Shortcut Explained: *Case 1* : no prime numbers present choose the largest number and check if it's divisible by all remaining numbers - if yes , then it's the LCM if no , then multiply it by 2 and check again if still not divisible , then multiply it by 3 and check again Repeat until it is divisible by all other numbers eg 12 6 24 8 *Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven ) Example 1 : 4 6 7 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside) Between 4 and 6 - 6 is greater which is not divisible by 4 6*2 = 12 is divisible by 4 So LCM = 12 * (7) = 84 Example 2 : 7 10 12 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside) Between 10 and 12 - 12 is greater but not divisible by 10 Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10 So LCM = 60 * (7) = 420 *Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven ) Then DO NOT keep it aside. Proceed normally like case 1 Example 1 : 7 8 14 7 is prime but 14 is divisible by seven ( or is a multiple of 7 ) Hence do not keep it aside.
sir in a short cut method you said take prime number separetly and multiple by the highest number but in eg. 3 and 4 there is also a prime number present there like 3 ...3 is also a prime number category ...in that case what should have we to do...please take it seriously and i hope yo will reply back and give appropraite answer which have we need
@@naazirayash9139 Bro ... in Eg 3 : 12, 3, 9 . Prime number is 3 but still 12 can be divided by 3(So dont consider 3 as prime number) So u can solve in the same manner u did for above 2 examples. in Eg 4: *3, 11, 12*. Prime No. are 3 & 11. But the remaining number (12) is divisible by 3 (so dont consider 3 as prime number here). But 12 is not divided by 11 (so consider 11 prime number & solve in the same manner like sir did)
may almighty bless you sir . i think in my whole life i never see like you any tutor who provides just like lectures free of cost .i wish i would be like you
These videos of various topics are really helpful for those who are preparing for various exams. And it is a small thing to thank you people(your team) for making this and your vision. I hope you people will reach the your abnormous goal.
If higher number is not divisible by prime.. then keep the prime a side then.. multiple the prime with final number which is divisible by all other numbers ❤
I am learning to see your videos it is very useful for me. I cleared IBPS RRB PO because your videos, it is very useful to me. Sir, please do the data sufficiency topic. Thank you, Sir.
Sir you are the best teacher for teaching maths for competitive exams. The most important thing is that you teach in a very patient manner. Therefore slow and dumb students like me can easily understand and grasp the concept.
I don't have enough words to express my gratitude..thankyou sir quants was always a really troublesome section for me..but your vedios helped me a lot.Today everyone is trying hard to promote their paid courses here you are giving this amazing sections thats too totaly free of cost & some of these vedios are way better than paid courses..I wish i could be at your doorsteps oneday to take your blessings after i get my first job...thankyou again sir.may god bless you with good health & happiness...
You're teaching skills are incredible sir. From you sir we have two benefits one is we learn aptitude step by step and another one is we learn English so easily...
I'm preparing for some State exams...and...i have already covered all the topics... it's as usual just most easiest way to understand thank you so much sir ....for you efforts... 🙏
Sir...I have watched your all videos uptill now , my basic concepts were not clear..now it is crystal clear m happy ... m speechless no words for your Hard work n efforts many students like me without coaching are dependent on you...hats off keep it on your are really doing great job 👍
Yeah .I also tried for finding the lvm by shortcut method .but it didn't work out. See 12,3,9 Pick 3 separately since it is prime 9,12 Highest no=12,(12/9=not divisible) 12×2=24,(24/9=not divisible) 12×3=36,(36/9=divisible) 36 is LCM for other 2 nos Check for 3×36 =108= LCM. But not correct . Rather find lcm for both 36(I.e LCM of other no's) and 3(prime no) LCM =36
Shortcut Explained: *Case 1* : no prime numbers present choose the largest number and check if it's divisible by all remaining numbers - if yes , then it's the LCM if no , then multiply it by 2 and check again if still not divisible , then multiply it by 3 and check again Repeat until it is divisible by all other numbers eg 12 6 24 8 *Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven ) Example 1 : 4 6 7 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside) Between 4 and 6 - 6 is greater which is not divisible by 4 6*2 = 12 is divisible by 4 So LCM = 12 * (7) = 84 Example 2 : 7 10 12 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside) Between 10 and 12 - 12 is greater but not divisible by 10 Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10 So LCM = 60 * (7) = 420 *Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven ) Then DO NOT keep it aside. Proceed normally like case 1 Example 1 : 7 8 14 7 is prime but 14 is divisible by seven ( or is a multiple of 7 ) Hence do not keep it aside.
