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Linear Algebra 34 | Range and Kernel of a Matrix

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  • čas přidán 14. 08. 2024
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Komentáře • 6

  • @MichaelWilliams-ow9ue
    @MichaelWilliams-ow9ue Před rokem +3

    I was literally thinking about kernels right when I saw that this video had just been uploaded four minutes ago.

  • @MrWater2
    @MrWater2 Před rokem

    Sorry I didn't get what to prove where ran(A)=span(a1, ..., an). Is it not just a definition? Because the range define as Ax is the linear combination of the columns of A with x in the domain (Rn). And the span it's just the set of vector u in Rn (if M is in Rn) such that there are lambdas_j in R and u_j in M where every u can be write as a linear combinations of another vectors u_j. So the u_j are the a_1, ..., a_n and the lambdas are the x_i, ..., x_n so every vector u can be write as linear combination of the vectors of A. Am I correct?
    Mmm! Also if A is not Linear independent suppose Rk with k

  • @user-eo5gv9zn8m
    @user-eo5gv9zn8m Před rokem

    What is name of your whiteboard you use ?