If you picked "4" on your first move, would the machine still work? It seems as if this machine could not be able to process its own moves unless they are on field 1, 3, 4, or 5.
Yes, if you choose 4 on your first move the computer would play number 2. Actually from that position, the computer would will 100% of the games as all possible moves lead to that outcome.
Playing mid-left in that situation is the most optimal strategy for the computer, even better than center. After that, all possible outcomes lead to a win from the computer (given that it makes optimal moves), one of them being the example of the video. With that play the computer has an outcome probability of 100% win / 0% draw / 0% lose.
When player places a mark on 5 is the only situation when the computer does not win, but also it does not lose: it ends in a draw. After player places a mark on 5, computer places a mark on 2 then player must place a mark on 3, computer places a mark on 7 then player must place a mark on 4, computer places a mark on 6 and finally the player places a mark on 8 or 9 and computer on the left one (8 or 9) and it ends in a draw.
Thanks to this video, I’m now obsessed with mechanical computers
I wanted to build such a machine in redstone, but when i realised how simple it is, i also got the idea to build a mechanical version.
Where can I find a description of the machine's operation?
I am trying to find some time to publish this,
I keep all the diagrams and drawings from the design
This is amazing!
Thanks!!
If you picked "4" on your first move, would the machine still work?
It seems as if this machine could not be able to process its own moves unless they are on field 1, 3, 4, or 5.
Yes, if you choose 4 on your first move the computer would play number 2.
Actually from that position, the computer would will 100% of the games as all possible moves lead to that outcome.
Why didn't the computer play center in the second bank of play?
Playing mid-left in that situation is the most optimal strategy for the computer, even better than center. After that, all possible outcomes lead to a win from the computer (given that it makes optimal moves), one of them being the example of the video.
With that play the computer has an outcome probability of 100% win / 0% draw / 0% lose.
@@Sukercc1 same goes for second move in center(100% win). Human player was doomed the moment he/she placed that silver ball to the side.
if the player places a mark on 5 what is the computer supposed to do, considering the algorithm it would lose in this scenario
When player places a mark on 5 is the only situation when the computer does not win, but also it does not lose: it ends in a draw.
After player places a mark on 5, computer places a mark on 2
then player must place a mark on 3, computer places a mark on 7
then player must place a mark on 4, computer places a mark on 6
and finally the player places a mark on 8 or 9 and computer on the left one (8 or 9) and it ends in a draw.
In that situation if the player does not follow those steps the computer would win
There is no way for the human to place field 1 or start the game, or is there?
Hello! No, the gameplay is designed so the computer always starts (and it always starts with number 1)