Coulomb's Law (6 of 7) Force from Three Charges Arranged in a Triangle
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- čas přidán 7. 02. 2014
- How to use Coulombs law to calculate the net force on one charge from two other charges arranged in a triangular shape.
Coulomb's law states that the magnitude of the force between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. If the sign of the charges is the same, both positive or both negative, then there will be a force of repulsion between the charges. If they have the opposite sign then there will be a force of attraction between the objects. The force is along the straight line joining the two charges. The SI unit for the force is the newton.
The force between the charged bodies at rest is commonly known as the electrostatic force. Coulomb's law is an inverse-square law and is similar to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.
The law is named after the French physicist Charles-Augustin de Coulomb who first discovered it in 1785. The SI unit for electric charge was named after him.
This video can be shared at: • Coulomb's Law (6 of 7)...
Honestly big props to you. You make people not feel dumb coz you just explain it so well and simply and eloquently without showing too much unnecessary complexity. Something a lot of my professors lack hence making people feel stupid and get discouraged all together
Thanks, my goal is always to make the explanations as clear and simple as possible.
Please never stop making these kinds of videos. You have explained something very nicely in 11 minutes that my teachers took 3 days to do.
Thanks for the great comment
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I felt like an electron until I found your videos
Thank you and may God bless you
Merna Chaldo That is perhaps the nicest comment I have ever received! Thank you!
=)
For once in my entire 21 years of living, I am finally starting to understand physics. Thank you!
Excellent! You're most welcome.
Guess what? you are the best explainer I have ever seen!!!!!!. Thank you so much for taking time to explain critical objectives and explain how to solve them easily. Thumps up!!!
that is very very nice of you to say. thank you for the comment.
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thanks for the positive comment, hope the test goes well
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You are very welcome!
Thank you so much, I just began physics 2 and I want to get a good understanding of the basic principals of electric forces, since the remainder of the lessons build on these concepts.
Glenn Meeker You are very welcome, have fun in class.
after spending a really long time trying to find out how to get the solution to the same question with different values, yours was definitely the most helpful! thank you!
Great that it worked out.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you Vin Diesel
+SP P You are very welcome….I am currently between The Fast and the Furious shootings and have decided to dedicate my free time to Physics. If you are interested….You can see a listing of all my videos from my website, www.stepbystepscience.com
Thanks, Brian. I'm in second semester of general physics and this has been very helpful.
You are very welcome, thanks for the comment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
This helped so much, thank you! Really good, clear explanation.
+Trent Harris Thank you very much, my first goal is to always be clear and concise and right to the point.
You can see a listing of all my videos from my website, www.stepbystepscience.com
Thank you so much for this, it's really helpful ^^
Also, at around 8:30 you mentioned about using the cosine. Forgive me if I'm wrong, but you can find F31x by using a Sine rule as well right? As in Sin90/4.38x10^-7 = Sin53/F31x
Your graphics are very good too. My son has started a physics degree here in the UK and I have pointed him in your CZcams video direction.
+Dave Brabner Great, thank you very much. He can find a listing of all my videos at my website, www.stepbystepscience.com. Where is he studying? We live in Germany and my son may be going to Scotland to study next year.
omgggggg why couldn't i have found this channel two weeks ago haha job well done!
+bryce lovett (wutlawl) There is still time.
You can link to all my videos at my website: www.stepbystepscience.com
bryce lovett same here 😂😂😂 I ruined my life panicking in those two weeks
As always, thank you for the amazing video :)
+Mohammed Al-Bashiri And again thank you!
Thank you so much for these explanations! I can't express enough how helpful the videos were...and btw,your voice sounds like Vin Diesel's voice! ;D
Luca Lima Great, it is usually either Vin Diesel or Vince Vaughn's voice. Funnny. Thanks for watching and commenting.
I can't thank you enough for your videos sir.....blessed to have you here....
+asma syed You already have….
You can a listing of all my videos at my website, www.stepbstepscience.com
+Brian Swarthout
Busy with exams these days.... But surely will after my exams 👍
thanks a lot this has been very helpful and easy to understand!
Great and thanks of the comment.
This video helped me tremendously! Now I have to have my son watch it ( I don't like having to relearn stuff from 30 yrs ago lol)
Thank you for the nice comment, yes it is all in the family.
Thank you! Your video was very helpful!!! :)
Kim Taylor Martinez Great, this one of my favorite videos, thank you for commenting.
Great video. Someone said you sound like Vin Diesel, but I think you sound like Lanny Poffo aka "The Genius".
Thank you so much. Going for computer engineering but i suck at physics. you helped me alot on my traditional hw. and most likely on my exam
TheShanaList Thanks for the nice comment, I wish you lots of success in your studies..
This video was nice and dont stop making these
Thanks for the great comment and the support.
Thank you for the video !!!
My pleasure, thanks for watching!
Thank You!
great explanation kind sir.