00:06 Introduction to LCM and its importance in competitive exams. 02:07 Learn multiple methods to find LCM. 04:05 Finding the least common multiple (LCM) of multiple numbers. 06:15 Traditional and factorization methods for finding LCM 08:11 Explaining how to find the LCM using factorization method 10:02 Finding LCM using factorization method 11:56 Start with the smaller number when finding LCM 13:47 Long division method is essential for finding LCM 15:47 Identify the LCM by checking for divisibility 17:42 Finding LCM by checking divisibility of numbers 19:32 Finding LCM using division method 21:13 To find the lcm, practice is key.
@AC18UCS031 Gopal G No, we have to check whether the prime number is a factor of the biggest number or any of the multiples of the biggest number. If no then we have to keep it aside and multiply...
In short cut method 3rd example 3 is a prime number, as per ur explanation the third question answer is 108 sir. Please give me the reply as soon as possible.
but its wrong since 36 is the actual LCM but the explaination is having very smooth ghapla the real explanation of short cut method is not there. The best shortcut is to learn the Long-division method which solves 100% problems and listen to your instincts that is developed by practice.
Shortcut Explained: *Case 1* : no prime numbers present choose the largest number and check if it's divisible by all remaining numbers - if yes , then it's the LCM if no , then multiply it by 2 and check again if still not divisible , then multiply it by 3 and check again Repeat until it is divisible by all other numbers eg 12 6 24 8 *Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven ) Example 1 : 4 6 7 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside) Between 4 and 6 - 6 is greater which is not divisible by 4 6*2 = 12 is divisible by 4 So LCM = 12 * (7) = 84 Example 2 : 7 10 12 7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside) Between 10 and 12 - 12 is greater but not divisible by 10 Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10 So LCM = 60 * (7) = 420 *Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven ) Then DO NOT keep it aside. Proceed normally like case 1 Example 1 : 7 8 14 7 is prime but 14 is divisible by seven ( or is a multiple of 7 ) Hence do not keep it aside.
Sir thank you so much for your wonderful teaching to us ....my request is can you say what are the topics to prepare for RRB clerk I was fresher preparing for competitive exam
Sir pls continue dis basics for all the topics bcz somany ppl dntknw the basics its very useful to us somny ppl not affort to go to coaching classes in dis covid pandemic ty
Shortcut Explained:
*Case 1* : no prime numbers present
choose the largest number and check if it's divisible by all remaining numbers -
if yes , then it's the LCM
if no , then multiply it by 2 and check again
if still not divisible , then multiply it by 3 and check again
Repeat until it is divisible by all other numbers
eg 12 6 24 8
*Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven )
Example 1 :
4 6 7
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside)
Between 4 and 6 - 6 is greater which is not divisible by 4
6*2 = 12 is divisible by 4
So LCM = 12 * (7) = 84
Example 2 :
7 10 12
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside)
Between 10 and 12 - 12 is greater but not divisible by 10
Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10
So LCM = 60 * (7) = 420
*Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven )
Then DO NOT keep it aside.
Proceed normally like case 1
Example 1 :
7 8 14
7 is prime but 14 is divisible by seven ( or is a multiple of 7 )
Hence do not keep it aside.
Thanks for this.
thank you so much...
sir in a short cut method you said take prime number separetly and multiple by the highest number but in eg. 3 and 4 there is also a prime number present there like 3 ...3 is also a prime number category ...in that case what should have we to do...please take it seriously and i hope yo will reply back and give appropraite answer which have we
need
@@naazirayash9139 Bro ... in Eg 3 : 12, 3, 9 . Prime number is 3 but still 12 can be divided by 3(So dont consider 3 as prime number) So u can solve in the same manner u did for above 2 examples.
in Eg 4: *3, 11, 12*. Prime No. are 3 & 11. But the remaining number (12) is divisible by 3 (so dont consider 3 as prime number here). But 12 is not divided by 11 (so consider 11 prime number & solve in the same manner like sir did)
Thank you
may almighty bless you sir . i think in my whole life i never see like you any tutor who provides just like lectures free of cost .i wish i would be like you
These videos of various topics are really helpful for those who are preparing for various exams. And it is a small thing to thank you people(your team) for making this and your vision. I hope you people will reach the your abnormous goal.
But 3 IS a prime number.
3*12=36
@@PRASHANTKUMAR-su9bx Could u explain clearly?
