Passive and Active (Sallen-Key) RC Filter Operation and Design

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  • čas přidán 6. 07. 2024
  • An introduction to passive and active low pass filters, filter requirements and design concerns, and the evolution from a simple single-pole RC filter to a multi-stage Sallen-Key topology.
    Links and references at: www.analogzoo.com/?p=1090
  • Věda a technologie

Komentáře • 51

  • @zanecook4402
    @zanecook4402 Před 4 lety +7

    This is one of the best electronics videos I have seen. Fantastic explanation and the design tool you showed is definitely going in my bookmarks.

  • @emcgon
    @emcgon Před 8 lety +25

    The best filter tutorial I have ever seen - thanks.

    • @Analogzoo
      @Analogzoo  Před 8 lety +2

      +emcgon Thanks! Be sure to check out the videos Matt Duff (from Analog Devices) did; there's a bunch of them, all very good.

    • @sain8827
      @sain8827 Před 7 lety

      I second that. Very well explained and thought out. Will check out Matt Duff as well. Thank you!

    • @magerehenk7579
      @magerehenk7579 Před 7 lety +2

      I suppose you had to filter through a lot of tutorials to get here eh?

    • @piscopatos
      @piscopatos Před 4 lety

      @@magerehenk7579 i see wht u did there :)

  • @royjacqvanstraeten668

    I wish ..you made more of these filter topics...thank you

  • @etofigh
    @etofigh Před 8 lety +3

    Perfectly explained! You sir have my gratitude.

  • @Infinitesap
    @Infinitesap Před 2 lety +1

    Incredible video you did here. So easy to follow even though it's very complicated. tells a lot about your skill level.
    I learn do much from your stuff. Please make more videos 😉

  • @khalidabduljaleel
    @khalidabduljaleel Před 5 lety

    One of the best videos I have seen in a while 👍

  • @hubercats
    @hubercats Před rokem

    Great presentation! Thank you.

  • @PapasDino
    @PapasDino Před 8 lety

    Thanks Craig for a great tutorial!

  •  Před 8 lety +4

    excellent! keep them coming.

  • @alejandrosantiago6080
    @alejandrosantiago6080 Před 4 lety

    Thanks for the clear explain and the examples ! ... keep it up mate

  • @CyrilleBoucanogh
    @CyrilleBoucanogh Před 2 lety

    You are genius in teaching! Thank you!!!

  • @niranjankumarkannaujiya9743

    Thank you so much for this video.

  • @fer_fdi
    @fer_fdi Před 2 lety

    Excellent! thank you very much. Very clearly explained.

  • @amazagx
    @amazagx Před 2 lety

    Excellent!! Great!!
    Thank you!!

  • @trevorvanbremen4718
    @trevorvanbremen4718 Před 3 lety

    BRILLIANT video!!! The ONLY possible thing missing is that you never showed an FFT scope plot of the 10kHz sine wave. SUBSCRIBED!

  • @3cu14rs
    @3cu14rs Před 8 lety

    Nice, thanks a bunch. Would appreciate a similar guide for multi stage passive filters if you ever felt like it.

  • @jdennee
    @jdennee Před 8 lety

    Nice video!

  • @4a4ik
    @4a4ik Před 8 lety

    Great tutorial, thanks a lot! :D

  • @peternotpeter
    @peternotpeter Před 3 lety +2

    Loved this video, its very well explained and easy to understand. I wonder if you would be able to do a voltage control filter based on OTA LM13600/13700 ? I'd be very interested. thank you again and keep up the excellent work.

  • @neuralnetwork653
    @neuralnetwork653 Před 8 lety

    nice video! Thank you

  • @saarboaz123
    @saarboaz123 Před 3 lety

    nice! thanks!

  • @user-bz7ki7dl1r
    @user-bz7ki7dl1r Před 3 lety

    Very good video. Thank you for sharing. May i ask a question: why the magnitude do not go lower than -60 when frequency continuously increases?

  • @SureshKumar-nk2ok
    @SureshKumar-nk2ok Před 4 lety

    thank u very much sir.pls suggest for power supply filter for 100hz cuttoff

  • @wilmdrdo1228
    @wilmdrdo1228 Před 4 lety

    Great anal llysis my frend

  • @phillipneal8194
    @phillipneal8194 Před 18 dny

    Great presentation. Thank you. What about slew rate at 14 Mhz ? What do I use for an op-amp ?

  • @byronwatkins2565
    @byronwatkins2565 Před 3 lety

    A narrow band pass filter could do this in a single stage. The possible disadvantage is matching the peak frequency to 10 kHz, but it is also necessary to match the cutoff frequency in your design.

  • @amirb715
    @amirb715 Před 5 lety

    Did you just connect the filter directly to the SA? I am asking because the filter does not have 50 ohm input/output impedance. The input impedance is in kohm range and out put must be a few ohm only. How did you calibrate the SA and TG?

  • @fer_fdi
    @fer_fdi Před 2 lety

    Question here: on a S-K filter "cell", the op amp is working just as a buffer? COuld it be exchanged for a transistor buffer o even a tube buffer?