Thank you
thank you it was helpful, what if the charges were not the same magnitude and the third charge was closer to the smaller charge can you kindly work and example as such
thank you so much, this was helpful
You are very welcome.
sir, i wanted to know what woul be the force on EACH ELECTRON if the Q3 was positive(+)
thank you so much for describing this so clearly, i've subscribed and ill be sure to tell my friends about your videos :). keep this up !
+Lifector • You are very welcome, thanks for letting your friends know. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you!
You are very welcome, thanks for commenting.
Find the magnitude of the resultant force on a charge of 1 μC held at P due to two charges of +2 x 10 C and -10 C at A and B respectively. Given AP = 10 cm and BP = 5 cm. ∠APB = 90°
Good Day! When given Q1 & Q2 have different values, What if F32 is not equal to F31, How can you compute F total?
Where did you get the 37°?
What I mean is that, how can I find it, if that is not given or shown in the problem?
How about when you need to find the net force that acts in q1?
Thank you Dustin Hoffman
Just hanging out with Mrs. Robinson.
Thanks so much :)
Thank you!!!!!
You're welcome!
Thank you sir God bless You abandonedly l am proud of you
Thanks for watching and commenting. You can see a listing of all my videos at www.stepbystepscience.com
Really good video man
Glad you think so! Thanks for the comment.
Very clear explanation - thank you
+Dave Brabner Thanks, I try to go over everything step-by-step…in fact you can a listing of all my videos from my website, www.stepbystepscience.com
sometime, angles are not given, so how to find angles?
wow. you are amazing! but do you do videos on deriving equations in this topics?
+Guru prasad Thank you but I do not have any videos on the derivation of equations.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Believe or not
you are better than my prof 😍😍😍
Thank you💪🏽
Any time!
How would you fine the magnitude of the net force now?
Thank you very much ^_^
if you're finding the electric field between q1 and q2 do you factor in q3?
+scott caron Yes, every charge contributes to the field.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you so much I love youuu🥰🥰
You’re welcome 😊
Given: q1= 3nC, q2=2nC, q3= 6nC, same figure as your illustration here. What is the magnitude and direction of the electric force acting on 6nC. Dist between 2 charges is Square root of 2. thank you so much
And the angle is 45 degrees since this is an isosceles triangle
What if you don't know the value of Q3?
I don't understand why the arrow goes away from negative isn't the arrow suppose to come towards the negative
The arrow represents the force, two negative charges will repel each other so the force is away.
What if the Q3 has no value? It's not given?
👍 Forces at work..
This should work for an equilateral triangle too right?
Yes, it should work for any triangle, you just have to adjust your calculation for the different angles.
Well explained
Thank you.
what would happen if Q1 and Q2 have different magnitude and what if the triangle is equilateral triangle
The process is the same, you just have to abject for the different charges and angles.
agh i shouldn't have take grade 12 physics in the summer... thank you for the help bro
That must be hard....You can see a listing of all my videos at www.stepbystepscience.com
Step-by-Step Science somehow finished the course with an 85 thank you for the videos
What if its a right triangle? Do you have a video on that?
Austin Haikes Sorry but I do not. But of course all of the same principles apply.
A listing of all of my videos can be found on my website: www.stepbystepscience.com.
Hello, can do this question, by find the force on q2?
yes
Life savior
Thanks for the comment.
What if F31 not equal to F32?
why the value of nanocolounbs became x10 raise to -9? our professor taught us that it is -6 not -9.
+05jddc Good question, milli- is x10-3; micro is x10-6; nano is x10-9. Does that help?
You can see a listing of all my videos at my website, www.stepbystepscience.com
yes thanks! i did not see that coming lol. i did not notice the difference between nano and micro last time but now i know. :) thanks for the info! :)
I'm learning
Fantastic!
He's at Kent, funny, but he was thinking of taking a year out in Germany before starting his degree.
What if you don’t have the angle
Then you need the forces to get the angle, or there must be another way to get the angle.
From your value of F31 = 4.38*10^-7
And total angle is 74°
I used the formula
R = A√(2 + cos theta )
And i got resultant force
6.67*10^-7
Is this correct??????
Is that different than what I got?
Your answer is 7*10^-7 newton
But mine is 6 .67 *10 ^ -7
Did i have made any mistake
I use Resultant between two force formula
..
Which is
R= √(A^2 +B^2 +2ABcos theta)
Help... 😗
Best
Thank you!
Hi, what if they the charges are not arranged in a equilateral triangle?
+Peter Tran Then it gets a little more complicated and you probably have to use a some trigonometry to figure out the resultant direction of the force. You can see a listing of all my videos at my website, www.stepbystepscience.com
please solve this
suuuuuuuuupeeeeer
Great and thanks for commenting.
I don't get why u don't need to put negative signs, please send help
Because when you use the equation you are only finding the magnitude of the force. No the direction.
@@stepbystepscience ah I see, were not going to use the î... Thanks for clarifying x
Thank you