That is why the channel is called Step By B´Step Science. You can also see a listing of all my videos by topic at www.stepbystepscience.com
Been looking at the text book for an hour lost on the example they gave, thanks for the clear explanation !
Great that you found it helpful, thanks for the comment.
Thank you so much! I was stuck on this question for a while you made it really clear and easy to follow :)
Great, glad that the videos were halpful. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you! I will definitely be using this great resource.
Thank you so much for doing this video :) You are a legend!
No problem, glad that you found the video helpful.
Great explanation. Keep up the good videos
This helped me understand my homework so much! thank you haha ive been stuck on these problems for awhile!
Merry Phan Great, hanks for commenting and good luck with the homework.
Bro thank you so much. My teacher sucks and wasn't helping me at all and this is the only video i found which actually answers my question perfectly so thank you so much.
You're very welcome, glad to be of help.
Thankyou...m literally loving your videos....
+asma syed Great and thank you for the positive comment.
You can a listing of all my videos from my website, www.stepbystepscience.com
Ur Explanations are simply awesome....
Thanks for saying so...You can a listing of all my videos from my website at www.stepbystepscience.com
This video was incredibly helpful, thank you.
Sorry to be offtopic but does someone know of a trick to log back into an instagram account?
I was dumb lost my login password. I would appreciate any help you can offer me
@Salvador Keaton instablaster :)
@Boden Raylan thanks for your reply. I got to the site thru google and I'm waiting for the hacking stuff now.
I see it takes quite some time so I will reply here later with my results.
@Boden Raylan DAMN IT ACTUALLY WORKED :O Literally hacked my IG account details after ~ 30 minutes of using the site.
Just had to pay 15$ but for sure worth the price :)
Thanks so much, you saved my ass!
@Salvador Keaton happy to help :D
Awesome vid thanks so much!
This has been a very helpful video! You do a very good job of explaining the terminology at a pace for beginners like myself! Than you!
You're very welcome! Glad the video was helpful.
Thank you, I find this lesson so easy. This will help me for the test tomorrow
Best of luck!
what i like about your vids are nice visual presentation and a great explanation!
keep it up
thanks a lot!
Thanks for the comment, I try to make the presentations nice to look at with simple step by step instruction. In fact you can see a listing of all my videos at www.stepbystepscience.com
Definitely what i meant!
thanks i will
Tq so much. Your explanation is very clear and perfect. Apart from that, thanks for those extra tips as well 😇
Thanks for the great comments.
I love your vid. tmr I'm having my physics test on this topic. hoping that I can do well. wish me luck! 😁
oned ned I wish you lot of success on the physics test.
Thank you!! what do I need to do to find the distance Q2 needs to be from Q1 to have a Fnet=0. In other words the distance for it to remain stationary.
thank you very much! I'm not good at mathematics, physics or anything that numbers involve so this is very helpful! I have a question tho, its also about coulombs law. What if the only given is the force attraction between positive and negative charges? we have to find its distance but to do that, we need the charges of q1 and q2. And seeing that the only given is the force attraction, well, I dunno what to do and where to start.
Always concise Doc. Your the best. B :)
Thanks again.
great work, very clear and helpful thank you
+Salem Alotaibi Thank you very much for the positive comment!
Omg! This vieo is the best!! Thank you!
You're welcome!! Thanks for commenting.
Thanks man you really helped me with this top video.
Glad I could help, best wishes
Thanks so much man
you explained so good that my concept is cleared
Great and thanks for letting me know.
Brilliant!
very helpful. nice one.
Was very helpful
Thank you. I have recommended that my distance learning students watch your video.
Excellent and thank you!
Thanks, you have been a very big help
Glad to hear it, best wishes!
Thank you for providing step by step instructions. First day in my phys I was already considering dropping and need this course to move into PT school. So step by step and problem by problem I will be on your site as our teacher knows his stuff but skips the steps and leaves us not of the math world wondering what happened on the board!
Don't give up on the first day, stick with it and your confidence will grow. Good luck and thanks for the comment.
Hoping that I can sit through class take notes and then make sense here of step missed!!!
this really helped thanks
u saved my life. thank you
Any time. Thanks for watching!
love it ❤❤❤❤
Great video, just one question. Why did we neglect the force F12
Thanks ...making it easy to comprehend
Glad to hear that, you are very welcome.
very nice i understand this explanation more than my prof's explanation
thank you very much!!
You're welcome!
Thank you very much, I have physics exam soon. I have a question, does this equation aply always ? Or does it change as we move one of charges ?
Good question, not it is always the same equation. If you have more then two charges then you have to apply the equation to each pair of charges and then add up the total force. Thanks for commenting.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Thanks...شكرا ✨💖
Thanks a million. This lecture seems very helpful but could i also have some practice problems?
Thanks for the comment, there are a couple of practice problems available in the following videos that you can see on my website. You can see a listing of all my videos at my website, www.stepbystepscience.com
Pog video my dude 😩
Why tf do they even teach this in school.
🤣
Thanks so much for this but just one question. If calculating for the particle in the middle, of their is an opposite charge on one side and a similar charge on the other (effectively pushing it in one direction since on repels and the other attracts) do you just add the forces together?
Yes, you just add the forces...but you have to make sure that you are correctly considering the direction of the forces. By convention, forces that are to the left are negative and forces to the right are positive.
Step-by-Step Science thank you so much!
When determining the direction of the forces, is F31 going to the right because -8 is greater than -16? I know that because both have negative charges, they are repulsive. I don't understand why it goes to the right. Does F32 go to the left because 6 is greater than -8?
you sound like kevin from the office. thanks for the video
what about finding 1 distance between 3 points with 2 charges given and 1 distance given
Thank You Thank You sir
Thank u so much!