3 is a prime number, but 12 can divisible by 3
If higher number is not divisible by prime.. then keep the prime a side then.. multiple the prime with final number which is divisible by all other numbers ❤
Hope u guys are understand ❤❤
Sir, at 18:56, you mentioned that there are no prime numbers. However, 3 is prime.
same ques
I am learning to see your videos it is very useful for me. I cleared IBPS RRB PO because your videos, it is very useful to me. Sir, please do the data sufficiency topic. Thank you, Sir.
Very great congrats bro🤩
Congratulations
Sir, I live in Saudi arabe. I am very glad to watch your video .I pray God for you..
Super bro
Hi
Sir you are the best teacher for teaching maths for competitive exams. The most important thing is that you teach in a very patient manner. Therefore slow and dumb students like me can easily understand and grasp the concept.
I don't have enough words to express my gratitude..thankyou sir quants was always a really troublesome section for me..but your vedios helped me a lot.Today everyone is trying hard to promote their paid courses here you are giving this amazing sections thats too totaly free of cost & some of these vedios are way better than paid courses..I wish i could be at your doorsteps oneday to take your blessings after i get my first job...thankyou again sir.may god bless you with good health & happiness...
You're teaching skills are incredible sir. From you sir we have two benefits one is we learn aptitude step by step and another one is we learn English so easily...
I am obliged to your gratitude and kindness. Thank you sir.
@@FeelFreetoLearn sir please dont think I am arrogant or anything but it is said like 2 raised to the power of 3 or 4 etc
@@FeelFreetoLearn❤❤❤
@@FeelFreetoLearn apply prime no.method in question 3...same question is asked by many students why u are not responding to it
....
Naa louda am kadhu first 3 is prime number kadhu anti 3,4 answer malli chepu@@FeelFreetoLearn
I'm preparing for some State exams...and...i have already covered all the topics... it's as usual just most easiest way to understand thank you so much sir ....for you efforts... 🙏
What a great teacher you are. Blessings to you
Sir...I have watched your all videos uptill now , my basic concepts were not clear..now it is crystal clear m happy ... m speechless no words for your Hard work n efforts many students like me without coaching are dependent on you...hats off keep it on your are really doing great job 👍
Your kind words and remarks are my inspiration, thank you madam.
It's great to find and happy to have the topics..tq
I never had best teaching in my life TQ sir which is your dedication and spreading by quality of knowledge...
Thank you for showing different methods of finding LCM, kindly please make another video for how to find HCF sir by using various methods...
Best learning technique,A lot's of Love ❤️❤️❤️❤️ sir
I m learnt more and more after watching dis video... Vry useful to me... Thank u sir.....
Sir this video is ausump I was confused with this L.C.M Topic you only cleared thank you very much
Sir you are a god to me,plz providing more videos for non maths students
I don't have any words to express Tq sir and May God bless you sir👍🙏🙏🙏
Waoooo great explanation sir..... what's fantastic
Thank you so much sir...ur teaching is just mind-blowing🔥🙏
Thank you madam, those are some really kind words you could spare.
Thanks a lot of you sir....your classes are very helpful for me.... this is my request to you sir please continue the classes on reasoning also
Superb explanation....thank you so much sir
You teach really too good and I really thank you sir for this amazing video 🙏 my doubts related to LCM got clear after watching this video
I think this is the best class for LCM in CZcams
I’m glad you think that way, thank you sir.
Ur videos are useful to students and also teachers sir ..iam a teacher ...tnq sir
Simply super...chala clear ga explain chesaru sir 👌👌👍👍
Thank you for the kindest remarks sir.
you're awesome sir.. thanq so much..
Great teaching sir.. thanks a lot sir
Thnku sir
To b honest ,,i had a mathematics phobia,but watching ua videos makes me the phillic towards it
Wonderful method sir ... I appreciate your method and you ❤
Sir pls make more videos on other topics like pair test,order and ranking etc.I like your teaching it was very very useful to me sir.
GOOD VERY CLEAR ABOUT L C M THANKS AND KEEP IT UP
Its soo easy to learn it from here sir🙏 thank you🙏
Ur teaching in mind blowing 🎉🎉
Your teaching style is very nice, Sir!! Waiting for more videos from you.
Thank you madam, those are some really kind words you could spare.
I am from Nepal and I am preparing for lok sewa and your videos are really very helpful sir. Thank u soo much🙏🙏🙏
You’re welcome madam.
Thank you so much sir! You are making our lives more easier🙌
You’re most welcome madam and Thank you for the kind words.
Thx sir u make my work easy
Thank you sir.sir your teaching is so amazing . I loved you teaching.
