@BattleToad ,This is awesome to hear. I hope you pass the PE with flying colors! I’m not as consistent though as i should (sorry about that, working on it) but there are a few PE vids available already. Let me know what you want to see more of and will do my best.
Great content. Insightful and coherent explanations with good pace and diligent procedural steps that you share with the audience in a genuinely helpful manner. God bless you for uploading these instructional tutorials.
@@allychildress905 Adding to what you said: A circuit is the sum of its weakest part; you need to also determine the terminal ratings(of the equipment) and the overcurrent protection device used. You must choose the column for whichever rating is lowest.
Always round up until you exceed 800A. Then the wire must meet or exceed the breakers rating. A calculated 64A load would require a 70A breaker on #6 copper.
You want the breaker to trip before the cable burns up. You would round down to 60 A breaker, otherwise the cable will overheat, that is the purpose of these calculations - finding out the d ration due to temperature.
@@KJVNHVN I was curious since yourself and beeps were giving two different answers so I had to do some looking. NEC 240.4(B) says the next higher standard overcurrent device rating (above the ampacity of the conductors being proctected) shall be permitted to be used
They have changed the table numbers, I use 310.16. Same Info its just worded a bit different and the temp rating of the table is now in the actual text not listed at top of the table. So 310.16 states that TABLE 310.16 is based on 30 degrees C. Read the notes under table 310.16 and it tells you where the temp correction and if you have more then 3 conductors in a conduit correction tables are.
an engineer online says that if the wire insulation is rated for 600v use 310.15(b)(2)(a) and if the insulation is rated for up to 2,000v use 310.15(b)(2)(b)
if it is over three conductors would you find the right ambient temperature just how you did in the video except you would multiply your answer by whatever the number is for your conductors so if you had 4 conductors it would be your answer times .80?
My question would be why do we apply temperature correction factors at all? I understand the math but can you give an example of a real world scenario where you would need to do that, change the ambient air rating of 30 C to said temp?
thank you for explaining regarding the table to use, 60, 75 or 90, that makes a great difference
Raiya Academy vids....helped me with my FE....now helping with procuring my PE! Thx for the continuing your informative lessons.
@BattleToad ,This is awesome to hear. I hope you pass the PE with flying colors! I’m not as consistent though as i should (sorry about that, working on it) but there are a few PE vids available already. Let me know what you want to see more of and will do my best.
Great content. Insightful and coherent explanations with good pace and diligent procedural steps that you share with the audience in a genuinely helpful manner. God bless you for uploading these instructional tutorials.
This means a lot to me. Thank you again!
Very nice explained ,thanks for sharing knowledge,peace
Wow you've explained this so well 👏🙌 thank you so much. I wish I had you as my professor.
Thank you so much! Makes so much sense now.
Nice
Thank you so much it was very helpful
Wow this stuff is soooo easy. Memorised it after watching once, thank you so much! I’m not worried AT ALL about my exam coming up
how did your exam go?
This is a good explanation
Good and direct. Thanks
My question is what if you have more then 3 conductors?
Then you would need to use table 310.15(b)(3). Adjustment factors
Then you derate the value of the wire based on how many conductors are in the raceway and 4-6 conductors is an 80 percent deration factor
More on NEC video
What about if I found the same insulation in 75 column and 90 column which one should I use?
Thank you ma'am
@@allychildress905 Adding to what you said: A circuit is the sum of its weakest part; you need to also determine the terminal ratings(of the equipment) and the overcurrent protection device used. You must choose the column for whichever rating is lowest.
@Ally C 👍 I added that in only for the additional value. You're doing great. I wish I had more employees like you Ally.
@Ally C At the rate that I'm acquiring new customers right now, I'll likely have a branch there someday 😀 or maybe a heart attack 😂
Thank you! Great video
Thanks for the info really helpful.
So if your ampacity is 63.7Amps would you round down or up to the next size overcurrent protection?
Always round up until you exceed 800A. Then the wire must meet or exceed the breakers rating.
A calculated 64A load would require a 70A breaker on #6 copper.
You want the breaker to trip before the cable burns up. You would round down to 60 A breaker, otherwise the cable will overheat, that is the purpose of these calculations - finding out the d ration due to temperature.
@@KJVNHVN I was curious since yourself and beeps were giving two different answers so I had to do some looking. NEC 240.4(B) says the next higher standard overcurrent device rating (above the ampacity of the conductors being proctected) shall be permitted to be used
Thanks ❤
are u getting tables from the Code Book ? Because I dont remember seeing that table with that table number there ?
They have changed the table numbers, I use 310.16. Same Info its just worded a bit different and the temp rating of the table is now in the actual text not listed at top of the table. So 310.16 states that TABLE 310.16 is based on 30 degrees C. Read the notes under table 310.16 and it tells you where the temp correction and if you have more then 3 conductors in a conduit correction tables are.
Hello 👋 can you make a video about sizing a equipment grounding conductor.?
Huuuuooooyeahhhhhhh
Only problem I have is knowing which ambient correction to use? 30 or 40 degree Celsius.
im stuck on that as well, let me know if you figure it out.
an engineer online says that if the wire insulation is rated for 600v use 310.15(b)(2)(a) and if the insulation is rated for up to 2,000v use 310.15(b)(2)(b)
@@xaviermadera7216 well thanks for the reply and answer!
if it is over three conductors would you find the right ambient temperature
just how you did in the video except you would multiply your answer by whatever the number is for your conductors so if you had 4 conductors it would be your answer times .80?
If its 4 or more conductors refer to table 310.15 (B) (3) (a) for the de-rate %.
4-6 conductors is .80, yes.
My question would be why do we apply temperature correction factors at all? I understand the math but can you give an example of a real world scenario where you would need to do that, change the ambient air rating of 30 C to said temp?
On like a rooftop somewhere where hot .
Hot climates such as Arizona or Las Vegas.
Thank you very much, the question is: why do you still use Fahreneit ? :D
Because . . . 'murica.
Where is the math and physics behind the generation of 310.15?
what year nec is this