Welcome!
very helpful. thank you
You are very welcome and thanks for commenting.
If you were looking for the magnitude of this net force, would it give you a positive answer even though it would still be directed towards the left?
(I'm just confused with the signs)
@Stephanie Hernandez, the magnitude is always positive, so to speak. the sign tells you just the direction of the force.
Thank you 😊💕
You're welcome 😊
How hard would it be to literally just be like "here is the equation." These examples are completely useless when there's no direct connection to a specific variable. I've watched this like five times and I still have no idea what's going on but this is what my teacher assigned me to learn from.
????? I am a bit confused. That is what I did here is the problem and here is how you find the answer.
Hi ... thank you for sharing your work & skills with us. You left me wanting a bit more out of this problem, though. we only found the net force on Q3, though. What's going to happen to Q1? It is also influenced by Q2 and Q3. and since Q1 and Q3 are both like charges, and therefore repelling, which one is going to win out and be attracted to Q2 in the end, thereby neutralizing the charge on Q2, and then what happens to the other electron? Fun stuff to think about! :)
Great but the question is specifically asking us to find the net force on Q3. So Q3 is the reference point.
Saved my exam!!!
hope it goes or went well. thanks for the comment.
Great video
No problem, glad that you found the video helpful.
How do we solve this problem if the distance between one of the particles is unknown?
Perfect explanation 😊
Glad you think so, thanks so much!
Your video is very helpful
Glad you think so!
great!
sir if there are three charges of the same magnitude (say all are positive), all are in the same line and the charge which is in between, is in equilibrium ,then is it necessary that the other two charges should be fixed at their places in order that they can' t be displaced ( since all are positive charges)
Thank you
You're welcome
thanks for this brief video, twas really helpful though.........
Great.
thank u sooo much....good jop
Hi sir I am from India.i like your video
Thank you to India from Berlin Germany
I would like this video 1000 times if I could💯
That is very nice of you to say, thanks for watching and commenting.
Helpful!
Thanks
Great Video
Thanks!
In this problem,are we calculating the net force on q3?
thank you :)
+Mohammed Al-Bashiri Thank you again.
Nice presentation
jobayer abir Thank you, it took a little while but turned out pretty good.
But what if it has the same force going both ways, making it equate to zero? What do i do then?
Nice video. Do you have one like this where the charges are also different sizes?
+saraa uh Thanks for the comment. I am not sure I understand, the charges in this video are all different. Do you mean charges that are not point charges? You can see a listing of all my videos at my website, www.stepbystepscience.com
like this picture is what i'm talking about. Where the charges are different sizes
www.webassign.net/walker/19-30.gif
+saraa uh I am really sorry but I must be missing something. The charges in my video are also different sizes; -16, +6 and -8 micro coulombs.
Thankssss it helped me
Great and thanks of right comment.
I have a question . Do we subtract the forces when they attract each other or do we add them up ?
Add them up when they point in the same direction, subtract them when they point in opposite direction.
If there were 5 or 6 charges, should I take the total magnitude of forces pointing in one direction and subtract from the total magnitude of forces pointing in the opposite direction? Also how do I determine which direction is negative? Thanks
Yes, you just add up all of the forces. By convention in math and science positive is up and/or to the right, negative is down and/or to the left. You can see a listing of all my videos at www.stepbystepscience.com
Thank you sir. My question is, are attractive forces positive or negative? And does it mean that all vectors going to the right are positive and those going to the left negative? I'm really get confused on this part. Make me understand the concept here sir. I appreciate your videos are loud and clear. Give me a link so that I watch the whole series on coulomb's law. I thank you.
Attractive and repulsive force can be either in the negative direction or the positive direction. It depends on the charge of the other particles. But yes, by definition, forces to the right are positive and forces to the left are negative. Does that help?
Appreciate
Do we have to calculate F21 as well?
I think you could have shown the force F21 as well, because it's value will differ than the Force acting between charges Q3 and Q2. Anyways, amazing explanation.
Yes, but I just wanted to focus on that one problem. Thank you for the comment.
Just to be certain, would you get the same results if you calculated the Force from Q1,2 and Q1,3? In your video, you calculate the sum of the Forces of Q3,1 and Q3,2.
+Tammy Bush I am not exactly sure what you are asking but I think the answer is yes. If you have only two charges the force on each is the same but the direction is opposite. Does that help?
You make me get 10 out of 10 ...... 😍 thank u
Thet hepen to me
That's fantastic!
thx
Three point charges 1.0 µC, 0.10 µC and 10.0 µC are placed on a straight line
and net force on 0.10 µC is zero. Find x in cm.
I thought negative charges have forces acting inwards
what if the charges are all positive??
nice presentation. please let me know what software/webtool you used for this
Shpresa Ahmeti everything is done right on my MacBook Pro with the preinstalled camera, keynote and quicktime.
nice
THAAANK YOU
You are very welcome.
Why did you use 0.9 in d in F31?
the first charge is negative the Q3 why did you not include the negative sign?
Good question. When we use the equation to calculate the magnitude of the force we do not include the signs of the charges. The magnitude is just the amount of force, the sign of the charge does not matter. The amount of force will still be the same.
We use the signs of the charges to determine the direction of the force. Opposite charges attract and like charges repel. Does that answer your question.
You're a fucking lifesaver chief, i have a physics final on Thursday on this stuff and you helped me a lot!
Hope the test goes well!
What do you do if you do not know if they are positive or negative? I.e it hasn't been stated what charges they have.
Maybe that would imply that they are positive. Often you would not say the charge is positive 3 Coulombs just 3 Coulombs.
Oh I see, thank you.