  • @CyrilleBoucanogh
    @CyrilleBoucanogh Před 2 lety

    Can I ask a question? What price are we paying when adding capacitors to make the frequency response more even? Is it more ringing effect. right?

  • @gowrangakrishnamurthyhanas9677

    Nice tutorial. Thanks. Suppose I have a non-sinusoidal periodic input and am interested in filtering out the Fourier dc(average) component of the input through hardware, kindly suggest how I should go about the design

    • @Analogzoo
      @Analogzoo  Před 6 lety

      If you just want the DC value of a signal, you'll want to remove all signal components whose frequencies are above zero hertz, so you'd want a low-pass filter. What cut-off frequency you choose for your low-pass filter will depend on the frequency components of your input signal, as you want to attenuate all those components as much as possible. Note also that a low-pass filter is effectively an integrator in the time domain (think of a simple RC filter), so generally the lower your cut-off frequency, the longer it will take for the filter to settle on the DC value of the signal.

    • @gowrangakrishnamurthyhanas9677
      @gowrangakrishnamurthyhanas9677 Před 6 lety

      My understanding is that in a low-pass filter, when dc and lower
      frequencies are passed from input to output, the capacitor facilitates
      this by slowly getting charged. In order to meet a very low cut-off
      frequency requirement, let me assume I use a very large time constant
      (RC) which, let's say, is larger than the period T of the input
      signal. During each positive excursion, the capacitor will try to
      charge towards the peak value, though slowly, but will lose very
      little charge before the next positive excursion arrives. Does this
      not mean, the capacitor will not average out over time but instead
      keep riding on the peak . If on the other hand, I am restricted to use
      a RC time constant which is lesser than T, I will have no freedom to
      choose the theoretical maximum RC time constant. Kindly let me know
      if my understanding is correct. Thanks.

    • @Analogzoo
      @Analogzoo  Před 6 lety

      You state that the capacitor "will lose very little charge before the next positive excursion". This suggests that the capacitor discharges more slowly than it charged. If you apply a signal, say a sine wave, to an RC low pass filter, why would the capacitor charge at a different rate than it discharges?

    • @gowrangakrishnamurthyhanas9677
      @gowrangakrishnamurthyhanas9677 Před 6 lety

      The charge and discharge time of the capacitor is assumed to be the same. I consider a saw-tooth wave where the sweep time from 0v - peak (say 10v) takes 7T/8 secs and the fly-back period lasts for T/8 secs. If the charge and discharge time constants (RC) is comparable to 7T/8 secs, the capacitor will have sufficient time to charge to the peak value while getting only T/8 secs to discharge, before the next cycle starts. So, while RC will give the rate at which the capacitor will charge or discharge, the actual level to which it has come down on discharging will be determined by the fly-back time, viz. T/8 secs. Assuming it has lost only 2v before the next cycle started, the average value will be (10v+8v)/2 = 9v. On the other hand if I had allowed the fly-back period period of T/4 secs for the capacitor to discharge, the average would have decreased further. My question is, without caring for such variable average values dictated by the time periods of the impressed signal, how do I recover the true Fourier dc component present in the impressed signal. To cite another case, I want to know how I can recover the Fourier average of a full wave rectified signal whose average is some finite quantity and not zero. The charge and discharge time constants are assumed same and equal to T/4 secs. Thanks.

    • @Analogzoo
      @Analogzoo  Před 6 lety

      An RC low pass filter is an integrator, thus with the correctly selected R and C values it will give you the average of your input signal. In your example of a 0-10v sawtooth wave, the center of that sawtooth is 5v. Being a symmetrical, periodic waveform, the sawtooth spends just as much time above 5v as it does below 5v, hence the average of that signal is 5v, which is the DC component of that waveform. If you generate a 0-10v sawtooth signal with a function generator and feed it into an appropriate RC low pass filter, that's exactly what you'll see. Change the signal to a square, triangle, or sine wave, the average remains the same.
      When you say "without caring for such variable average values dictated by the time periods of the impressed signal, how do I recover the true Fourier dc component", I assume you mean that you want to get the average voltage of the signal without caring about the frequency of the signal. The answer is, I don't think you can. Integrating a function over some period of time gives you the average, but different frequency signals necessarily complete their cycles over different time periods. For example, the period of a 10MHz signal is 100nS, so 1mS would be more than enough time to see many periods of the signal and determine its average value very accurately. A 1Hz signal on the other hand wouldn't complete even one cycle in that same 1mS time frame, so you wouldn't be able to accurately determine its average value.
      So, if you know that your input signal is of a higher frequency, then you can make your R and C values smaller, and thus obtain your average DC voltage faster. But if you must accommodate very low frequency signals, then your R and C values will have to be larger, and it will necessarily take more time to get the average DC value that you're looking for.

  • @phillipneal8194
    @phillipneal8194 Před 5 měsíci

    Do Sallen-Key active filters work at HF frequencies 3-30Mhz ?