Fantastic & superb taught
Sir in 3rd and 4th question '3' is also a prime number
Yeah .I also tried for finding the lvm by shortcut method .but it didn't work out.
See
12,3,9
Pick 3 separately since it is prime
9,12
Highest no=12,(12/9=not divisible)
12×2=24,(24/9=not divisible)
12×3=36,(36/9=divisible)
36 is LCM for other 2 nos
Check for 3×36 =108= LCM.
But not correct .
Rather find lcm for both 36(I.e LCM of other no's) and 3(prime no)
LCM =36
Shortcut Explained:
*Case 1* : no prime numbers present
choose the largest number and check if it's divisible by all remaining numbers -
if yes , then it's the LCM
if no , then multiply it by 2 and check again
if still not divisible , then multiply it by 3 and check again
Repeat until it is divisible by all other numbers
eg 12 6 24 8
*Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven )
Example 1 :
4 6 7
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside)
Between 4 and 6 - 6 is greater which is not divisible by 4
6*2 = 12 is divisible by 4
So LCM = 12 * (7) = 84
Example 2 :
7 10 12
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside)
Between 10 and 12 - 12 is greater but not divisible by 10
Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10
So LCM = 60 * (7) = 420
*Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven )
Then DO NOT keep it aside.
Proceed normally like case 1
Example 1 :
7 8 14
7 is prime but 14 is divisible by seven ( or is a multiple of 7 )
Hence do not keep it aside.
Yes..u r correct.. nobody observe this.
Max 90% only apply shortcut method
12,3,9 is an example of remaining 10%
Apply long division method
U made it look easy thanks a lot
... ❤
It's a really a nice class sir ✌️❤️
Sir you are really doing a excellent job, crystal clear of all topics lots of ❤️ from Karnataka.
I am obliged to your gratitude and kindness. Thank you sir.
Sir i give u 100 out of 100....your videos to the point... I have no words to explain.....
Your kind feedback is my inspiration sir.
Always favourite ❤️, sir plz make video on ( problem of age ) 🙏🙏
In shortcut method question number 3 contains 3 and it is prime number
00:06 Introduction to LCM and its importance in competitive exams.
02:07 Learn multiple methods to find LCM.
04:05 Finding the least common multiple (LCM) of multiple numbers.
06:15 Traditional and factorization methods for finding LCM
08:11 Explaining how to find the LCM using factorization method
10:02 Finding LCM using factorization method
11:56 Start with the smaller number when finding LCM
13:47 Long division method is essential for finding LCM
15:47 Identify the LCM by checking for divisibility
17:42 Finding LCM by checking divisibility of numbers
19:32 Finding LCM using division method
21:13 To find the lcm, practice is key.
U'r amazing lecture sir keep going like this....... 🤩🤩👏👏
Thank you madam, I’m glad you liked my method.
Sir the lecture was comprehensive really but I got so confused in 3 as 3 is the prime no
Yes same confusion 3 is prime no
@AC18UCS031 Gopal G No, we have to check whether the prime number is a factor of the biggest number or any of the multiples of the biggest number. If no then we have to keep it aside and multiply...
Sir I am in 7 class
same doubt i have,plz any one
Yes exactly
12, 3, 9 = 108 LCM As 3 is a prime number
Sir Your are the best Solution for beginners and learners 🙏🙏..
I’m grateful for your kind remarks, Thank you sir.
Wow ...excellent explanation ..sir
Ur teaching is amazing
God bless you sir 👍🙏
Wow sir you are teaching very well 👏 thank you sir thank you very much sir 🙏 😊
Best teacher ... explain basic method from zero level ... thank you sir ...you teach very superb 👌👌
Thank you very much for your valuable feedback sir.
@@FeelFreetoLearn sir i like the way you solve every question from basic method ... i m your follower from 3 years.
czcams.com/video/BRudV1A8Q0s/video.html
Most helpful person ❣️
Super sir very best sir teaching very very super sir.....
Thank you sir 👍👍
Xlent xplaination sir😍
Thnq very much 🙏
You’re welcome sir.
Thank you very much sir for teaching us.
Sir you are not ordinarily human being 🤩
You are just awesome
Thank u sir.....
I’m grateful for your kind words, Thank you sir.
Thank you Soo much sir ..I am a per final yr Stu it will helps me more 🙏🙏🙏
You’re most welcome madam, I’m glad you found it useful.
Sir kindly make more videos on LCM and HCF it's an humble request..
sir in shot cut method 3 example : 3 is a prime number
I also have the same doubt...
