7-22 Determine the shear stress at point B on the web | Mechanics of Materials RC Hibbeler
Vložit
- čas přidán 5. 08. 2024
- 7-22. Determine the shear stress at point B on the web of the cantilevered strut at section a - a .
Dear Viewer You can find more videos in the link given below to learn more and more
Video Lecture of Mechanics of Materials by Beer & Jhonston
• Mechanics of Materials...
155 Problem solutions of all chapter of Mechanics of Materials by Beer & Jhonston
• Mechanics of Materials...
Chapter 8 of Mechanics of Matereials rc hibbeler (09th Edition)
• Combined Loading (Chap...
Chapter 7 of Mechanics of Matereials rc hibbeler (09th Edition)
• Transverse Shear (CHAP...
Chapter 6 of Mechanics of Matereials rc hibbeler (09th Edition)
• CHAPTER 6 (BENDING) BY...
Chapter 5 of Mechanics of Matereials rc hibbeler (09th Edition)
• Chapter 5 (Torsion ) B...
Chapter 4 of Mechanics of Matereials rc hibbeler (09th Edition) • Chapter 4 (Axial Loadi...
Chapter 3 of Mechanics of Matereials rc hibbeler (09th Edition) • CHAPTER 3 MECHANICAL P...
Chapter 2 of Mechanics of Matereials rc hibbeler (09th Edition)
• CHAPTER 2 STRAIN, MECH...
Chapter 1 of Mechanics of Matereials rc hibbeler (09th Edition)
• CHAPTER 1 STRESS- INTE...
#mechanicsofsolids #mechanicsofsolids #mechanicsofmaterials #problemsolution #strengthofmaterial #mechanicsofstructure #strengthofmaterialstutorials #solidmechanics #strengthofmaterialstutorials
you have all kinds of problems students should learn. Thanks a lot.
yes my main aim is that student should learn effectively
thank you
You are Welcome
you are the man
Kindly share my videos with your friends and help me in growing my channel. Thank you 😊
for the shear stress at B why didn't we find it at thickness 0.02 AND 0.05 since there are different thicknesses just before and just after point B
below centroidal axial the the thickness is 0.02 which we have to taken.
Why didn't you do 7-23 or is this both question 7-22 and 23 in 1 ?
7-23 is exactly same as 7-22 if you share question I shall explain here what to do. I think in 7-23 you have to find the maximum shear stress....
For maximum shear stress you have to do all the steps as I did in question 7-22 and then from neutral axis to largest distance which is above neutral axis you have to find Qmax and then put it in shear stress formula. So instead of Qb you have to find Qmax and rest all the steps are same. If you feel any difficulty do let me know. Thank you