a surprisingly interesting sum -- 2 ways!

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  • čas přidán 21. 08. 2024
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Komentáře • 38

  • @xizar0rg
    @xizar0rg Před rokem +142

    Starting off saying he's going to use "one of my favorite functions", I was confused as to how the floor function was going to come into play.

    • @MichaelGrantPhD
      @MichaelGrantPhD Před rokem +8

      I saw your comment before I hit start, so I was waiting for him to say this... but then he said "one of my favorite *special* functions" and I knew he meant something different. Because why the floor function is indeed awesome, I knew it wasn't "special" in the mathematical sense of the term!

    • @wesleydeng71
      @wesleydeng71 Před rokem +2

      Generating function is another one of his. I can attest to that.

    • @Ahmed-Youcef1959
      @Ahmed-Youcef1959 Před rokem

      @@wesleydeng71
      Sure ,i was waiting for Generating function

  • @JohnSmith-zq9mo
    @JohnSmith-zq9mo Před rokem +18

    For the interchange of integration and summation, the monotone convergence theorem can also be used since everything is positive.

  • @PhilBoswell
    @PhilBoswell Před rokem +28

    It is super interesting to see how Michael adjusts his approach as he goes, but also super confusing when he suddenly rewinds without warning.
    Would it be possible, even if slightly janky, to insert a "rewind" effect to demonstrate that the backwards jumps are deliberate rather than an editing error?

    • @UltraMaXAtAXX
      @UltraMaXAtAXX Před rokem +6

      It would be so on brand with the humor of Stephanie - make it happen, please?

  • @jonathanbeeson8614
    @jonathanbeeson8614 Před rokem +15

    Interesting and instructive problem and solutions as usual, Professor Penn, but it seems there were some problems with the editing today...a couple of redundant bits left in possibly by mistake.

  • @goodplacetostop2973
    @goodplacetostop2973 Před rokem +12

    13:27

  • @user-yt8xc8zw6v
    @user-yt8xc8zw6v Před rokem +1

    Here is a another approach to the second way , notice that the integral of dilog(x) from 0 to 1 = the integral of dilog(1-x) form 0 to 1 and use the remarkable identitiy dilog(x)+dilog(1-x)+ log(x) log(1-x)=zeta(2) so it suffices to evaluate the integral of log(x)log(1-x) from 0 to 1 , this can be easily calculated by using a little trick.

  • @adandap
    @adandap Před rokem +1

    Christmas time at Michael's place. "Help yourself to a nut. There's a nutcracker there, or you can use one of my favourite tools - that steamroller outside."

  • @redroach401
    @redroach401 Před 3 měsíci

    This was my favourite explanation of new bounds thank you so much

  • @oddlyspecificmath
    @oddlyspecificmath Před rokem +3

    This was fun; I've been looking for perspective on sums and (for me at least) this has just the right level of progression to help me pause and analyze what's familiar to others. Thanks 😊

  • @manucitomx
    @manucitomx Před rokem +1

    That was very cool!
    Thank you, professor!

  • @paulkohl9267
    @paulkohl9267 Před rokem +1

    Thank you MP for doing so many great math vids!

  • @martinkausoh1386
    @martinkausoh1386 Před rokem +1

    Great to see my favorite math professor at large but I prefer the first solution 😅 Many thanks Michael for Your hard and inspiring work

  • @martinkausoh1386
    @martinkausoh1386 Před rokem +4

    Some problem with the video cutting? Thatś the second time that I noticed a start-over in between😊

  • @HerbertLandei
    @HerbertLandei Před rokem +1

    Great, now do the same for sum 1/n³

  • @Calcprof
    @Calcprof Před 10 měsíci

    Partial fractions is actually not a theorem about integration, but rather a theorem about the structure of rational functions. As such it comes up in many areas.

  • @CielMC
    @CielMC Před rokem

    The video was a little jumpy, but the ride was enjoyable.

  • @RUKA-ur6oj
    @RUKA-ur6oj Před rokem

    分かりやすいです

  • @holyshit922
    @holyshit922 Před rokem +1

    What about following sum
    sum((n choose 2m)(m choose k),m=k..floor(n/2))
    Result should depend on n and k
    Wolfram Alpha does not calculate this sum correctly

  • @puertavideo
    @puertavideo Před rokem +8

    5:58 - 6:04 ?? Is that ment to be there

    • @woody442
      @woody442 Před rokem +5

      Absolutely! It was a little spoiler in case you were about losing attention ;-)

    • @txikitofandango
      @txikitofandango Před rokem +1

      Harkens back to when he used to edit his own videos :)

    • @robertveith6383
      @robertveith6383 Před rokem

      * meant

  • @moulinaie
    @moulinaie Před rokem +1

    I'm happy I got the solution ! This is not so easy on this channel !! Thanks for your cool problems.

  • @y.k.495
    @y.k.495 Před rokem +5

    it's looks like ζ(2)+ζ(3) !

  • @petersievert6830
    @petersievert6830 Před rokem

    Some heave time travelling this time around ;-)

  • @Patapom3
    @Patapom3 Před rokem

    Amazing!

  • @CM63_France
    @CM63_France Před rokem

    Hi,
    And so, compared to the sum of the inverses of the squares, it only subtracts 1? not very glorious 😆
    Editing problems.

  • @user-gy7hc6pi7h
    @user-gy7hc6pi7h Před rokem +1

    I pushed the 2^8th like

  • @konstantintrifonov7319
    @konstantintrifonov7319 Před rokem +1

    I recently saw a similar video about calculating using the integral of the dilogarithm czcams.com/video/pmuFPRiNgjc/video.html

  • @zlodevil426
    @zlodevil426 Před rokem +1

    there was no need to bring this horrible calculus into a simple problem

  • @franksaved3893
    @franksaved3893 Před rokem +3

    Michael's favorite trick is fucking awesome

    • @robertveith6383
      @robertveith6383 Před rokem

      Stop your major cursing, especially in a mathematics forum. It is rude, ignorant, and needless.