Sir, will u explain in the 3rd example 3 is also a prime number 🤔
Sir, could you explain ?
Sir can you explain 3rd example it has 3 prime number
question 3 in short cut method 3 is prime number right? Confused can u clarify sir
Waiting for next video
Excellent session sir..Thank u so much sir..Keep going like this
You’re most welcome and thank you for the kind remarks madam.
Tq so much sir ur excellent teacher to me
Hlo sir
Iam recently subscribed ur channel
I listened one topic .it is with very clear explanation it's helpful to newly started students 👍
Your kind words and remarks are my inspiration, thank you madam.
After long tym
Short cut method is soo helpfull for us sir, tq sir for your valuable teaching
Waiting for your more videos on CZcams
Keep going sir...
Your explanation is very good...
This topic is clear 👍👐
I am obliged to your kindness. Thank you madam.
Sir please do more video sir I'm preparing upsc exam sir .. I'm very weak in csat sir I'll following ur video only sir thank you sir
👌Thank you so much sir very helpful for your method🙏
You’re welcome sir, I’m glad I could help.
Thank you very much sir..
What about 3 .... Plz clarify this doubt... In question number 4 ) 3 11 also a prime number but you focused on 11 why not on 3
Kaash sir aap pehle mile hote ....toh main Bsc main fail Naa hota ....maths favourite bn rha h mera apko videos dekhke .
Wonder teacher🙏
Thank you so much 🙏
thankyou sir plz upload all videos on LCM AND HCF
Thankyou sir this useful for my exam . Thankyou sir
I love your videos very much
you are teaching great
a billion thanks to you sir
Your kind words and remarks are my inspiration, thank you sir.
Justtt wow 🔥🎉
In short cut method 3rd example 3 is a prime number, as per ur explanation the third question answer is 108 sir. Please give me the reply as soon as possible.
Yes , absolutely right
Yes ur corect
but its wrong since 36 is the actual LCM but the explaination is having very smooth ghapla
the real explanation of short cut method is not there. The best shortcut is to learn the Long-division method which solves 100% problems and listen to your instincts that is developed by practice.
Shortcut Explained:
*Case 1* : no prime numbers present
choose the largest number and check if it's divisible by all remaining numbers -
if yes , then it's the LCM
if no , then multiply it by 2 and check again
if still not divisible , then multiply it by 3 and check again
Repeat until it is divisible by all other numbers
eg 12 6 24 8
*Case 2* : if prime present + other number are not divisible by it ( or in other words, other number is not a multiple of seven )
Example 1 :
4 6 7
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of seven ) - hence keep it (aside)
Between 4 and 6 - 6 is greater which is not divisible by 4
6*2 = 12 is divisible by 4
So LCM = 12 * (7) = 84
Example 2 :
7 10 12
7 is a prime and other numbers are not divisible by seven ( or they are not a multiple of 7 ) - hence keep it (aside)
Between 10 and 12 - 12 is greater but not divisible by 10
Then if we keep multiplying 12 by x1 x2 x3 x4 We will get 12x5=60 which is divisible by 10
So LCM = 60 * (7) = 420
*Case 3* : if prime present + other number are divisible by it ( or in other words, other number is a multiple of seven )
Then DO NOT keep it aside.
Proceed normally like case 1
Example 1 :
7 8 14
7 is prime but 14 is divisible by seven ( or is a multiple of 7 )
Hence do not keep it aside.
U r correct ...but sir not giving explanation for the questions...
Sir please complete all series thank you
18:55 3 is also a prime
Sir waiting for next part
3 is prime number, though great explanation sir, I was waiting for this video
Sir thank you so much for your wonderful teaching to us ....my request is can you say what are the topics to prepare for RRB clerk I was fresher preparing for competitive exam
How to calculate if there are two or more prime numbers in the given question ??
I finally found the Indian guy on CZcams
Thanku sir plz do more vedios in this topic for rrb group d as soon as possible.
very useful sir plz take tuturial session on each topic
can't thank you enough sir
Thankyou sooo much brother 🙂
Tquu so much sir ..nice explaination and very easy to understand
I’m glad you found my channel amiable, you’re most welcome madam.
Sir pls continue dis basics for all the topics bcz somany ppl dntknw the basics its very useful to us somny ppl not affort to go to coaching classes in dis covid pandemic ty
I surely will madam.
I owe you a lot 💞💞🙏
Clear video, If it's is a little bit faster then it would be great and lag-free