Young's Double Slit Experiment
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- čas přidán 6. 08. 2024
- This physics video tutorial provides a basic introduction into young's double slit experiment. It explains how to calculate the distance between the slits given the wavelength of light used and distance from the slit to the screens. It also explains how to calculate the distance between the first order bright fringe and the central bright fringe. The bright fringes are the locations where constructive interference occurs and the dark fringes are produced due to destructive interference. This tutorial contains many examples and practice problems.
Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
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Brewster's Angle:
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Planck's Constant and Blackbody Radiation:
• Planck's Constant and ...
Photon Momentum and Effective Mass:
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Wien's Law:
• Blackbody Radiation an...
Compton Effect & Wavelength:
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Physics 2 Final Exam Review:
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Hey, on question 2, I got the answer as 3.3*10^-11 meters, could there have been a conversion error on your part because I converted all the values into meters via calculator converter.
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Thank you sir for this veryy understanding video! But you only teach about the bright fringe and i want to know about dark fringe. Im having problem with determining the m of dark fringe.
for dark fringe, change lambda to lambda/2 in the equations
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why is theta equivalent to theta 1 at 4:00 minutes into the video? I wanted to know why those 2 angles are equivalent. tks
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If the distance between the two points is 6cm and the angle of reflection, is 30⁰ what is the wavelength?
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12:45
Multiply 8.5 x 3
Multiply with wavelength
Divide number with 0.5
Great
On the last example, why didn't we multiple m=4 on the left side of the equation?
can you please make a video about thin films.
for the final example, when calculating for d, why are you not dividing by m? I see you are leaving it on the numerator side of the equation when dividing by the remaining left side, but not including it on the denominator.... which would cancel m out entirely... maybe I am missing something.. someone explain pls
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Look at the CZcams video "Double Slit Experiment" by Todd Grigsby.
It uses an interferometer to show that light waves can bounce off another.
This applies to the double slit experiment thus the title.
Some other guy was saying that's the squared magnitude of a complex function. I've seen them rounded, if that's the case.
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How to consider angle is small?
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what about darker sides? do we just add 1/2lamda ?
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What would happen if the constructive interferencing from 1 set of double slits passed through another set of double slits? Would the universe break because of energy being created?
😂😂😂 it's very likely that's you'd not be able to align the double slits at the exact same spot where the waves are in phase, but if you do... You'll just get another interference pattern where the intensity/amplitude is lesser than the last interference pattern you saw.
The highest intensity in an interference pattern is achieved at the centre of the double slits (projected on the screen) but if you plan on using another 'Double' slit, the starting intensity of the light would be less than the original, and hence you'd only get a fainter interference pattern :)
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Is it normal to have an average of 17 lessons per subject for finals?
A little high. We have 14
If we are asked to calculate lamda or width fringe of first minima are we going to use m=0
Or m=1
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I believe you have to use one of these 2
Why did they divide the distance of the two slits by 10^3??
i don't get why the two angles (theta 1) are equivalent. could you help me to prove it please?
thank you
It has to do with the geometry of similar triangles
A wave is spread across. In a double slit experiment, if the wavefunction representing the electron, hits the slits, shouldn’t that be a measurement and shouldn’t that collapse the wavefunction? Now, you'll say it's not a physical wave, it's a probability wave. But then how does a probability wave split into two after the slits? Then, it should be like, the wave hits the slits, the electron says, dude I'm going through the slits, so don't collapse, but you can split into two and diffract. When does it decide that it's going through the slit?
we just did this in class
Could I know the reason triangle’s base line is λ ? Why that length could be λ 😭
Can we use white light in this expriment ? If yes how ? If not why ?
No, because white light is a mixture red, blur, green, ect., which are at different wavelengths. This experiment uses light at just one wavelength. If you use light with different wavelengths, then each wavelength is going to be diffracting at different angles and interfering with each other so you won't get the neat maximum-minimum pattern on the screen
Yes, you can use white light, it will just produce an even cooler looking interference pattern as the different colours will diffract at a different angle, leaving you with something similar to a horizontal looking rainbow
Monochromatic light is preferred because the resulting interference pattern is more sharper when compared to a white light (which is a mixture of other colours).
White would give you interference, but not as sharp and distinct as a monochromatic source.
04:00 why are the angles equal
u waffled so hard
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ecxactlyy
for 10:35 instead of using dy(1)=lambda m D you could've just used tan1.5 times 4.5 (make your life easier)
Hey does anyone know why he multiplied 0.05mm 0.05x10 to the power of -3? I don’t understand that part.
To convert from mm to m
@@umr4h138 Oh I see now thanks.
I have a question please, why did he divide 2.29*10^-5 by 10^-3
bro i came here to ask the same question i dont understand whyyyyy
@@bakedpiexzigzag1652To convert it to millimeters. You divide by 10^-3 if you want the mm conversion of any value
anwer of the third question : 1.76*10^-3 m/1.33 = 1.32*10^-3
right?! that is what i got as well, i am unsure why he isnt dividing by the m (canceling m)
6:19 You mean in degrees not in radians, sin(theta) is ~theta
No it is radians and not degrees
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